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By what factor does the rate change in each of the following cases (assuming constant temperature)?

(a) A reaction is first order in reactant A, and [A] is doubled.

(b) A reaction is second order in reactant B, and [B] is halved.

(c) A reaction is second order in reactant C, and [C] is tripled.

Short Answer

Expert verified
  1. When the reaction is doubled, the rates increase by a factor of 2.
  2. When the reaction is halved, the rate reduces by a factor of 4.
  3. When the reaction is tripled, the rate rises by a factor of 9.

Step by step solution

01

(a) When the reaction is doubled

For reactant A, write the rate law for the reaction in a first-order:

rate=kA1

When the concentration of the reactant doubles, write a new rate rule for the reaction:

rate=k2×A1=2×kA1

As a result, the rates increase by a factor of 2.

02

(b) When the reaction is halved

For reactant B, write the rate law for the reaction in a second order:

rate=kB2

When the concentration of the reactant is half, write the following revised rate law for the reaction:

rate=k12×B2=14×kB2

As a result, the rate reduces by a factor of 4.

03

 Step 3: (c) When the reaction is triple

For reactant C, write the rate rule for the reaction in a second order:

rate=kC2

Write a new rate rule for the reaction when the reactant concentration is tripled:

rate=k3×C2=9×kC2

As a result, the rate rises by a factor of 9.

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Question: Reaction rate is expressed in terms of changes in concentration of reactants and products. Write a balanced equation for

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2NOBr(g)→2NO(g)+Br2(g)

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(e) At what time does the instantaneous rate equal the average rate over the entire experiment?

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