Q19.71P The solubility of zinc oxalate i... [FREE SOLUTION]

Chapter 19: Q19.71P (page 875)

The solubility of zinc oxalate is $7.9 脳 10^{- 3} M 补迟18掳颁.$ Calculate its $K_{sp}$ .

Short Answer

Expert verified

The $K_{sp}$ of zinc oxalate is $6.2 脳 10^{- 5} .$

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Concept Introduction

The $Q_{s p}$ -ion-product expression is obtained by multiplying the concentrations of ions generated by the dissolution of a chemical. When a solution is saturated, the $Q_{sp}$ value is referred to as the $K_{s p}$ value (solubility-product constant).

${MX}_{2} {> >M}^{2 +} {+ 2X}^{-}$

We do not include the solid and liquid states in the $K_{sp}$ equations

$K_{s p} = [M^{2 +}] {[X^{-}]}^{2}$ .

$(S)$ is equal to the concentration of one mol of the ion formed by dissolution of some compound.

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First, we can write the dissolution equation for ${ZnC}_{2} O_{4}$ :

$Z n C_{2} O_{4} (s) 鈬� Z n^{2 +} (a q) + C_{2} O_{4}^{2 -} (a q) S$

role="math" localid="1663309639326" $(Z n C_{2} O_{4}) = 7.9 脳 10^{- 3} M K_{s p} = [Z n^{2 +}] [C_{2} O_{4}^{2 -}] [Z n^{2 +}] = S [Z n^{2 +}] = 7.9 脳 10^{- 3} M$

$[C_{2} O_{4}^{2 -}] = S [C_{2} O_{4}^{2 -}] = 7.9 脳 10^{- 3} M K_{s p} = S 脳 S K_{s p} = 6.2 脳 10^{- 5} .$

Therefore, the $K_{s p}$ of zinc oxalate is $6.2 脳 10^{- 5} .$

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The solubility of zinc oxalate is $7.9 脳 10^{- 3} M 补迟18掳颁.$ Calculate its $K_{sp}$ .

Short Answer

Step by step solution

Concept Introduction

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91影视

The solubility of zinc oxalate is7.9脳10-3M补迟18掳颁.Calculate itsKsp.

Short Answer

Step by step solution

Concept Introduction

information Provided

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Chemistry Branches

Chemical Reactions

Kinetics

The Earths Atmosphere

Making Measurements

Study anywhere. Anytime. Across all devices.

The solubility of zinc oxalate is $7.9 脳 10^{- 3} M 补迟18掳颁.$ Calculate its $K_{sp}$ .