/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q60P What is implied by the word 鈥渃... [FREE SOLUTION] | 91影视

91影视

What is implied by the word 鈥渃onstant鈥 in the term equilibrium constant? Give two reaction parameters that can be changed without changing the value of an equilibrium constant.

Short Answer

Expert verified

The term 鈥榗onstant鈥 implies that the equilibrium constant is constant for a reaction independent of the initial reactant concentration. The pressure and initial concentration of the reactants can be changed without changing the value of the equilibrium constant.

Step by step solution

01

Reaction equilibrium

When a reversible reaction is carried out for a period of time, it can be seen that there will be no change in the concentration of the reactants or products. This state is called a dynamic equilibrium in which the rate of forward and backward reactions becomes equal such that the overall concentration of species remains constant.

A reaction equilibrium is determined by pressure, temperature, concentration, and volume. The value of these parameters is determined by the nature of the reaction and is set so that the equilibrium favors the product formation.

02

Equilibrium constant

The reaction quotient is the ratio of the concentration of products to that of the reactants at any point of the reaction. It is used to determine the direction favored by the system.

There is no further change in the concentration of the reactant or products once a reaction reaches equilibrium. Therefore, the reaction quotient becomes constant, and this value of the reaction quotient is called the equilibrium constant. A higher value of equilibrium constant implies a higher concentration of products at equilibrium and thereby higher yield.

03

“Constant” in the equilibrium constant

The equilibrium constant for a reaction is constant for a particular temperature. If the temperature does not change, the ratio of the concentration of products to reactants at which equilibrium is attained for a reaction is constant.

The value of the equilibrium constant is independent of the initial concentration of the reactant. Therefore, the term 鈥榗onstant鈥 in the equilibrium constant suggests that the value is constant for a reaction for a particular temperature independent of initial reactant concentration.

The two variables that can be changed that do not cause a change in equilibrium constant are pressure and concentration. The pressure of a reaction can also be changed by changing its volume, which does not alter the equilibrium constant.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The oxidation of SO2is the key step in H2SO4production:role="math" localid="1654927501262" SO2(g)+12O2(g)SO3(g)螖贬rxn0=-99.2kj (a) What qualitative combination of T and P maximizes SO3yield? (b) How does addition of affect Q? K? (c) Why is catalysis used for this reaction?

Consider the formation of ammonia in two experiments.

  1. To a 1.00-L container at727oC1.30mol of N2and 1.65molofH2are added. At equilibrium, 0.100molofNH3 is present. Calculate the equilibrium concentrations of N2andH2, and find Kcfor the reaction: 2NH3(g)N2(g)+3H2(g)
  2. In a different 1.00-L container at the same temperature, equilibrium is established with 8.3410-2molofNH3,1.50molofN2,and1.25molofH2 present. CalculateKc for the reaction:NH3(g)N2(g)+32H2(g)
  3. (c) What is the relationship between the Kc values in parts (a) and (b) ? Why aren't these values the same?

For a problem involving the catalysed reaction of methane and steam, the following reaction table was prepared:



Explain the entries in the 鈥淐hange鈥 and 鈥淓quilibrium鈥 rows.

For a problem involving the catalysed reaction of methane and

steam, the following reaction table was prepared:


Explain the entries in the 鈥淐hange鈥 and 鈥淓quilibrium鈥 rows.

Question:For the following equilibrium system, which of the changes will form more CaCO3?

CO2(g)+Ca(OH)2(s)CaCO3(s)+H2O(l)Ho=-113kJ

(a) Decrease temperature at constant pressure (no phase change)

(b) Increase volume at constant temperature

(c) Increase partial pressure of CO2

(d) Remove one-half of the initial CaCO3

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.