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Chapter 21: Q21.88P (page 976)

In the electrolysis of molten BaI2,

(a) What product forms at the negative electrode?

(b) What product forms at the positive electrode?

Short Answer

Expert verified

(a)I2 gas

(b) barium metal

Step by step solution

01

To find the product forms at the negative electrode

BaI2鈫�Ba2++I-

(a)In electrolysis of molten salts, the anion turns into a free element. Anions form free elements in the anode. In molten BaI2, the anion is I-.

2I鈫�2e-+I2(g)

Hence This I turns into role="math" localid="1659623165940" I2(g)

02

To find the product forms at the positive electrode

(b) In electrolysis of molten salts, the cation turns into a free element. Cations form free elements in the cathode. In molten BaI2,Ba2+is the cation.

Ba2++2e-鈫�Ba(s)

Hence The Ba2+ions turn into barium metal.

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