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Which of the following are polyprotic acids? Write successive ionization equations for the polyprotic acids in water. \begin{equation} \begin{array}{ll}{\text { a. } \mathrm{H}_{3} \mathrm{BO}_{3}} & {\text { c. HNO }_{3}} \\ {\text { b. } \mathrm{CH}_{3} \mathrm{COOH}} & {\text { d. } \mathrm{H}_{2} \mathrm{SeO}_{3}}\end{array} \end{equation}

Short Answer

Expert verified
Polyprotic acids: a. H鈧傿O鈧 and d. H鈧係eO鈧.

Step by step solution

01

Identify Polyprotic Acids

Polyprotic acids can donate more than one proton (H鈦 ion) per molecule in successive steps. From the given options, we need to identify if each acid is polyprotic. - (a) H鈧傿O鈧 has three hydrogen ions, hence it's potentially polyprotic. - (b) CH鈧僀OOH is a monoprotic acid since it can only donate one hydrogen ion. - (c) HNO鈧 is also monoprotic as it only donates one hydrogen ion. - (d) H鈧係eO鈧 has two hydrogen ions, making it a diprotic acid.
02

Write Ionization Equations for H鈧傿O鈧

H鈧傿O鈧 is a triprotic acid; it can release three protons successively in water. However, due to its weak nature, we commonly focus on the interaction with one set of hydroxide ions. For a strict chemical approach, it typically does not donate protons in the classical sense but reacts as follows: 1. H鈧傿O鈧 + 2H鈧侽 鈬 B(OH)鈧勨伝 + H鈧僌鈦 (not ionization in the typical sense).
03

Write Ionization Equations for H鈧係eO鈧

H鈧係eO鈧 is a diprotic acid and typically dissociates in two steps: 1. H鈧係eO鈧 鈬 H鈦 + HSeO鈧冣伝 2. HSeO鈧冣伝 鈬 H鈦 + SeO鈧兟测伝 These equations represent the successive ionization of H鈧係eO鈧 in water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionization Equations
Ionization equations are essential in understanding how acids dissociate in solutions. Especially in the case of polyprotic acids, writing these equations helps us visualize and understand each step where a hydrogen ion is lost. Polyprotic acids can donate more than one proton per molecule, leading to several ionization steps. For instance, let's consider the dissociation of - H鈧係eO鈧 (diprotic acid): - First step: \(\text{H}_2\text{SeO}_3 \rightleftharpoons \text{H}^+ + \text{HSeO}_3^-\) - Second step: \(\text{HSeO}_3^- \rightleftharpoons \text{H}^+ + \text{SeO}_3^{2-}\)These equations show how H鈧係eO鈧 gradually ionizes by donating protons. Writing and balancing these equations are crucial for predicting the behavior of acids in different chemical environments.
Acid-Base Chemistry
In the realm of acid-base chemistry, understanding the nature and behavior of acids is fundamental. Acids are substances that can donate protons to other substances, which in return, become more acidic. This process is known as ionization. - Polyprotic acids contain more than one ionizable hydrogen ion: - They release each proton in a separate ionization step. - This is different from strongly acidic behavior, where the substance may donate a single proton quickly. An important aspect of acid-base chemistry is understanding the reactivity of different acids. For example, polyprotic acids like H鈧係eO鈧 release hydrogen ions in consecutive steps, affecting how these acids interact with bases and other compounds in reactions. In contrast, monoprotic acids such as CH鈧僀OOH or HNO鈧 donate only one proton, showcasing the diversity in acid reactivity.
Successive Ionization Steps
Successive ionization steps refer to the sequential release of protons from a polyprotic acid. Each step involves the loss of one proton, which often results in a distinct ionization stage with its own equilibrium constant. Consider the diprotic acid - H鈧係eO鈧: - First ionization: The first proton dissociates: \(\text{H}_2\text{SeO}_3 \rightleftharpoons \text{H}^+ + \text{HSeO}_3^-\) - Second ionization: The remaining hydrogen ion dissociates: \(\text{HSeO}_3^- \rightleftharpoons \text{H}^+ + \text{SeO}_3^{2-}\)Each ionization step weakens progressively, meaning the first ionization constant (\(K_a1\)) is larger than the second (\(K_a2\)). This concept explains why subsequent ionizations occur less readily. Understanding successive ionization is key in predicting the pH changes and calculating the concentration of ions in a solution. It also provides insights into how these acids will behave in buffering solutions or when titrated with bases.

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