/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 How is a mole ratio used to find... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

How is a mole ratio used to find the limiting reactant?

Short Answer

Expert verified
A mole ratio helps identify the limiting reactant by comparing required moles (from the balanced equation) to available moles, to determine which reactant will run out first.

Step by step solution

01

Understand the Reaction

To find the limiting reactant, you need to know the balanced chemical equation for the reaction. This equation will provide the molar ratios between the reactants and products. For example, in the reaction \( aA + bB \rightarrow cC + dD \), the coefficients \( a \), \( b \), \( c \), and \( d \) give the molar ratios of the substances involved.
02

Calculate Moles of Reactants

Next, convert the amounts of reactants you have (usually in grams) to moles using the formula: moles \( = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \). This will give you the number of moles of each reactant that you have available.
03

Determine Ideal Moles Required

Using the balanced equation, determine how many moles of the reactants ideally should react together. This is done by referencing the mole ratio from the equation. For instance, if the equation requires 1 mole of \( A \) to react with 2 moles of \( B \), you use the same ratio for the available moles.
04

Compare Available and Required Moles

Compare the actual moles you have of each reactant to the required moles. You do this by checking which reactant would run out first if the reaction were to occur according to the mole ratio. This is the reactant you have less of compared to what's needed.
05

Identify the Limiting Reactant

The reactant that has fewer available moles than required according to the mole ratio is the limiting reactant. This is the reactant that will be completely consumed first, thus limiting the extent of the reaction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mole Ratio
In chemical reactions, understanding the mole ratio is essential for determining how substances interact. The mole ratio refers to the proportion of moles of one substance to the moles of another substance as expressed in the balanced chemical equation.
To illustrate, consider the reaction: \(2H_2 + O_2 \rightarrow 2H_2O\). Here, the mole ratio between hydrogen and oxygen is 2:1, meaning two moles of hydrogen react with one mole of oxygen to form water. This ratio guides how much of each substance we need to completely react with one another.
  • Mole ratios are found from the coefficients of a balanced equation.
  • They are used to scale reactions up or down.
  • They allow chemists to predict how much product will form from given reactants.
Knowing the mole ratio helps in finding the limiting reactant as it dictates the exact amount of each reactant required for the reaction to proceed efficiently. It's a roadmap for the chemical reaction, showing exactly how substances combine.
Balanced Chemical Equation
A balanced chemical equation is a statement that expresses a chemical reaction through symbols and formulas, illustrating how reactants transform into products while adhering to the law of conservation of mass. Every chemical equation must be balanced meaning the number of atoms for each element is the same on both sides of the equation.
Balancing a chemical equation involves adjusting the coefficients (the numbers placed before the molecules) to ensure that the number of atoms for each element is equal on both sides. For example, in the simple equation \(N_2 + 3H_2 \rightarrow 2NH_3\), the atoms are balanced because there are the same number of nitrogen and hydrogen atoms on each side.
  • Balance chemical equations by adjusting coefficients, not subscripts.
  • It ensures the conservation of mass and atoms during the reaction.
  • It provides the accurate mole ratio needed to predict the reactant and product quantities.
This balance is crucial when determining the limiting reactant, as it gives us the precise stoichiometric relationships among the compounds involved.
Moles of Reactants
The amount of each reactant participating in a chemical reaction is expressed in moles. Moles provide a bridge between the atomic scale and the macroscopic quantities we can measure.
To find the number of moles, you divide the mass of the substance (in grams) by its molar mass (in grams per mole). For instance, if you have 18 grams of water with a molar mass of 18 g/mol, you have 1 mole of water.
  • Moles allow chemists to count particles by weighing them.
  • They facilitate easier calculations in stoichiometry.
  • You can calculate the mass of substances needed for a reaction by using moles.
In determining the limiting reactant, it is essential to convert the masses of the reactants into moles using the formula \(\text{moles} = \frac{\text{mass}}{\text{molar mass}}\). This conversion is the key step to relate the quantities of different substances involved in terms of the balanced chemical equation.
Reaction Stoichiometry
Reaction stoichiometry is the calculation of the quantities of reactants and products in a chemical reaction. It involves using the balanced chemical equation to understand the relationships between the reactants consumed and the products formed.
Stoichiometry relies on mole ratios derived from the balanced chemical equation, and these ratios are pivotal when determining the limiting reactant in a reaction. By comparing the actual moles of reactants with the ideal moles required, chemists can identify which reactant is limiting the reaction's extent.
  • Stoichiometry helps in predicting the amounts of products formed from given reactants.
  • It involves calculations using mole ratios, mass, and number of moles.
  • It's integral for determining the efficiency of reactions in practical settings.
Understanding reaction stoichiometry is necessary to accurately identify the limiting reactant, as it ensures that chemists can process and predict outcomes of chemical reactions effectively and efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Car Battery Car batteries use lead, lead(IV) oxide, and a sulfuric acid solution to produce an electric current. The products of the reaction are lead(II) sulfate in solution and water. \begin{equation} \begin{array}{l}{\text { a. Write the balanced equation for the reaction. }} \\\ {\text { b. Determine the mass of lead(II) sulfate produced }} \\ {\text { when } 25.0 \text { g of lead reacts with an excess of lead(IV) }} \\\ {\text { oxide and sulfuric acid. }}\end{array} \end{equation}

How is molar mass used in some stoichiometric calculations?

Alkaline Battery An alkaline battery produces electrical energy according to this equation. \begin{equation} \mathrm{Zn}(\mathrm{s})+2 \mathrm{MnO}_{2}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow \end{equation} \begin{equation} \quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\mathrm{Zn}(\mathrm{OH})_{2}(\mathrm{s})+\mathrm{Mn}_{2} \mathrm{O}_{3}(\mathrm{s}) \end{equation} \begin{equation} \begin{array}{l}{\text { a. Determine the limiting reactant if } 25.0 \mathrm{g} \text { of } \mathrm{Zn} \text { and }} \\ {30.0 \mathrm{g} \text { of } \mathrm{MnO}_{2} \text { are used. }} \\ {\text { b. Determine the mass of } \mathrm{Zn}(\mathrm{OH})_{2} \text { produced. }}\end{array} \end{equation}

Air Pollution Nitrogen oxide, which is present in urban air pollution, immediately converts to nitrogen dioxide as it reacts with oxygen. \begin{equation} \begin{array}{l}{\text { a. Write the balanced chemical equation for the forma- }} \\ {\text { tion of nitrogen dioxide from nitrogen oxide. }} \\\ {\text { b. What mole ratio would you use to convert from }} \\ {\text { moles of nitrogen oxide to moles of nitrogen dioxide? }}\end{array} \end{equation}

Hydrofluoric acid solutions cannot be stored in glass containers because HF reacts readily with silica dioxide in glass to produce hexafluorosilicic acid \(\left(\mathrm{H}_{2} \mathrm{SiF}_{6}\right)\) \begin{equation} \mathrm{SiO}_{2}(\mathrm{s})+6 \mathrm{HF}(\mathrm{aq}) \rightarrow \mathrm{H}_{2} \mathrm{SiF}_{6}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(1) \end{equation} 40.0 \(\mathrm{g} \mathrm{SiO}_{2}\) and 40.0 \(\mathrm{g}\) HF react to yield 45.8 \(\mathrm{g} \mathrm{H}_{2} \mathrm{SiF}_{6}\) \begin{equation} \begin{array}{l}{\text { a. What is the limiting reactant? }} \\ {\text { b. What is the mass of the excess reactant? }}\end{array} \end{equation} \begin{equation} \begin{array}{l}{\text { c. What is the theoretical yield of } \mathrm{H}_{2} \mathrm{SiF}_{6} \text { ? }} \\ {\text { d. What is the percent yield? }}\end{array} \end{equation}

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.