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What information must you have in order to calculate the mass of product formed in a chemical reaction?

Short Answer

Expert verified
Use a balanced equation, reactant mass, molar masses, and stoichiometry to find the product mass.

Step by step solution

01

Determine the Balanced Chemical Equation

To calculate the mass of the product formed in a chemical reaction, the first step is to write down the balanced chemical equation for the reaction. A balanced equation ensures that there is a conservation of mass, with equal numbers of each type of atom in the reactants and the products.
02

Identify the Reactants and Products

Identify all reactants and products in the equation. It is crucial to know which compound's mass is needed and which substances are providing the atoms for the reaction. This step helps in understanding which elements contribute to the final product.
03

Obtain Mass and Molar Mass Information

Gather the initial mass of the reactants. Additionally, find out the molar mass (in g/mol) for each reactant and product. The molar mass can be obtained from the periodic table by adding up the atomic masses of all atoms present in a molecule.
04

Use the Mole Ratio from the Balanced Equation

Use the coefficients of the balanced chemical equation to determine the mole ratio between the reactants and the desired product. This ratio allows the conversion from the moles of a reactant to the moles of a product.
05

Calculate Moles of Reactants

Calculate the number of moles of reactants using the formula: \[ ext{Moles} = \frac{ ext{Mass (g)}}{ ext{Molar Mass (g/mol)}} \]This step is crucial to link the given quantities with the stoichiometry of the chemical equation.
06

Convert Moles of Reactants to Moles of Product

Using the mole ratio from Step 4, convert the moles of the reactants to moles of the product. This step translates the reactant amount into the likely amount of product formed based on the reaction.
07

Calculate the Mass of the Product

Finally, convert the moles of product calculated in the previous step back to mass using the product's molar mass: \[ ext{Mass} = ext{Moles} \times ext{Molar Mass} \]This gives the mass of the product formed in the reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balanced Chemical Equation
To accurately predict the mass of a product in a chemical reaction, it's vital to start with a balanced chemical equation. A balanced equation ensures the law of conservation of mass is maintained, which states that mass can neither be created nor destroyed in a chemical reaction. This balance is necessary to guarantee the number of atoms for each element in the reactants is equal to the number in the products.
To balance a chemical equation, adjust the coefficients (the numbers in front of substances) to ensure that each type of atom matches on both sides.
  • Only change the coefficients, never alter the subscripts (the small numbers in chemical formulas), as doing so will change the substances themselves.
  • Start with the most complex molecules first and leave simpler substances and pure elements for last.
  • Check each element systematically until all are balanced.
A well-balanced equation is the foundation upon which stoichiometry calculations are built, making it a crucial first step in any analysis.
Mole Ratio
The mole ratio is an essential concept in stoichiometry that links reactants to products in a chemical reaction. It is derived from the balanced chemical equation and plays a crucial role in determining the amounts of various substances involved in the reaction.
The coefficients before the chemical formulas in a balanced equation tell you the number of moles of each substance that participate in the reaction. These become the mole ratios needed for calculations.
  • For example, in the equation \(2H_2 + O_2 \rightarrow 2H_2O\), the mole ratio of \(H_2\) to \(H_2O\) is 2:2 or 1:1.
  • This tells us that two moles of hydrogen gas will produce two moles of water.
Using these ratios, you can convert moles of a given reactant to moles of a product, facilitating the determination of the product's mass after further calculations. An accurate mole ratio ensures an understanding of the relationship between different substances in the reaction and is integral to precise chemical calculations.
Molar Mass
Molar mass is the mass of one mole of a substance, expressed in grams per mole (g/mol). It is a key concept in stoichiometry as it connects mass to moles, allowing you to convert between the two in your calculations.
To calculate the molar mass of any compound:
  • Identify the atomic masses of all elements in the compound, which you can find on the periodic table.
  • Add together the atomic masses for all the atoms in the chemical formula.
For example, to find the molar mass of water (\(H_2O\)), you add twice the atomic mass of hydrogen (approximately 1 g/mol per atom) and the atomic mass of oxygen (approximately 16 g/mol). This yields a molar mass of approximately 18 g/mol for water.
Using the equation \( ext{Moles} = \frac{\text{Mass (g)}}{\text{Molar Mass (g/mol)}}\), you can switch between knowing the amount of a substance in terms of mass and moles, an essential part when using stoichiometry to find unknowns in chemical equations.

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Most popular questions from this chapter

List several reasons why the actual yield from a chemical reaction is not usually equal to the theoretical yield.

Car Battery Car batteries use lead, lead(IV) oxide, and a sulfuric acid solution to produce an electric current. The products of the reaction are lead(II) sulfate in solution and water. \begin{equation} \begin{array}{l}{\text { a. Write the balanced equation for the reaction. }} \\\ {\text { b. Determine the mass of lead(II) sulfate produced }} \\ {\text { when } 25.0 \text { g of lead reacts with an excess of lead(IV) }} \\\ {\text { oxide and sulfuric acid. }}\end{array} \end{equation}

Chrome The most important commercial ore of chromium is chromite \(\left(\mathrm{FeCr}_{2} \mathrm{O}_{4}\right) .\) One of the steps in the process used to extract chromium from the ore is the reaction of chromite with coke (carbon) to produce ferrochrome (FeCr_ ). \begin{equation} 2 \mathrm{C}(\mathrm{s})+\mathrm{FeCr}_{2} \mathrm{O}_{4}(\mathrm{s}) \rightarrow \mathrm{FeCr}_{2}(\mathrm{s})+2 \mathrm{CO}_{2}(\mathrm{g}) \end{equation} What mole ratio would you use to convert from moles of chromite to moles of ferrochrome?

Challenge When copper wire is placed into a silver nitrate solution \(\left(\mathrm{AgNO}_{3}\right),\) silver crystals and copper(ll) nitrate \(\left(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\right)\) solution form. \begin{equation} \begin{array}{l}{\text { a. Write the balanced chemical equation for the reaction. }} \\ {\text { b. If a } 20.0 \text { -g sample of copper is used, determine the theoretical yield }} \\ {\text { of silver. }} \\ {\text { c. If } 60.0 \text { g of silver is recovered from the reaction, determine the }} \\\ {\text { percent yield of the reaction. }}\end{array} \end{equation}

When heated by a flame, ammonium dichromate decomposes, producing nitrogen gas, solid chromium(III) oxide, and water vapor \begin{equation} \left(\mathrm{NH}_{4}\right) 2 \mathrm{Cr}_{2} \mathrm{O}_{7} \rightarrow \mathrm{N}_{2}+\mathrm{Cr}_{2} \mathrm{O}_{3}+4 \mathrm{H}_{2} \mathrm{O} \end{equation} Write the mole ratios for this reaction that relate ammonium dichromate to the products.

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