Chapter 10: Problem 20
What is the mass in grams of each of the following? \begin{equation}\begin{array}{l}{\text { a. } 6.02 \times 10^{24} \text { atoms Bi }} \\ {\text { b. } 1.00 \times 10^{24} \text { atoms Mn }} \\\ {\text { c. } 3.40 \times 10^{22} \text { atoms He }} \\ {\text { d. } 1.50 \times 10^{15} \text { atoms } \mathrm{N}} \\ {\text { e. } 1.50 \times 10^{15} \text { atoms } U}\end{array}\end{equation}
Short Answer
Step by step solution
Calculate Moles
Bi - Moles and Mass
Mn - Moles and Mass
He - Moles and Mass
N - Moles and Mass
U - Moles and Mass
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Avogadro's Number
- Converting atoms to moles: Divide the number of atoms by Avogadro's number to find how many moles you have.
- Understanding scale: Although elements vary in size, each mole contains exactly the same number of atoms.
Molar Mass
To calculate the molar mass:
- Check the periodic table: Each element’s atomic weight equals its molar mass.
- Units: It's always in g/mol, allowing you to easily convert from moles to grams.
Mass in Grams
For example, if you have \( 1.66 \) moles of Manganese (Mn) with a molar mass of \( 54.94 \, \text{g/mol} \):
- Calculate mass: \( \text{mass} = \text{moles} \times \text{molar mass} = 1.66 \, \times \, 54.94 \approx 91.18 \, \text{g} \).
Chemical Elements
There are several things to remember about elements:
- Unique identity: Every element has a specific number of protons defining its identity (atomic number).
- Variety of states: Elements can exist in various states—solid, liquid, or gas—depending on environmental conditions.
- Role in chemistry: Understanding elements is crucial for predicting how substances react and combine.