Chapter 14: Problem 4
Estimate the change in entropy when 1.00 mol of argon is heated from \(300 \mathrm{K}\) to \(1200 \mathrm{K}\). What assumptions have you made and how could you make your estimate more accurate? (Section 14.2 ) (The heat capacity, \(C_{p^{\prime}}\), of argon gas is \(20.8 \mathrm{JK}^{-1}\) mol \(^{-1}\).)
Short Answer
Step by step solution
Understand the concept of entropy change
Apply the formula for entropy change
Calculate the natural logarithm
Compute \(\ln(4)\)
Substitute and solve for \(\Delta S\)
Consider assumptions and accuracy
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Entropy
To quantify this change in entropy during a temperature change, we use the formula:
- \(\Delta S = n C_p \ln \left(\frac{T_2}{T_1}\right)\)
Heat Capacity
For argon gas, the given heat capacity is \(C_p = 20.8 \text{ J/K.mol}\). This means that for every mole of argon, 20.8 joules are required to increase the temperature by 1 Kelvin when pressure is kept constant.
In calculations of entropy change during heating, using a constant \(C_p\) simplifies the computation. However, for more precision, one might consider that \(C_p\) can vary with temperature, which could significantly affect the calculated entropy change.
Temperature Change
The extent of temperature change directly influences the increase in thermal energy within the system, thus affecting the entropy. As temperature rises, molecules become more energetic and disordered, and hence the entropy increases.
This is why in our formula for \(\Delta S\), the temperature change is represented as the ratio \(\frac{T_2}{T_1}\). The natural logarithm of this ratio forms part of the calculation for entropy change, emphasizing how even a modest temperature rise can significantly impact the entropy.
Moles of Gas
In our scenario with argon gas, \(n = 1.00\text{ mol}\), which means the calculations for entropy change are based on a single mole of argon being heated.
Choosing the right number of moles is important, as it directly influences the outcome of the entropy change calculation. For multiple moles, the entropy change would be proportionally larger, following the direct relationship in the formula \(\Delta S = n C_p \ln \left(\frac{T_2}{T_1}\right)\).
Thus, understanding the concept of moles helps in quantifying and predicting the thermodynamic changes occurring in a chemical system.