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Which of the following statements is correct ? (a) The \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\) ion has a tetrahedral geometry and is diamagnetic (b) The \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\) ion has a square planar geometry and is paramagnetic (c) The \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right\\}^{2-}\) ion has a square planar geometry and is diamagnetic (d) The \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2-}\) ion has a tetrahedral geometry and is diamagnetic

Short Answer

Expert verified
The correct statement is (c): The \([\text{Ni}(\text{CN})_{4}]^{2-}\) ion has a square planar geometry and is diamagnetic.

Step by step solution

01

Determine the oxidation state of Nickel

Nickel in \([\text{Ni}(\text{CN})_{4}]^{2-}\) is in the oxidation state +2. This is because the CN ligand carries a charge of -1 each, resulting in an overall charge of -4 from the ligands. To match the ion's charge of -2, Nickel must contribute a +2 charge.
02

Find the electron configuration of Ni(II)

The atomic number of Ni is 28, with an electron configuration of [Ar] 3d\(^8\) 4s\(^2\). In Ni(II), the configuration becomes [Ar] 3d\(^8\), as it loses two electrons from the 4s orbital.
03

Determine the hybridization and geometry of the complex

The CN\(^-\) ligands are strong field ligands, which cause the pairing of electrons in the 3d orbitals. This results in the dsp\(^2\) hybridization, giving the \([\text{Ni}(\text{CN})_{4}]^{2-}\) ion a square planar geometry.
04

Determine the magnetic property

In a square planar complex with dsp\(^2\) hybridization, all electrons are paired due to the strong field effect of the CN\(^-\) ligands, making \([\text{Ni}(\text{CN})_{4}]^{2-}\) diamagnetic.
05

Evaluate each provided statement

Go through each statement: (a) Incorrect - The ion has a square planar geometry, not tetrahedral.(b) Incorrect - The ion is diamagnetic, not paramagnetic.(c) Correct - The ion is both square planar and diamagnetic.(d) Incorrect - The \([\text{Cu}(\text{NH}_{3})_{4}]^{2-}\) is square planar with 4 ligands which typically forms a square planar configuration, not tetrahedral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. Understanding electron configuration helps in predicting the chemical, magnetic, and optical properties of complexes. For nickel (Ni) with an atomic number of 28, the electron configuration in its neutral state is
  • d.
  • [Ar] 3d\(^8\) 4s\(^2\)

When Ni forms a complex ion like Ni(II), it loses two electrons from the 4s orbital to become . This new configuration affects its behavior, interaction with ligands, and overall properties such as magnetism and geometry.
Hybridization
Hybridization is essential in understanding the geometry of coordination complexes. It involves the mixing of atomic orbitals to form new hybrid orbitals. In , the presence of strong field ligands like CN\(^-\) leads to the pairing of unpaired d electrons. This results in a dsp\(^2\) hybridization.
With dsp\(^2\) hybridization, the complex assumes a square planar geometry. The square planar shape is typical of coordination compounds and affects both the physical and chemical characteristics of the complex.
  • Knowing the hybridization helps predict the shape.
  • Strong field ligands influence hybridization type.
Magnetism
Magnetism in coordination complexes depends largely on the electron configuration and hybridization of the central metal ion. In a complex like, when strong field ligands such as CN\(^-\) are present, the electrons pair up in the d orbitals. Consequently, iteteti\text{Ni} care d眉zeyinde bir yere gelmemi艧.yedinci s谋ray谋 fazlas谋yla g枚zden 莽谋kararak almak i莽inbu atmosferdeymi艧 gibi yap谋yoraltoid."] denetlenmi艧tir.olgunlar谋n razli膷itih junaka. are fully paired, making the complex \枚gz眉nellikle y眉ksek verim kendisi taperleri bolca izlemektir."莽ok boyutlu bir 艧ark谋 g枚r眉yorum. Ancak tapeler i莽inde kompleks yap谋lar olu艧turuyor.
  • The paired electrons result in a diamagnetic nature.
  • Diamagnetic substances are repelled by magnetic fields.
    • This behavior is crucial for understanding applications in areas like MRI contrast agents or in electronics.
    Oxidation States
    The oxidation state indicates the total number of electrons an atom either gains or loses in forming a chemical bond. Determining the oxidation state is vital for understanding the properties and reactivity of coordination complexes.In the complex, nickel is in the +2 oxidation state. The cyanide ion (CN\(^-\)) has a charge of -1 per ligand; with four cyanide ligands, the total negative charge becomes -4.
    • This requires nickel to have a +2 oxidation state to make the overall charge of the complex -2.
    The oxidation state influences the ion's electron configuration, which further impacts the hybridization, geometry, and magnetic properties of the complex. Understanding these interactions is crucial for identifying and predicting the behavior of coordination compounds in various chemical processes.

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