Chapter 10: Problem 17
Which of the following will have maximum electron affinity ? (a) \(1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}\) (b) \(\mathrm{ls}^{2} 2 \mathrm{~s}^{2} 2 p^{6}\) (c) \(1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 p^{6} 3 \mathrm{~s}^{2} 3 \mathrm{p}^{5}\) (d) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}\)
Short Answer
Step by step solution
Understanding Electron Configuration
Analyzing Option A
Analyzing Option B
Analyzing Option C
Analyzing Option D
Understanding Electron Affinity
Comparing Non-Noble Gases
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Configuration
- The s subshell can hold 2 electrons.
- The p subshell can hold 6 electrons.
- The d subshell can hold 10 electrons, while the f subshell holds 14 electrons.
Nonmetals
- High electron affinities, making them eager to gain additional electrons.
- They are usually poor conductors of electricity and heat.
- Nonmetals can form both ionic and covalent bonds.
Noble Gases
- They have full electron configurations, giving them no tendency to gain, lose, or share electrons.
- These gases are colorless, odorless, and tasteless.
- Due to their stability, they have very low chemical reactivity compared to nonmetals.
Electron-Electron Repulsion
- In small atoms like Fluorine, added electrons face higher repulsions because the space in their p orbitals is more cramped following the atom's compact nature.
- Larger atoms like Chlorine have more space in their outer shell, reducing the repulsion among electrons when a new electron is added.
- This reduced repulsion is why Chlorine usually exhibits a higher electron affinity than Fluorine, despite having more electrons.