/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 What is the highest oxidation nu... [FREE SOLUTION] | 91影视

91影视

What is the highest oxidation number that sulfur can have? The lowest? Consider the number of valence electrons it has.

Short Answer

Expert verified
Sulfur's highest oxidation number is +6, and its lowest is -2.

Step by step solution

01

Understand the Electron Configuration of Sulfur

Sulfur has an atomic number of 16, meaning it has 16 electrons. The electron configuration is \(1s^2 2s^2 2p^6 3s^2 3p^4\). This indicates that sulfur has 6 electrons in its outer shell (3s and 3p orbitals), which are its valence electrons.
02

Determine the Maximum Oxidation Number

The maximum oxidation number of an element is achieved when it loses all its valence electrons. For sulfur, with 6 valence electrons, the highest oxidation number would be +6. This is because sulfur can lose up to 6 electrons when it forms compounds.
03

Determine the Minimum Oxidation Number

The minimum oxidation number is based on how many electrons an element can gain to complete its valence shell. Sulfur can gain 2 electrons to fill its 3p shell, reaching the stable electron configuration of \(3s^2 3p^6\). Therefore, the lowest oxidation number of sulfur is -2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sulfur Electron Configuration
Sulfur is a chemical element with the symbol **S** and atomic number **16**. Understanding its electron configuration is key to deciphering its chemical behavior. The electron configuration describes the distribution of electrons among the different atomic orbitals in an atom. For sulfur, its electron configuration is: \[1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^4\]The numbers before the letters (1, 2, 3) represent the energy levels or shells. The letters (s, p) denote the type of orbitals, and the superscript numbers indicate the number of electrons in those orbitals. Thus, sulfur's configuration illustrates that it has 16 electrons distributed across the orbitals up to the 3rd energy level. The **3s^2 3p^4** part of the configuration shows that 6 electrons are in its outermost shell, meaning these are the **valence electrons**. Valence electrons are critical for bonding and chemical reactions.
Valence Electrons
Valence electrons play a crucial role in determining how an element reacts chemically. These are the electrons located in the outermost shell (or energy level) of an atom. For sulfur, there are **six valence electrons**, as highlighted in its electron configuration: - 3s orbital: 2 electrons - 3p orbital: 4 electrons In its natural state, sulfur has these six outer electrons available for forming chemical bonds with other elements. Sulfur's valence electron configuration allows it to easily participate in a variety of chemical reactions, either by losing or gaining electrons. Recognizing the number and behavior of valence electrons is fundamental to predicting the chemical and physical properties of sulfur.
Maximum Oxidation Number
The maximum oxidation number of an element corresponds to the number of valence electrons it can lose. For sulfur, this number is determined by its six valence electrons. When sulfur forms compounds, it can shed all of these electrons, achieving a maximum oxidation state of **+6**. This occurs, for example, in sulfuric acid (H鈧係O鈧), where sulfur is in its highest oxidation state. The process involves oxidation, which results in the sulfur atom losing electrons, thereby increasing its oxidation number. Knowing the maximum oxidation state can help predict the behavior of sulfur in various chemical reactions and its ability to form different kinds of compounds.
Minimum Oxidation Number
The minimum oxidation number for sulfur is based on filling its valence shell to achieve a stable electronic configuration. Sulfur can gain two additional electrons to fill its 3p orbital, completing the set with six electrons (from 3p鈦 to 3p鈦). This results in sulfur reaching its octet completion and achieving a stable state, akin to a noble gas configuration. Consequently, the minimum oxidation number of sulfur is **-2**. This oxidation state is typically observed in compounds like hydrogen sulfide (H鈧係). In this form, sulfur acts as a reducing agent by gaining electrons in the formation of bonds, which is common in many of its compounds, particularly those found in biological systems and natural processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If the enthalpy change is favorable and the entropy change is favorable, would the reaction be spontaneous at high temperatures, low temperatures, or all temperatures?

Explain why the activation energy of a reaction is sometimes referred to as a barrier.

Reactant B goes from \(2.25 \mathrm{M}\) to \(1.50 \mathrm{M}\) in \(0.85\) seconds. What is the rate of change of \(\mathrm{B}\) ?

Determine the oxidation numbers of each of the atoms in the following. a. \(\mathrm{KMnO}_{4}\) b. \(\mathrm{OCl}_{2}\) c. \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) d. \(\mathrm{Li}_{3} \mathrm{PO}_{4}\) e. \(\mathrm{NaClO}\) f. \(\mathrm{Br}_{2}\) g. \(\mathrm{ClF}_{3}\) h. \(\mathrm{CaCl}_{2}\) i. \(\mathrm{K}_{2} \mathrm{O}\)

Balance the following equations and classify the following reactions as combination, decomposition, single replacement, double replacement, or combustion. For each, indicate if it is a redox reaction or not. a. \(\mathrm{Na}+\mathrm{Cl}_{2} \rightarrow \mathrm{NaCl}\) b. \(\mathrm{Na}_{3} \mathrm{PO}_{4}+\mathrm{KOH} \rightarrow \mathrm{NaOH}+\mathrm{K}_{3} \mathrm{PO}_{4}\) c. \(\mathrm{P}_{4}+\mathrm{O}_{2} \rightarrow \mathrm{P}_{2} \mathrm{O}_{3}\) d. \(\mathrm{N}_{2}+\mathrm{H}_{2} \rightarrow \mathrm{NH}_{3}\) e. \(\mathrm{Al}+\mathrm{HCl} \rightarrow \mathrm{H}_{2}+\mathrm{AlCl}_{3}\) f. \(\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}\) g. \(\mathrm{NH}_{3}+\mathrm{CuO} \rightarrow \mathrm{Cu}+\mathrm{N}_{2}+\mathrm{H}_{2} \mathrm{O}\) h. \(\mathrm{NH}_{4} \mathrm{NO}_{3} \rightarrow \mathrm{N}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{O}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.