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Write the electron configuration for each of the following ions, and determine which ones possess noble-gas configurations: (a) \(\mathrm{Sr}^{2+}\), (b) \(\mathrm{Ti}^{2+}\), (c) \(\mathrm{Se}^{2-}\),(d) \(\mathrm{Ni}^{2+}\),(e) \(\mathrm{Br}^{-}\), (f) \(\mathrm{Mn}^{3+}\).

Short Answer

Expert verified
The electron configurations for the given ions are: (a) \(\mathrm{Sr}^{2+}\): [Kr] - Noble gas configuration (b) \(\mathrm{Ti}^{2+}\): [Ar]3d^2 - Not a noble gas configuration (c) \(\mathrm{Se}^{2-}\): [Kr] - Noble gas configuration (d) \(\mathrm{Ni}^{2+}\): [Ar]3d^6 - Not a noble gas configuration (e) \(\mathrm{Br}^{-}\): [Kr] - Noble gas configuration (f) \(\mathrm{Mn}^{3+}\): [Ar]3d^2 - Not a noble gas configuration \(\mathrm{Sr}^{2+}\), \(\mathrm{Se}^{2-}\), and \(\mathrm{Br}^{-}\) possess noble-gas configurations.

Step by step solution

01

1. Write the electron configuration of the neutral atom

First, we should write the electron configuration of the neutral atom for each element. You can use the periodic table to find the order in which subshells are filled. (a) Sr: [Kr]5s^2 (b) Ti: [Ar]4s^2 3d^2 (c) Se: [Ar]4s^2 3d^{10} 4p^4 (d) Ni: [Ar]4s^2 3d^8 (e) Br: [Ar]4s^2 3d^{10} 4p^5 (f) Mn: [Ar]4s^2 3d^5
02

2. Write the electron configuration of each ion

Now, taking into account the charge of each ion, we will adjust the number of electrons to match the charge. Subshells should be emptied according to the (n+l) rule, respecting Hund's rule. (a) \(\mathrm{Sr}^{2+}\): [Kr] (b) \(\mathrm{Ti}^{2+}\): [Ar]3d^2 (c) \(\mathrm{Se}^{2-}\): [Ar]4s^2 3d^{10} 4p^6 (d) \(\mathrm{Ni}^{2+}\): [Ar]3d^8-2 = [Ar]3d^6 (e) \(\mathrm{Br}^{-}\): [Ar]4s^2 3d^{10} 4p^5+1 = [Ar]4s^2 3d^{10} 4p^6 (f) \(\mathrm{Mn}^{3+}\): [Ar]4s^2 3d^5-3 = [Ar]3d^2
03

3. Compare the electron configurations with noble gases

Finally, we will compare the electron configurations of each ion to the electron configurations of noble gases. Noble gases have completely filled s and p orbitals in their highest energy level. (a) \(\mathrm{Sr}^{2+}\): [Kr] - Noble gas configuration (b) \(\mathrm{Ti}^{2+}\): [Ar]3d^2 - Not a noble gas configuration (c) \(\mathrm{Se}^{2-}\): [Ar]4s^2 3d^{10} 4p^6 - Noble gas configuration ([Kr]) (d) \(\mathrm{Ni}^{2+}\): [Ar]3d^6 - Not a noble gas configuration (e) \(\mathrm{Br}^{-}\): [Ar]4s^2 3d^{10} 4p^6 - Noble gas configuration ([Kr]) (f) \(\mathrm{Mn}^{3+}\): [Ar]3d^2 - Not a noble gas configuration So, \(\mathrm{Sr}^{2+}\), \(\mathrm{Se}^{2-}\), and \(\mathrm{Br}^{-}\) possess noble-gas configurations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Noble Gas Configuration
A noble gas configuration is a key concept in understanding how ions stabilize themselves by achieving a completely filled electron shell, similar to the nearest noble gas. Noble gases are known for their stability, since their outermost electron shell is fully occupied, providing them with minimal reactivity. To achieve a noble gas configuration, atoms will gain, lose, or share electrons to fill or empty their outer electron shell. This process results in a stable electronic arrangement. For example:
  • Strontium Ion (\(\mathrm{Sr}^{2+}\)): When it loses 2 electrons, it shares the same electron configuration as Krypton, \([\mathrm{Kr}]\).
  • Selenium Ion (\(\mathrm{Se}^{2-}\)): Gains 2 electrons and matches Krypton, \([\mathrm{Kr}]\).
  • Bromine Ion (\(\mathrm{Br}^{-}\)): By gaining 1 electron, it achieves the configuration of Krypton, \([\mathrm{Kr}]\).
Achieving a noble gas configuration is an important principle as it explains why elements form ions with certain charges. By doing so, they reach a low energy state, making them more stable compared to their neutral form.
Electron Subshells
Electron subshells describe regions where electrons are likely to be found in an atom. These regions are part of a larger structure known as electron shells, which are divided into subshells labeled as \(s\),\(p\),\(d\), and \(f\).In each subshell, electrons have specific levels of energy.Understanding subshells provides insight into why electrons occupy certain positions within an atom's structure. For instance:
  • The \(s\) subshell can hold up to 2 electrons.
  • The \(p\) subshell can accommodate up to 6 electrons.
  • The\(d\) subshell has room for up to 10 electrons.
  • The\(f\) subshell can contain up to 14 electrons.
By analyzing the electron configuration of ions, we determine electrons are removed from the highest energy subshell first. This often means electrons in the \(s\) subshell get removed before the\(d\) subshell in transition metals, as seen in the example of \(\mathrm{Ni}^{2+}\), where two outer electrons are lost from the \(4s\) subshell first.
Periodic Table
The periodic table is an essential tool in understanding electron configurations and the behavior of elements. It organizes elements in a way that highlights periodicity, meaning trends and patterns repeat throughout the table.Each element's position on the periodic table corresponds to its atomic structure, including:
  • Electron configuration and energy levels, which determine chemical behavior and properties.
  • The atomic number, indicating the number of protons and consequently the number of electrons in a neutral atom.
For effective electron configuration, elements are grouped into blocks:
  • s-block: Includes Groups 1 and 2, where electron configurations end in \(s\) subshells.
  • p-block: Holds Groups 13 to 18, with electron configurations ending in \(p\) subshells.
  • d-block: Known as transition metals, associated with \(d\) subshells.
  • f-block: Contains lanthanides and actinides, with electrons filling \(f\) subshells.
Utilizing the periodic table, we predict electron configurations and predict how ions will form. For instance, Selenium is located in the \(p\) block, indicating its outer electrons are in \(p\) orbitals. Understanding these patterns helps predict chemical reactions and behavior.

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Most popular questions from this chapter

(a) Use bond enthalpies to estimatethe enthalpy change for the reaction of hydrogen with ethene: $$\mathrm{H}_{2}(\mathrm{~g})+\mathrm{C}_{2} \mathrm{H}_{4}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{6}(g)$$ (b) Calculate the standard enthalpy change for this reaction, using heats of formation. Why does this value differ from that calculated in (a)?

In the following pairs of binary compounds determine which one is a molecular substance and which one is an ionic substance. Use the appropriatenaming convention (for ionic or molecular substances) to assign a name to each compound: (a) \(\mathrm{SiF}_{4}\) and \(\mathrm{LaF}_{3}\), (b) \(\mathrm{FeCl}_{2}\) and \(\mathrm{ReCl}_{6}\), (c) \(\mathrm{PbCl}_{4}\) and \(\mathrm{RbCl}\)

One scale for electronegativity is based on the concept that the electronegativity of any atom is proportional to the ionization energy of the atom minus its electron affinity: electronegativity \(=k(\mathrm{IE}-\mathrm{EA})\), where \(k\) is a proportionality constant. (a) How does this definition explain why the electronegativity of \(\mathrm{F}\) is greater than that of \(C l\) even though \(C l\) has the greater electron affinity? (b) Why are both ionization energy and electron affinity relevant to the notion of electronegativity? (c) By using data in Chapter 7 , determine the value of \(k\) that would lead to an electronegativity of \(4.0\) for \(\mathrm{F}\) under this definition. (d) Use your result from part (c) to determine the electronegativities of \(\mathrm{Cl}\) and \(\mathrm{O}\) using this scale. Do these values follow the trend shown in Figure \(8.6\) ?

(a) Does the lattice energy of an ionic solid increase or decrease (i) as the charges of the ions increase, (ii) as the sizes of the ions increase? (b) Using a periodic table, arrange the following substances according to their expected lattice energies, listing them from lowest lattice energy to the highest: \(\mathrm{ScN}, \mathrm{KBr}, \mathrm{MgO}\), NaF. Compare your list with the data in Table \(8.2\).

Consider the nitryl cation, \(\mathrm{NO}_{2}^{+}\). (a) Write one or more appropriate Lewis structures for this ion. (b) Are resonance structures needed to describe the structure? (c) With what familiar molecule is it isoelectronic?

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