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Identify the specific element that corresponds to each of the following electron configurations: (a) \(1 s^{2} 2 s^{2}\), (b) \(1 s^{2} 2 s^{2} 2 p^{4}\), (c) \([\mathrm{Ar}] 4 s^{1} 3 d^{5}\), (d) \([\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{4}\), (e) \(1 s\) ?

Short Answer

Expert verified
The elements corresponding to each electron configuration are: (a) Beryllium (Be), (b) Oxygen (O), (c) Chromium (Cr), (d) Tellurium (Te), and (e) Hydrogen (H).

Step by step solution

01

(a) 1s^2 2s^2 Electron Configuration

For this configuration, we have a total of 4 electrons (2 in the 1s subshell and 2 in the 2s subshell). The element with 4 electrons is Beryllium (Be). Its atomic number is 4.
02

(b) 1s^2 2s^2 2p^4 Electron Configuration

For this configuration, we have a total of 8 electrons (2 in the 1s, 2 in the 2s, and 4 in the 2p subshells). The element with 8 electrons is Oxygen (O). Its atomic number is 8.
03

(c) [Ar] 4s^1 3d^5 Electron Configuration

Here, we have a noble gas, Argon (Ar) in the electron configuration. Argon has 18 electrons. Additionally, there is 1 electron in the 4s subshell and 5 electrons in the 3d subshell. Therefore, in total, there are 18 + 1 + 5 = 24 electrons. The element with 24 electrons is Chromium (Cr). Its atomic number is 24.
04

(d) [Kr] 5s^2 4d^10 5p^4 Electron Configuration

Here, we have another noble gas, Krypton (Kr) in the electron configuration. Krypton has 36 electrons. Additionally, there are 2 electrons in the 5s, 10 electrons in the 4d, and 4 electrons in the 5p subshells. Therefore, in total, there are 36 + 2 + 10 + 4 = 52 electrons. The element with 52 electrons is Tellurium (Te). Its atomic number is 52.
05

(e) 1s Electron Configuration

For this configuration, we have only 1 electron in the 1s subshell. The element with 1 electron is Hydrogen (H). Its atomic number is 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Number
The atomic number of an element is fundamental to understanding its place in the periodic table and its chemical behavior. The atomic number represents the number of protons in an atom's nucleus, and by extension, it also equals the number of electrons in a neutral atom. This number is unique to each element and determines the element's identity.
For example, in the exercise given, Beryllium (Be) has an atomic number of 4, meaning it has 4 protons in its nucleus and 4 electrons orbiting the nucleus. By knowing the atomic numbers, students can easily use the electron configurations to identify elements, as seen in the textbook solutions. When an element's electron configuration is written, we begin by counting electrons up to the atomic number, which then helps in determining the type and arrangement of subshells that contain these electrons.
  • The atomic number is crucial for understanding the periodic table.
  • It determines the specific identity of an element.
  • It helps to link the electron configurations to the correct element.
Subshells in Quantum Chemistry
Subshells are divisions within the electron shells of an atom and are denoted by the letters s, p, d, and f. These subshells have different capacities for electrons: 's' can hold 2, 'p' can hold 6, 'd' can hold 10, and 'f' can hold 14 electrons.
In quantum chemistry, the energy levels and the presence of subshells are defined by quantum numbers. These help predict the electron configuration of each element. For instance, the exercise solutions demonstrate how to distribute electrons through the different subshells. In case (a), the electrons are distributed in the 1s and 2s subshells, consistent with Beryllium's configuration.
Understanding subshells is critical because they dictate an atom's shape and how it bonds with other atoms. Here are some key points:
  • Subshells are based on quantum numbers.
  • They determine the distribution of electrons in an atom.
  • They are essential for predicting chemical bonding and properties.
When dealing with subshells, it's important to fill in the lower energy subshells first, following the 'Aufbau Principle', before moving on to higher energy subshells.
Noble Gas Notation
Noble gas notation, also known as electron configuration shorthand, simplifies the representation of an atom's electron structure by using the closest previous noble gas to represent filled subshells. It is a convenient way, especially for elements with a large atomic number, to denote their electron configurations without having to write out all the preceding electron arrangements.
In the given exercise, Chromium's electron configuration starts with \[Ar\], which represents all of the electron subshells filled up to Argon, a noble gas. From this point, only the electrons in excess of Argon's configuration are listed (4s^1 3d^5).
Using noble gas notation helps to display how additional electrons fill the available subshells beyond the noble gas configuration. This method not only makes writing electron configurations faster but also eases the understanding of valence electrons, which are fundamental for forming chemical bonds.
  • Noble gas notation abbreviates electron configuration.
  • It begins with the electron configuration of the nearest noble gas.
  • It highlights the valence subshells which are key in chemical bonding.
Remember that the noble gases are located at the end of each row in the periodic table, and they include Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), and Radon (Rn). Use the noble gas that comes before your element of interest in the periodic table when applying this notation.

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Most popular questions from this chapter

The discovery of hafnium, element number 72, provided a controversial episode in chemistry. G. Urbain, a French chemist, claimed in 1911 to have isolated an element number 72 from a sample of rare earth (elements 58-71) compounds. However, Niels Bohr believed that hafnium was more likely to be found along with zirconium than with the rare earths. D. Coster and \(G\). von Hevesy, working in Bohr's laboratory in Copenhagen, showed in 1922 that element 72 was present in a sample of Norwegian zircon, an ore of zirconium. (The name hafnium comes from the Latin name for Copenhagen, Hafnia). (a) How would you use electron configuration arguments to justify Bohr's prediction? (b) Zirconium, hafnium's neighbor in group \(4 \mathrm{~B}\), can be produced as a metal by reduction of solid \(\mathrm{ZrCl}_{4}\) with molten sodium metal. Write a balanced chemical equation for the reaction. Is this an oxidation- reduction reaction? If yes, what is reduced and what is oxidized? (c) Solid zirconium dioxide, \(\mathrm{ZrO}_{2}\), is reacted with chlorine gas in the presence of carbon. The products of the reaction are \(\mathrm{ZrCl}_{4}\) and two gases, \(\mathrm{CO}_{2}\) and \(\mathrm{CO}\) in the ratio \(1: 2 \mathrm{Write}\) a balanced chemical equation for the reaction. Starting with a 55.4-g sample of \(\mathrm{ZrO}_{2}\), calculate the mass of \(\mathrm{ZrCl}_{4}\) formed, assuming that \(\mathrm{ZrO}_{2}\) is the limiting reagent and assuming \(100 \%\) yield. (d) Using their electron configurations, account for the fact that \(\mathrm{Zr}\) and Hf form chlorides \(\mathrm{MCl}_{4}\) and oxides \(\mathrm{MO}_{2}\).

When the spectrum of light from the Sun is examined in high resolution in an experiment similar to that illustrated in Figure 6.11, dark lines are evident. These are called Fraunhofer lines, after the scientist who studied them extensively in the early nineteenth century. Altogether, about 25,000 lines have been identified in the solar spectrum between \(2950 \AA\) and \(10,000 \AA\). The Fraunhofer lines are attributed to absorption of certain wavelengths of the Sun's "white" light by gaseous elements in the Sun's atmosphere. (a) Describe the process that causes absorption of specific wavelengths of light from the solar spectrum. (b) If a scientist wanted to know which Fraunhofer lines belonged to a given element, say neon, what experiments could she conduct here on Earth to provide data?

Sketch the shape and orientation of the following types of orbitals: (a) \(p_{x}\), (b) \(d_{z^{2}}\),(c) \(d_{x^{2}-y^{2}}\).

Is energy emitted or absorbed when the following electronic transitions occur in hydrogen: (a) from \(n=4\) to \(n=2,(b)\) from an orbit of radius \(2.12 \AA\) to one of radius \(8.46 \AA\), (c) an electron adds to the \(\mathrm{H}^{+}\) ion and ends up in the \(n=3\) shell?

(a) According to the Bohr model, an electron in the ground state of a hydrogen atom orbits the nucleus at a specific radius of \(0.53 \AA\). In the quantum mechanical description of the hydrogen atom, the most probable distance of the electron from the nucleus is \(0.53 \AA\). Why are these two statements different? (b) Why is the use of Schrödinger's wave equation to describe the location of a particle very different from the description obtained from classical physics? (c) In the quantum mechanical description of an electron, what is the physical significance of the square of the wave function, \(\psi^{2} ?\)

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