/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 Ethanol \(\left(\mathrm{C}_{2} \... [FREE SOLUTION] | 91影视

91影视

Ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) is currently blended with gasoline as an automobile fuel. (a) Write a balanced equation for the combustion of liquid ethanol in air. (b) Calculate the standard enthalpy change for the reaction, assuming \(\mathrm{H}_{2} \mathrm{O}(g)\) as a product. (c) Calculate the heat produced per liter of ethanol by combustion of ethanol under constant pressure. Ethanol has a density of \(0.789 \mathrm{~g} / \mathrm{mL}\) (d) Calculate the mass of \(\mathrm{CO}_{2}\) produced per \(\mathrm{kJ}\) of heat emitted.

Short Answer

Expert verified
(a) The balanced equation for the combustion of ethanol is: \( C_{2}H_{5}OH + 3O_{2} \rightarrow 2CO_{2} + 3H_{2}O \). (b) The standard enthalpy change for the reaction is -1234.4 kJ/mol. (c) The heat produced per liter of ethanol by combustion under constant pressure is -21133.2 kJ. (d) The mass of CO2 produced per kJ of heat emitted is 0.0713 g/kJ.

Step by step solution

01

a) Writing the balanced equation for the combustion of ethanol.

Combustion of ethanol occurs when it reacts with oxygen to produce carbon dioxide and water. The unbalanced equation is: C2H5OH + O2 -> CO2 + H2O To balance the equation, we need to balance the number of atoms for each element on both sides. After balancing the equation, we have: C2H5OH + 3O2 -> 2CO2 + 3H2O The balanced equation for the combustion of ethanol is: \( C_{2}H_{5}OH + 3O_{2} \rightarrow 2CO_{2} + 3H_{2}O \)
02

b) Calculating the standard enthalpy change for the reaction.

To calculate the standard enthalpy change for the combustion of ethanol, we will use the standard enthalpies of formation for the reactants and products. The standard enthalpies of formation of ethanol, oxygen gas, carbon dioxide, and water vapor are: 螖Hf鈦 (C2H5OH) = -277.7 kJ/mol 螖Hf鈦 (O2) = 0 kJ/mol (since O2 is an element in its standard state) 螖Hf鈦 (CO2) = -393.5 kJ/mol 螖Hf鈦 (H2O) = -241.8 kJ/mol The standard enthalpy change for the reaction (螖Hrxn) is given by the difference between the products' and reactants' standard enthalpies of formation multiplied by the stoichiometric coefficients in the balanced equation: 螖Hrxn = [2(螖Hf鈦 (CO2)) + 3(螖Hf鈦 (H2O)] - [螖Hf鈦 (C2H5OH) + 3(螖Hf鈦 (O2))] 螖Hrxn = [2(-393.5) + 3(-241.8)] - [-277.7 + 3(0)] 螖Hrxn = [-787 - 725.4] - [-277.7] 螖Hrxn = -1234.4 kJ/mol So, the standard enthalpy change for the combustion of ethanol is -1234.4 kJ/mol.
03

c) Calculating the heat produced per liter of ethanol.

To calculate the heat produced per liter of ethanol, we first need to determine the number of moles of ethanol in a liter using the given density: Density of ethanol = 0.789 g/mL 1 L of ethanol = 1000 mL Mass of 1 L ethanol = (0.789 g/mL) * (1000 mL) = 789 g Molar mass of ethanol = 2(12.01) + 6(1.01) + 1(16.00) = 46.07 g/mol Number of moles of ethanol in 1 L = (789 g) / (46.07 g/mol) = 17.13 mol Now that we know the moles of ethanol in one liter, we can use the standard enthalpy change for the reaction to find the heat produced: Heat produced per liter = (17.13 mol) * (-1234.4 kJ/mol) = -21133.2 kJ So, the heat produced per liter of ethanol by combustion under constant pressure is -21133.2 kJ.
04

d) Calculating the mass of CO2 produced per kJ of heat emitted.

To calculate the mass of CO2 produced per kJ of heat emitted, we first need to determine the amount of CO2 produced for each mole of ethanol burnt: From the balanced equation: 1 mol C2H5OH -> 2 mol CO2 So, the amount of CO2 produced for 17.13 mol of ethanol is: CO2 produced = (17.13 mol C2H5OH) * (2 mol CO2 / 1 mol C2H5OH) = 34.26 mol CO2 Now, the mass of CO2 produced is given by: Mass of CO2 produced = (34.26 mol CO2) * (44.01 g/mol) = 1507.05 g Finally, we can find the mass of CO2 produced per kJ of heat emitted: Mass of CO2 per kJ of heat = (1507.05 g) / (21133.2 kJ) = 0.0713 g/kJ So, the mass of CO2 produced per kJ of heat emitted is 0.0713 g/kJ.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balanced Chemical Equations
In chemistry, a balanced chemical equation represents the conservation of mass and energy by ensuring the same quantity of each type of atom is present on both sides of the equation. For ethanol combustion, the reactants are ethanol (\( \text{C}_2\text{H}_5\text{OH} \)) and oxygen (\( \text{O}_2 \)), while the products are carbon dioxide (\( \text{CO}_2 \)) and water (\( \text{H}_2\text{O} \)).
To balance this equation, the goal is to have equal numbers of carbon, hydrogen, and oxygen atoms on both sides. Initially, the equation is:\[\text{C}_2\text{H}_5\text{OH} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O}\]First, balance the carbon atoms by placing a coefficient of 2 before \( \text{CO}_2 \), and then balance the hydrogen by placing 3 before \( \text{H}_2\text{O} \). Finally, adjust the oxygen atoms so that both sides have an equal amount, resulting in:\[\text{C}_2\text{H}_5\text{OH} + 3\text{O}_2 \rightarrow 2\text{CO}_2 + 3\text{H}_2\text{O}\]This balanced equation shows that one molecule of ethanol reacts with three molecules of oxygen, producing two molecules of carbon dioxide and three molecules of water.
Standard Enthalpy Change
The concept of standard enthalpy change refers to the amount of heat absorbed or released during a chemical reaction under standard conditions, typically 1 atm pressure and 298 K temperature.
This is often denoted by \(\Delta H_{rxn}\).
For the combustion of ethanol, the standard enthalpy change can be calculated by using the standard enthalpies of formation (\(\Delta H_f^0\)) for each substance involved.
Here are the values for each relevant compound:
  • \(\Delta H_f^0 (\text{C}_2\text{H}_5\text{OH}) = -277.7\, \text{kJ/mol} \)
  • \(\Delta H_f^0 (\text{O}_2) = 0\, \text{kJ/mol} \)
  • \(\Delta H_f^0 (\text{CO}_2) = -393.5\, \text{kJ/mol} \)
  • \(\Delta H_f^0 (\text{H}_2\text{O}) = -241.8\, \text{kJ/mol} \)
The enthalpy change for the reaction is calculated as follows:\[\Delta H_{rxn} = \left[2(\Delta H_f^0 (\text{CO}_2)) + 3(\Delta H_f^0 (\text{H}_2\text{O})\right] - \left[\Delta H_f^0 (\text{C}_2\text{H}_5\text{OH}) + 3(\Delta H_f^0 (\text{O}_2))\right]\]Plug in the values:\[\Delta H_{rxn} = \left[2(-393.5) + 3(-241.8)\right] - \left[-277.7 + 3(0)\right]\]This results in a standard enthalpy change of \(-1234.4 \, \text{kJ/mol}\), indicating that the reaction is exothermic, releasing energy.
Energy Production from Combustion
Ethanol combustion is a useful energy source due to the heat it releases. Calculating the heat produced involves understanding the relationship between the molar energy change and the number of moles reacting.
To find the energy released per liter of ethanol:
  • The density of ethanol is \(0.789\, \text{g/mL}\), leading to a mass of \(789\, \text{g}\) per liter.
  • The molar mass of ethanol is \(46.07\, \text{g/mol}\), so the number of moles in one liter is \(\frac{789}{46.07} = 17.13\, \text{mol}\).
Using the standard enthalpy change found previously:
  • Multiply the number of moles by the enthalpy change: \(17.13\, \text{mol} \times (-1234.4\, \text{kJ/mol}) = -21133.2\, \text{kJ}\)
Thus, each liter of ethanol releases \(21133.2\, \text{kJ}\) of energy upon combustion, which makes ethanol a powerful fuel source when burned under controlled conditions.
Carbon Dioxide Emission Calculations
Understanding the environmental impact of ethanol combustion involves calculating the amount of carbon dioxide produced per unit of energy.
The balanced equation indicates that each mole of ethanol combusted produces 2 moles of carbon dioxide.
For 17.13 moles of ethanol, as is found in one liter, the production of carbon dioxide can be determined:
  • Twice the moles of ethanol, resulting in \(34.26\, \text{mol}\) of \(\text{CO}_2\)
  • The molar mass of carbon dioxide is \(44.01\, \text{g/mol}\)
  • Hence, \(34.26\, \text{mol} \times 44.01\, \text{g/mol} = 1507.05\, \text{g}\) of \(\text{CO}_2\) is produced.
Now, calculate the mass of \(\text{CO}_2\) per \(\text{kJ}\) of heat emitted:
  • Using the energy per liter, \(21133.2\, \text{kJ}\)
  • Divide the total CO2 mass by the energy: \(\frac{1507.05\, \text{g}}{21133.2\, \text{kJ}} = 0.0713\, \text{g/kJ}\)
This result shows that for each kilojoule of energy released from ethanol combustion, approximately \(0.0713\, \text{g}\) of carbon dioxide is emitted, highlighting the environmental impact related to air quality and greenhouse gas emissions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the combustion of liquid methanol, \(\mathrm{CH}_{3} \mathrm{OH}(I)\) : \(\mathrm{CH}_{3} \mathrm{OH}(l)+\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)\) \(\Delta H=-726.5 \mathrm{~kJ}\) (a) What is the enthalpy change for the reverse reaction? (b) Balance the forward reaction with whole-number coefficients. What is \(\Delta H\) for the reaction represented by this equation? (c) Which is more likely to be thermodynamically favored, the forward reaction or the reverse reaction? (d) If the reaction were written to produce \(\mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) instead of \(\mathrm{H}_{2} \mathrm{O}(\mathrm{l})\), would you expect the magni- tude of \(\Delta H\) to increase, decrease, or stay the same? Explain.

(a) What are the units of molar heat capacity? (b) What are the units of specific heat? (c) If you know the specific heat of copper, what additional information do you need to calculate the heat capacity of a particular piece of copper pipe?

From the enthalpies of reaction calculate \(\Delta H\) for the reaction of ethylene with \(\mathrm{F}_{2}\) $$ \mathrm{C}_{2} \mathrm{H}_{4}(g)+6 \mathrm{~F}_{2}(g)-\cdots 2 \mathrm{CF}_{4}(g)+4 \mathrm{HF}(g) $$

Consider the combustion of a single molecule of \(\mathrm{CH}_{4}(g)\) forming \(\mathrm{H}_{2} \mathrm{O}(l)\) as a product. (a) How much energy, in J. is produced during this reaction? (b) A typical X-ray photon has an energy of \(8 \mathrm{keV}\). How does the energy of combustion compare to the energy of the X-ray photon?

(a) State the first law of thermodynamics. (b) What is meant by the internal energy of a system? (c) By what means can the internal energy of a closed system increase?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.