/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 Explain why a titration experime... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Problem 91

Explain why a titration experiment is a good way to measure the unknown concentration of a compound in solution.

Short Answer

Expert verified
A titration experiment is an effective method to measure the unknown concentration of a compound in a solution due to its principle of stoichiometry, precision in titrant addition, and endpoint detection. The stoichiometry of the reaction between the two solutions determines the ratio in which they react, allowing the calculation of the unknown concentration. The precision of titrant addition and effective endpoint detection ensures accurate and reliable results, making titration a suitable method for determining concentrations of unknown solutions.

Step by step solution

01

Understand Titration

Titration is a laboratory technique used to determine the concentration of an unknown solution by reacting it with a known volume and concentration of another solution, called the titrant. During a titration experiment, the titrant is slowly added to the unknown solution until the reaction is complete, as indicated by an endpoint. The endpoint is often observed using a pH indicator or by a sudden change in a chemical property of the solution.
02

Explain the Principle of Titration

In a titration experiment, the key principle is the stoichiometry of the reaction between the two solutions. The stoichiometric coefficients of the reactants determine the ratio in which they react and hence, can be used to calculate the unknown concentration of the compound in the solution.
03

Point out the Precision of Titration

Titration experiments are known for their accuracy and precision in measuring the unknown concentration of a compound in a solution. By utilizing a high degree of control in the volume of the titrant added to the unknown solution and a precise method to detect the endpoint, the concentration determined through titration has minimal room for error.
04

Explain the Endpoint Detection in Titration

One of the factors that make a titration experiment effective is the endpoint detection. A successful endpoint detection indicates that the equivalent point has been reached, which is the point where equal amounts of moles of the reactants have reacted in accordance with the stoichiometry principle. Several ways to detect the endpoint include the use of indicator dyes that change color at a specific pH or using electronic devices such as pH meters.
05

Conclude the Effectiveness of Titration in Measuring Concentration

Based on the explanation above, a titration experiment is a good way to measure the unknown concentration of a compound in a solution due to factors such as its principle of stoichiometry, precision in titrant addition, and the effectiveness in detecting the endpoint. These factors work together to enable the titration method to provide accurate and reliable results for determining the concentration of unknown solutions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Indicate the concentration of each ion or molecule present in the following solutions: (a) \(0.25 \mathrm{M} \mathrm{NaNO}_{3}\), (b) \(1.3 \times 10^{-2} \mathrm{M} \mathrm{MgSO}_{4},(\mathrm{c}) 0.0150 \mathrm{M} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\), (d) a mixture of \(45.0 \mathrm{~mL}\) of \(0.272 \mathrm{M} \mathrm{NaCl}\) and \(65.0 \mathrm{~mL}\) of \(0.0247 \mathrm{M}\) \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}\). Assume that the volumes are additive.

Write balanced molecular and net ionic equations for the reactions of (a) manganese with dilute sulfuric acid; (b) chromium with hydrobromic acid; (c) tin with hydrochloric acid; (d) aluminum with formic acid, \(\mathrm{HCOOH}\).

(a) Calculate the molarity of a solution made by dissolving \(0.750\) grams of \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) in enough water to form exactly \(850 \mathrm{~mL}\) of solution. (b) How many moles of \(\mathrm{KMnO}_{4}\) are present in \(250 \mathrm{~mL}\) of a \(0.0475 \mathrm{M}\) solution? (c) How many milliliters of \(11.6 \mathrm{M} \mathrm{HCl}\) solution are needed to obtain \(0.250 \mathrm{~mol}\) of \(\mathrm{HCl}\) ?

(a) Use the following reactions to prepare an activity series for the halogens: $$ \begin{aligned} \mathrm{Br}_{2}(a q)+2 \mathrm{NaI}(a q) & \longrightarrow 2 \mathrm{NaBr}(a q)+\mathrm{I}_{2}(a q) \\ \mathrm{Cl}_{2}(a q)+2 \mathrm{NaBr}(a q) & \longrightarrow 2 \mathrm{NaCl}(a q)+\mathrm{Br}_{2}(a q) \end{aligned} $$ (b) Relate the positions of the halogens in the periodic table with their locations in this activity series. (c) Predict whether a reaction occurs when the following reagents are mixed: \(\mathrm{Cl}_{2}(a q)\) and \(\mathrm{KI}(a q) ; \mathrm{Br}_{2}(a q)\) and \(\mathrm{LiCl}(a q)\).

A sample of \(1.50 \mathrm{~g}\) of lead(II) nitrate is mixed with \(125 \mathrm{~mL}\) of \(0.100 \mathrm{M}\) sodium sulfate solution. (a) Write the chemical equation for the reaction that occurs. (b) Which is the limiting reactant in the reaction? (c) What are the concentrations of all ions that remain in solution after the reaction is complete?
See all solutions

Recommended explanations on Chemistry Textbooks

Organic Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Chemical Reactions

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Nuclear Chemistry

Read Explanation

Chemistry Branches

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.