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Chapter 4: Problem 63

The average adult human male has a total blood volume of \(5.0 \mathrm{~L}\). If the concentration of sodium ion in this average individual is \(0.135 \mathrm{M}\), what is the mass of sodium ion circulating in the blood?

Short Answer

Expert verified
The mass of sodium ions circulating in the blood of an average adult human male is approximately 15.51 grams.

Step by step solution

01

Calculate the moles of sodium ions

First, we need to determine the number of moles of sodium ions in the blood. To do this, we can use the equation: moles of solute = concentration 脳 volume where concentration is given in molarity (M) and volume is given in liters (L). moles of sodium ions = \(0.135\text{ M} \times 5.0\text{ L}\)
02

Calculate the number of moles of sodium ions

Now, we just need to do the math: moles of sodium ions = \(0.135 \times 5.0\) moles of sodium ions = 0.675 moles
03

Convert moles of sodium ions to mass

To convert moles of sodium ions to mass, we'll use the molar mass of sodium (Na), which is 22.99 g/mol. The conversion equation is: mass of sodium ions = moles of sodium ions 脳 molar mass of sodium mass of sodium ions = \(0.675\text{ moles} \times 22.99\frac{\text{g}}{\text{mol}}\)
04

Calculate the mass of sodium ions

Finally, perform the calculation: mass of sodium ions = \(0.675 \times 22.99\) mass of sodium ions = 15.51 g So the mass of sodium ions circulating in the blood of an average adult human male is approximately 15.51 grams.

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Most popular questions from this chapter

A sample of solid \(\mathrm{Ca}(\mathrm{OH})_{2}\) is stirred in water at \(30^{\circ} \mathrm{C}\) until the solution contains as much dissolved \(\mathrm{Ca}(\mathrm{OH})_{2}\) as it can hold. A \(100-\mathrm{mL}\) sample of this solution is withdrawn and titrated with \(5.00 \times 10^{-2} \mathrm{M} \mathrm{HBr}\). It requires \(48.8 \mathrm{~mL}\) of the acid solution for neutralization. What is the molarity of the \(\mathrm{Ca}(\mathrm{OH})_{2}\) solution? What is the solubility of \(\mathrm{Ca}(\mathrm{OH})_{2}\) in water, at \(30^{\circ} \mathrm{C}\), in grams of \(\mathrm{Ca}(\mathrm{OH})_{2}\) per \(100 \mathrm{~mL}\) of solution?

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