/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 Why is it essential to use balan... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 3: Problem 55

Why is it essential to use balanced chemical equations when determining the quantity of a product formed from a given quantity of a reactant?

Short Answer

Expert verified
Using balanced chemical equations is essential when determining the quantity of a product formed from a given quantity of a reactant because it ensures the Law of Conservation of Mass is obeyed and provides stoichiometric coefficients for stoichiometry calculations. These coefficients help in accurately predicting reactant amounts required and product amounts formed, allowing for efficient planning and optimization of chemical reactions while reducing waste.

Step by step solution

01

Balanced Chemical Equations

In a balanced chemical equation, the number of atoms of each element is the same on the reactant side and the product side. This ensures that the Law of Conservation of Mass is followed, meaning the total mass of reactants is equal to the total mass of products. A balanced chemical equation also represents the stoichiometric coefficients, showing the relationship between moles of reactants and products.
02

Stoichiometry

Stoichiometry is the calculation of the quantities of reactants and products in a chemical reaction. It is based on the coefficients of the balanced chemical equation, which provide the molar proportions of the substances involved. These coefficients help us in determining the mass of reactants needed to produce a desired mass of products or to calculate the mass of products formed from a given mass of reactants.
03

Importance of Balanced Chemical Equations

When determining the quantity of a product formed from a given quantity of a reactant, it's essential to use a balanced chemical equation because: 1. It obeys the Law of Conservation of Mass, ensuring that the mass of reactants equals the mass of products. 2. It provides stoichiometric coefficients, which are crucial for carrying out stoichiometry calculations. 3. It helps predict the reactant amounts required to produce a desired quantity of products, as well as the product amounts formed from given quantities of reactant. 4. It allows for efficient planning and optimization of chemical reactions, as well as reducing waste by accurately calculating the required amounts of reactants. By using balanced chemical equations, we ensure the accuracy of our calculations related to chemical reactions and their material quantifications, making it essential for determining the quantity of a product formed from a given quantity of a reactant.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the balanced chemical equations for (a) the complete combustion of acetic acid \(\left(\mathrm{CH}_{3} \mathrm{COOH}\right)\), the main active ingredient in vinegar; (b) the decomposition of solid calcium hydroxide into solid calcium(II) oxide (lime) and water vapor; (c) the combination reaction between nickel metal and chlorine gas.

(a) What is the difference between adding a subscript 2 to the end of the formula for CO to give \(\mathrm{CO}_{2}\) and adding a coefficient in front of the formula to give \(2 \mathrm{CO}\) ? (b) Is the following chemical equation, as written, consistent with the law of conservation of mass? \(3 \mathrm{Mg}(\mathrm{OH})_{2}(s)+2 \mathrm{H}_{3} \mathrm{PO}_{4}(a q) \longrightarrow \mathrm{Mg}_{3}\left(\mathrm{PO}_{4}\right)_{2}(5)+6 \mathrm{H}_{2} \mathrm{O}(l)\) Why or why not?

An organic compound was found to contain only \(\mathrm{C}, \mathrm{H}\), and Cl. When a \(1.50-g\) sample of the compound was completely combusted in air, \(3.52 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) was formed. In a separate experiment the chlorine in a \(1.00-\mathrm{g}\) sample of the compound was converted to \(1.27 \mathrm{~g}\) of \(\mathrm{AgCl}\). Determine the empirical formula of the compound.

Write balanced chemical equations to correspond to each of the following descriptions: (a) Solid calcium carbide, \(\mathrm{CaC}_{2}\), reacts with water to form an aqueous solution of calcium hydroxide and acetylene gas, \(\mathrm{C}_{2} \mathrm{H}_{2}\). (b) When solid potassium chlorate is heated, it decom-

Hydrofluoric acid, \(\mathrm{HF}(a q)\), cannot be stored in glass bottles because compounds called silicates in the glass are attacked by the \(\mathrm{HF}(a q) .\) Sodium silicate \(\left(\mathrm{Na}_{2} \mathrm{SiO}_{3}\right)\), for example, reacts as follows: \(\mathrm{Na}_{2} \mathrm{SiO}_{3}(\mathrm{~s})+8 \mathrm{HF}(a q) \longrightarrow\) $$ \mathrm{H}_{2} \mathrm{SiF}_{6}(a q)+2 \mathrm{NaF}(a q)+3 \mathrm{H}_{2} \mathrm{O}(l) $$ (a) How many moles of \(\mathrm{HF}\) are needed to react with \(0.300 \mathrm{~mol}\) of \(\mathrm{Na}_{2} \mathrm{SiO}_{3} ?\) (b) How many grams of NaF form when \(0.500 \mathrm{~mol}\) of HF reacts with excess \(\mathrm{Na}_{2} \mathrm{SiO}_{3} ?\) (c) How many grams of \(\mathrm{Na}_{2} \mathrm{SiO}_{3}\) can react with \(0.800 \mathrm{~g}\) of HF?
See all solutions

Recommended explanations on Chemistry Textbooks

Kinetics

Read Explanation

Physical Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Chemical Reactions

Read Explanation

Inorganic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.