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The molecular formula of allicin, the compound responsible for the characteristic smell of garlic, is \(\overline{\mathrm{C}}_{6} \mathrm{H}_{10} \mathrm{OS}_{2}\) (a) What is the molar mass of allicin? (b) How many moles of allicin are present in \(5.00 \mathrm{mg}\) of this substance? (c) How many molecules of allicin are in \(5.00 \mathrm{mg}\) of this substance? (d) How many \(\mathrm{S}\) atoms are present in \(5.00 \mathrm{mg}\) of allicin?

Short Answer

Expert verified
(a) The molar mass of allicin is 162.26 g/mol. (b) There are \(3.08 \times 10^{-5}\) moles of allicin in a 5 mg sample. (c) There are \(1.85 \times 10^{19}\) molecules of allicin in a 5 mg sample. (d) There are \(3.70 \times 10^{19}\) sulfur atoms in a 5 mg sample of allicin.

Step by step solution

01

We need to find the molar mass of allicin, with molecular formula C6H10OS2. To do this, we will first find the molar mass of each element (taking values from the periodic table) and then multiply by the number of atoms of each element: Molar_mass_of_allicin = (6 × molar_mass_of_C) + (10 × molar_mass_of_H)+(1 × molar_mass_of_O) + (2 × molar_mass_of_S) Molar_mass_of_C = 12.01 g/mol Molar_mass_of_H = 1.01 g/mol Molar_mass_of_O = 16.00 g/mol Molar_mass_of_S = 32.07 g/mol Complete the calculation: Molar_mass_of_allicin= (6 × 12.01 g/mol) + (10 × 1.01 g/mol) + (1 × 16.00 g/mol) + (2 × 32.07 g/mol) = 162.26 g/mol (a) The molar mass of allicin is 162.26 g/mol. #Step 2: Calculate the number of moles of allicin in a 5 mg sample#

To find the number of moles of allicin, we will divide the mass of the allicin sample (5 mg) by the molar mass of allicin: Number_of_moles = mass_of_sample / Molar_mass_of_allicin Convert 5.00 mg to grams (1 mg = 0.001 g): 5.00 mg = 5.00 × 0.001 g = 0.005 g Complete the calculation: Number_of_moles = 0.005 g / 162.26 g/mol = 3.08 × 10^(-5) mol (b) There are 3.08 × 10^(-5) moles of allicin in a 5 mg sample. #Step 3: Calculate the number of allicin molecules in a 5 mg sample#
02

Now, to find the number of allicin molecules, we will multiply the number of moles by Avogadro's number (approximately 6.022 × 10^23/mol): Number_of_molecules = Number_of_moles × Avogadro's_number Complete the calculation: Number_of_molecules = 3.08 × 10^(-5) mol × 6.022 × 10^23/mol = 1.85 × 10^(19) molecules (c) There are 1.85 × 10^(19) molecules of allicin in a 5 mg sample. #Step 4: Calculate the number of sulfur atoms in a 5 mg sample of allicin#

Remember that in the molecular formula of allicin, there are two sulfur atoms. To find the total number of sulfur atoms present in a 5 mg sample of allicin, we can simply multiply the number of allicin molecules by the number of sulfur atoms per molecule: Number_of_S_atoms = Number_of_molecules × 2 Complete the calculation: Number_of_S_atoms = 1.85 × 10^19 × 2 = 3.70 × 10^19 S atoms (d) There are 3.70 × 10^19 sulfur atoms in a 5 mg sample of allicin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Formula
Understanding the molecular formula of a compound gives insight into the types and numbers of atoms that make up a molecule. For allicin, the molecular formula is \( \mathrm{C}_6 \mathrm{H}_{10} \mathrm{OS}_2 \). This formula tells us that one molecule of allicin contains six carbon (C) atoms, ten hydrogen (H) atoms, one oxygen (O) atom, and two sulfur (S) atoms.
The molecular formula is not only a representation of the molecule's composition but also essential in determining other properties, such as its molar mass.
The molar mass is calculated by adding the atomic masses of all atoms present in the molecular formula. Here, you can use the atomic masses found in the periodic table, which are measured in grams per mole (g/mol).
  • For carbon (C): Mass = 12.01 g/mol.
  • For hydrogen (H): Mass = 1.01 g/mol.
  • For oxygen (O): Mass = 16.00 g/mol.
  • For sulfur (S): Mass = 32.07 g/mol.
To find the molar mass of allicin, you multiply these atomic masses by their respective number of atoms in the formula, and sum them up. Performing this operation gives the molar mass, which, for allicin, calculates to 162.26 g/mol.
Avogadro's Number
Avogadro’s number is a cornerstone concept in chemistry, simplifying the understanding of relationships between atoms, molecules, and moles. The number is defined as \(6.022 \times 10^{23}\), a remarkably large constant that conveys the amount of atoms or molecules in a mole.
Utilizing Avogadro's number allows chemists to bridge the gap between the microscopic scale (atoms and molecules) and reality in lab practice with tangible masses and volumes.
For instance, in calculating the number of molecules in a sample, such as our 5 mg of allicin, once the number of moles is ascertained (let's say it was calculated to be \(3.08 \times 10^{-5} \text{ mol}\)) via formulae shown above, multiplying this by Avogadro's number gives the number of molecules within that sample:
  • Total molecules of allicin = \(3.08 \times 10^{-5} \text{ mol} \times 6.022 \times 10^{23}\text{ molecules/mol}\)
This calculation allows us to understand chemical quantities more precisely and aligns with stoichiometry in reaction mechanisms and product yields in laboratory or industrial practices.
Chemical Calculations
Chemical calculations allow us to determine various chemical properties and predict outcomes in chemical processes. These calculations are founded on basic principles such as the conservation of mass and use of a standard unit of measurement called the mole.
In this particular exercise with allicin, chemical calculations were employed to:
  • Determine allicin's molar mass using its molecular formula, which is crucial for converting between grams and moles.
  • Convert milligrams to grams, since using a consistent unit throughout calculations ensures accuracy (5 mg converts to 0.005 g).
  • Calculate the number of moles in a given mass by dividing the mass of the sample by the molar mass. This step unravels the sample's stoichiometric potential.
  • Determine molecular population via calculation of the number of molecules using Avogadro's number. This bridges mass-based measurement to particle count.
  • Quantify element-specific atom counts in a substance—like sulfur atoms—in terms of molecular formula specifics (as two sulfur atoms per allicin molecule implies two per entire molecular count).
These calculations empower chemists to plan experiments, balance equations, and predict how substances will react, making chemistry a quantifiable and predictive science.

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Most popular questions from this chapter

The source of oxygen that drives the internal combustion engine in an automobile is air. Air is a mixture of gases, which are principally \(\mathrm{N}_{2}(\sim 79 \%)\) and \(\mathrm{O}_{2}(\sim 20 \%)\). In the cylinder of an automobile engine, nitrogen can react with oxygen to produce nitric oxide gas, NO. As NO is emitted from the tailpipe of the car, it can react with more oxygen to produce nitrogen dioxide gas. (a) Write balanced chemical equations for both reactions. (b) Both nitric oxide and nitrogen dioxide are pollutants that can lead to acid rain and global warming; collectively, they are called "NOx" gases. In 2004, the United States emitted an estimated 19 million tons of nitrogen dioxide into the atmosphere. How many grams of nitrogen dioxide is this? (c) The production of \(\mathrm{NO}_{\mathrm{x}}\) gases is an unwanted side reaction of the main engine combustion process that turns octane, \(\mathrm{C}_{8} \mathrm{H}_{18}\) into \(\mathrm{CO}_{2}\) and water. If \(85 \%\) of the oxygen in an engine is used to combust octane, and the remainder used to produce nitrogen dioxide, calculate how many grams of nitrogen dioxide would be produced during the combustion of 500 grams of octane.

(a) You are given a cube of silver metal that measures \(1.000 \mathrm{~cm}\) on each edge. The density of silver is \(10.5\) \(\mathrm{g} / \mathrm{cm}^{3}\). How many atoms are in this cube? (b) Because atoms are spherical, they cannot occupy all of the space of the cube. The silver atoms pack in the solid in such a way that \(74 \%\) of the volume of the solid is actually filled with the silver atoms. Calculate the volume of a single silver atom. (c) Using the volume of a silver atom and the formula for the volume of a sphere, calculate the radius in angstroms of a silver atom.

(a). What is Avogadro's number, and how is it related to the mole? (b) What is the relationship between the formula weight of a substance and its molar mass?

A particular coal contains \(2.5 \%\) sulfur by mass. When this coal is burned at a power plant, the sulfur is con- verted into sulfur dioxide gas, which is a pollutant. To reduce sulfur dioxide emissions, calcium oxide (lime) is used. The sulfur dioxide reacts with calcium oxide to form solid calcium sulfite. (a) Write the balanced chemical equation for the reaction. (b) If the coal is burned in a power plant that uses 2000 tons of coal per day, what mass of calcium oxide is required daily to eliminate the sulfur dioxide? (c) How many grams of calcium sulfite are produced daily by this power plant?

Several brands of antacids use \(\mathrm{Al}(\mathrm{OH})_{3}\) to react with stomach acid, which contains primarily \(\mathrm{HCl}\) $$ \mathrm{Al}(\mathrm{OH})_{3}(s)+\mathrm{HCl}(a q) \longrightarrow \mathrm{AlCl}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l) $$ (a) Balance this equation. (b) Calculate the number of grams of \(\mathrm{HCl}\) that can react with \(0.500 \mathrm{~g}\) of \(\mathrm{Al}(\mathrm{OH})_{3}\) (c) Calculate the number of grams of \(\mathrm{AlCl}_{3}\) and the number of grams of \(\mathrm{H}_{2} \mathrm{O}\) formed when \(0.500 \mathrm{~g}\) of \(\mathrm{Al}(\mathrm{OH})_{3}\) reacts. (d) Show that your calculations in parts (b) and (c) are consistent with the law of conservation of mass.

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