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Chapter 25: Problem 54

Does 3-chloro-3-methylhexane have optical isomers? Why or why not?

Short Answer

Expert verified
Yes, 3-chloro-3-methylhexane has optical isomers because it has a chiral center at the third carbon atom, which is connected to four different groups: chlorine, a methyl group, a hydrogen, and the rest of the hexane chain. Having a chiral center allows the molecule to exhibit chirality and subsequently have optical isomers that can rotate plane-polarized light.

Step by step solution

01

Identify the structure of 3-chloro-3-methylhexane

First, let's draw the structure of the molecule. We have a hexane chain, with a chlorine and a methyl group on the third carbon: Cl | H3C 鈥� C 鈥� H | H3C 鈥� C 鈥� C 鈥� C 鈥� C 鈥� C 鈥� H | H
02

Analyze the methyl group

Now, let's focus on the third carbon, which has a chlorine, a methyl group, a hydrogen, and is connected to the rest of the hexane chain. It seems that this carbon is connected to four different groups: 1. Chlorine 2. Methyl group (CH3) 3. Hydrogen 4. The rest of the hexane chain
03

Determine if the third carbon is a chiral center

The carbon atom is connected to four different groups, so we can conclude that this carbon atom is a chiral center.
04

Determine if 3-chloro-3-methylhexane has optical isomers

Since 3-chloro-3-methylhexane has a chiral center (third carbon atom), it can have optical isomers. Optical isomers are stereoisomers that exhibit chirality and therefore are able to rotate plane-polarized light. In conclusion, 3-chloro-3-methylhexane does have optical isomers because it has a chiral center at the third carbon atom.

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Most popular questions from this chapter

Aldehydes and ketones can be named in a systematic way by counting the number of carbon atoms (including the carbonyl carbon) that they contain. The name of the aldehyde or ketone is based on the hydrocarbon with the same number of carbon atoms. The ending \(-a l\) for aldehyde or -one for ketone is added as appropriate. Draw the structural formulas for the following aldehydes or ketones: (a) propanal, (b) 2 -pentanone, (c) 3methyl-2-butanone, (d) 2-methylbutanal.

If a molecule is an "ene-one," what functional groups must it have?

Indicate whether each of the following molecules is capable of geometrical (cis-trans) isomerism. For those that are, draw the structures: (a) \(1,1-\) dichloro1-butene, (b) 2,4 -dichloro-2-butene, (c) 1,4 -dichlorobenzene, (d) 4,5 -dimethyl-2 -pentyne.

Enediynes are a class of compounds that include some antibiotic drugs. Draw the structure of an "enediyne" fragment that contains six carbons in a row. (Hint: "di" means "two".)

Write the condensed structural formula for each of the following compounds: (a) 3,3-dichlorobutyraldehyde, (b) methyl phenyl ketone, (c) para-bromoben zoic acid, (d) methyl-trans-2-butenyl ether, (e) \(N, N\) -dimethylbenzamide.
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