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The \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) ion has an absorption maximum at about \(725 \mathrm{~nm}\), whereas the \(\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) ion absorbs at about \(570 \mathrm{~nm} .\) Predict the color of each ion. (b) The \(\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}\) ion absorption maximum occurs at about \(545 \mathrm{~nm}\), and that of the [Ni(bipy) \(\left._{3}\right]^{2+}\) ion occurs at about \(520 \mathrm{~nm}\). From these data, indicate the relative strengths of the ligand fields created by the four ligands involved.

Short Answer

Expert verified
The predicted colors of the ions are: \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\): Green and \(\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\): Violet. The order of ligand field strength for the involved ligands is: bipy > en > \(\mathrm{NH}_{3}\) > \(\mathrm{H}_{2} \mathrm{O}\).

Step by step solution

01

Determine the absorbed colors from given wavelengths

To predict the color of the complexes, we must first find which color each complex absorbs from the visible spectrum. Visible light ranges from approximately 400nm (violet) to 700nm (red). The absorbed color corresponds to the energy of absorbed photons, and the complex will appear to be the complementary color on the color wheel. Recall that for the given complexes, the absorption maxima are: - \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) at \(725 \mathrm{~nm}\) - \(\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) at \(570 \mathrm{~nm}\) - \(\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}\) at \(545 \mathrm{~nm}\) - \(\left[\mathrm{Ni}(\mathrm{bipy})_{3}\right]^{2+}\) at \(520 \mathrm{~nm}\)
02

Determine the complementary colors

Now we need to find the complementary colors of the absorbed colors using a color wheel. The complementary color will be the color directly opposite to the absorbed color on the wheel. For the given complexes, we have: - \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\): Absorbs red light (725nm) -> Complementary color: Green - \(\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\): Absorbs yellow-green light (570nm) -> Complementary color: Violet So, the predicted colors of these ions are: - \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\): Green - \(\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\): Violet
03

Determine the relative strengths of the ligand fields

We can compare the absorption maxima of the given complexes to determine the relative strengths of the ligand fields. A higher absorption maximum corresponds to a stronger ligand field, as it requires more energy to be absorbed. Order of ligand field strength (strongest to weakest) based on the given absorption maxima: 1. \(\left[\mathrm{Ni}(\mathrm{bipy})_{3}\right]^{2+}\) at \(520 \mathrm{~nm}\) 2. \(\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}\) at \(545 \mathrm{~nm}\) 3. \(\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) at \(570 \mathrm{~nm}\) 4. \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) at \(725 \mathrm{~nm}\) So, the order of ligand field strength for the involved ligands is: bipy > en > \(\mathrm{NH}_{3}\) > \(\mathrm{H}_{2} \mathrm{O}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Color Absorption
When light interacts with a chemical compound, certain wavelengths are absorbed, leading to the color we perceive. In complex ions, this absorption is primarily due to the interaction between light and the electronic structure of the metal and its ligands.
The specific wavelengths absorbed by a complex ion are key to understanding its color because an ion absorbs certain parts of the visible light spectrum.
The visible spectrum ranges from about 400 nm to 700 nm, covering colors from violet to red. Each complex has a characteristic absorption maximum, determining which color it absorbs from the visible spectrum.
For instance, the complex ion \([\mathrm{Ni}(\mathrm{H}_{2}\mathrm{O})_{6}]^{2+}\) absorbs light at about 725 nm, corresponding to the red part of the spectrum. As a result, the ion appears green, which is the complementary color of red. This principle applies to other complex ions as well, e.g., \([\mathrm{Ni}(\mathrm{NH}_{3})_{6}]^{2+}\) absorbs yellow-green light, making it appear violet.
Understanding this absorption process helps in predicting the observed color of complex ions based on their absorption spectrum.
Visible Spectrum
The visible spectrum consists of all the light that human eyes can perceive, with wavelengths from about 400 nm (violet) to 700 nm (red). Each color in this spectrum corresponds to a specific wavelength.
When a complex ion absorbs certain wavelengths, it will often appear as the complementary color on the color wheel. This wheel is a circular arrangement of colors, where opposite colors complement each other.
For example:
  • Red (around 700-640 nm) has a complementary color of green.
  • Yellow-green (around 570 nm) is complemented by violet.
In complex chemistry, using the color wheel and the knowledge of the visible spectrum allows us to predict the observed colors of complex ions by knowing the specific wavelengths they absorb.
This makes the visible spectrum a powerful tool in determining how different complexes will appear to the naked eye.
Ligand Strength
Ligand field strength indicates how much a ligand can influence the electronic environment of a metal center in a complex.
Stronger ligands create a greater energy difference between the electronic states of the metal ions, which impacts the absorption of light.
The relative strength of ligands in a complex can be compared using their absorption maxima. A lower absorption wavelength corresponds to a higher ligand field strength because more energy is needed for electronic transitions.
In our example:
  • \([\mathrm{Ni}(\mathrm{bipy})_{3}]^{2+}\) has the strongest field at 520 nm.
  • \([\mathrm{Ni}(\mathrm{en})_{3}]^{2+}\) follows closely with 545 nm.
  • \([\mathrm{Ni}(\mathrm{NH}_{3})_{6}]^{2+}\) is next at 570 nm.
  • \([\mathrm{Ni}(\mathrm{H}_{2}\mathrm{O})_{6}]^{2+}\) has the weakest field at 725 nm.
Understanding ligand strength helps predict the behavior of complexes under different conditions, such as their color and reactivity.
Complex Ions
Complex ions are formed when a central metal ion is surrounded by molecules or ions known as ligands. These ligands are bound to the central metal through coordinate covalent bonds.
The structure and properties of these complex ions are determined by several factors including the type of metal, the nature of the ligands, and the spatial arrangement of the ligands around the metal.
Each complex ion can exhibit unique properties, such as particular colors or reactivity due to the distribution of electrons between the metal and the ligands.
Utilizing Ligand Field Theory, we can understand how these electronic interactions occur, which in turn helps predict the absorption characteristics and colors of the complex ions. For instance, the nature of the ligand can cause changes in the electronic states of the metal center, leading to differences in the energy of absorbed light."
Complex ions show the diversity of coordination chemistry and how variations in ligands and structure lead to a wide range of observed properties.

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Most popular questions from this chapter

Suppose that a transition-metal ion was in a lattice in which it was in contact with just two nearby anions, located on opposite sides of the metal. Diagram the splitting of the metal \(d\) orbitals that would result from such a crystal field. Assuming a strong field, how many unpaired electrons would you expect for a metal ion with six \(d\) electrons? (Hint: Consider the linear axis to be the z-axis).

A manganese complex formed from a solution containing potassium bromide and oxalate ion is purified and analyzed. It contains \(10.0 \% \mathrm{Mn}, 28.6 \%\) potassium, \(8.8 \%\) carbon, and \(29.2 \%\) bromine by mass. The remainder of the compound is oxygen. An aqueous solution of the complex has about the same electrical conductivity as an equimolar solution of \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\). Write the formula of the compound, using brackets to denote the manganese and its coordination sphere.

In 2001, chemists at SUNY-Stony Brook succeeded in synthesizing the complex trans-[Fe(CN) \(\left._{4}(\mathrm{CO})_{2}\right]^{2-}\), which could be a model of complexes that may have played a role in the origin of life. (a) Sketch the structure of the complex. (b) The complex is isolated as a sodium salt. Write the complete name of this salt. (c) What is the oxidation state of Fe in this complex? How many d electrons are associated with the \(\mathrm{Fe}\) in this complex? (d) Would you expect this complex to be high spin or low spin? Explain.

The total concentration of \(\mathrm{Ca}^{2+}\) and \(\mathrm{Mg}^{2+}\) in a sample of hard water was determined by titrating a 0.100-L sample of the water with a solution of EDTA \(^{4-}\). The EDTA \(^{4-}\) chelates the two cations: $$ \begin{array}{r} \mathrm{Mg}^{2+}+[\mathrm{EDTA}]^{4-}--\rightarrow[\mathrm{Mg}(\mathrm{EDTA})]^{2-} \\\ \mathrm{Ca}^{2+}+[\mathrm{EDTA}]^{4-}--\rightarrow[\mathrm{Ca}(\mathrm{EDTA})]^{2-} \end{array} $$ It requires \(31.5 \mathrm{~mL}\) of \(0.0104 M[\mathrm{EDTA}]^{4-}\) solution to reach the end point in the titration. A second \(0.100-\mathrm{L}\) sample was then treated with sulfate ion to precipitate \(\mathrm{Ca}^{2+}\) as calcium sulfate. The \(\mathrm{Mg}^{2+}\) was then titrated with \(18.7 \mathrm{~mL}\) of \(0.0104 M[\mathrm{EDTA}]^{4-} .\) Calculate the concentrations of \(\mathrm{Mg}^{2+}\) and \(\mathrm{Ca}^{2+}\) in the hard water in \(\mathrm{mg} / \mathrm{L}\).

Pyridine \(\left(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~N}\right)\), abbreviated py, is the following molecule: (a) Why is pyridine referred to as a monodentate ligand? (b) Consider the following equilibrium reaction: \(\left[\mathrm{Ru}(\mathrm{py})_{4}(\mathrm{bipy})\right]^{2+}+2 \mathrm{py} \rightleftharpoons\left[\mathrm{Ru}(\mathrm{py})_{6}\right]^{2+}+\) bipy What would you predict for themagnitude of the equilibrium constant for this equilibrium? Explain the basis for your answer.

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