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Write a balanced net ionic equation for each of the following reactions: (a) Dilute nitric acid reacts with zinc metal with formation of nitrous oxide. (b) Concentrated nitric acid reacts with sulfur with formation of nitrogen dioxide. (c) Concentrated nitric acid oxidizes sulfur dioxide with formation of nitric oxide. (d) Hydrazine is burned in excess fluorine gas, forming \(\mathrm{NF}_{3}\). (e) \(\mathrm{Hy}\) drazine reduces \(\mathrm{CrO}_{4}{ }^{2-}\) to \(\mathrm{Cr}(\mathrm{OH})_{4}^{-}\) in base (hydrazine is oxidized to \(\mathrm{N}_{2}\) ).

Short Answer

Expert verified
The balanced net ionic equations for each reaction are: a) Zn (s) + 2H鈦 (aq) 鈫 Zn虏鈦 (aq) + N鈧侽 (g) + H鈧侽 (l) b) S (s) + 6H鈦 (aq) + 6NO鈧冣伝 (aq) 鈫 SO鈧劼测伝 (aq) + 6H鈧侽 (l) + 6NO鈧 (g) c) SO鈧 (g) + 2H鈦 (aq) + 2NO鈧冣伝 (aq) 鈫 SO鈧劼测伝 (aq) + H鈧侽 (l) + 2NO (g) d) N鈧侶鈧 (g) + 3F鈧 (g) 鈫 2NF鈧 (g) e) N鈧侶鈧 (aq) + CrO鈧劼测伝 (aq) + 4OH鈦 (aq) 鈫 N鈧 (g) + 2H鈧侽 (l) + Cr(OH)鈧勨伝 (aq)

Step by step solution

01

a) Dilute nitric acid with zinc and nitrous oxide formation

1. Write the reactants and products in their ionic forms: Zn (s) + 2HNO鈧 (aq) 鈫 Zn(NO鈧)鈧 (aq) + N鈧侽 (g) + H鈧侽 (l) 2. Balance the overall equation: Zn (s) + 2HNO鈧 (aq) 鈫 Zn(NO鈧)鈧 (aq) + N鈧侽 (g) + H鈧侽 (l) 3. Write the net ionic equation by removing spectator ions: Zn (s) + 2H鈦 (aq) + NO鈧冣伝 (aq) 鈫 Zn鈦郝 (aq) + NO鈧冣伝 (aq) + N鈧侽 (g) + H鈧侽 (l) 4. Simplify the net ionic equation: Zn (s) + 2H鈦 (aq) 鈫 Zn虏鈦 (aq) + N鈧侽 (g) + H鈧侽 (l)
02

b) Concentrated nitric acid with sulfur and nitrogen dioxide formation

1. Write the reactants and products in their ionic forms: 6HNO鈧 (aq) + S (s) 鈫 H鈧係O鈧 (aq) + 6H鈧侽 (l) + 6NO鈧 (g) 2. Balance the overall equation: 6HNO鈧 (aq) + S (s) 鈫 H鈧係O鈧 (aq) + 6H鈧侽 (l) + 6NO鈧 (g) 3. Write the net ionic equation by removing spectator ions: 6H鈦 (aq) + 6NO鈧冣伝 (aq) + S (s) 鈫 2H鈦 (aq) + SO鈧劼测伝 (aq) + 6H鈧侽 (l) + 6NO鈧 (g) 4. Simplify the net ionic equation: S (s) + 6H鈦 (aq) + 6NO鈧冣伝 (aq) 鈫 SO鈧劼测伝 (aq) + 6H鈧侽 (l) + 6NO鈧 (g)
03

c) Concentrated nitric acid oxidizes sulfur dioxide with nitric oxide formation

1. Write the reactants and products in their ionic forms: 2HNO鈧 (aq) + SO鈧 (g) 鈫 H鈧侽 (l) + SO鈧劼测伝 (aq) + 2NO (g) 2. Balance the overall equation: 2HNO鈧 (aq) + SO鈧 (g) 鈫 H鈧侽 (l) + SO鈧劼测伝 (aq) + 2NO (g) 3. Write the net ionic equation by removing spectator ions: 2H鈦 (aq) + 2NO鈧冣伝 (aq) + SO鈧 (g) 鈫 H鈧侽 (l) + SO鈧劼测伝 (aq) + 2NO (g) 4. Simplify the net ionic equation: SO鈧 (g) + 2H鈦 (aq) + 2NO鈧冣伝 (aq) 鈫 SO鈧劼测伝 (aq) + H鈧侽 (l) + 2NO (g)
04

d) Hydrazine burned in excess fluorine gas forming NF鈧

1. Write the reactants and products in their ionic forms: N鈧侶鈧 (g) + 3F鈧 (g) 鈫 2NF鈧 (g) 2. Balance the overall equation: N鈧侶鈧 (g) + 3F鈧 (g) 鈫 2NF鈧 (g) 3. No ions are involved in this reaction, so the net ionic equation is the same as the balanced overall equation: N鈧侶鈧 (g) + 3F鈧 (g) 鈫 2NF鈧 (g)
05

e) Hydrazine reduces CrO鈧劼测伝 to Cr(OH)鈧勨伝 in base, with hydrazine oxidized to N鈧

1. Write the reactants and products in their ionic forms: N鈧侶鈧 (aq) + CrO鈧劼测伝 (aq) + 4OH鈦 (aq) 鈫 N鈧 (g) + 2H鈧侽 (l) + Cr(OH)鈧勨伝 (aq) 2. Balance the overall equation: N鈧侶鈧 (aq) + CrO鈧劼测伝 (aq) + 4OH鈦 (aq) 鈫 N鈧 (g) + 2H鈧侽 (l) + Cr(OH)鈧勨伝 (aq) 3. Write the net ionic equation by removing spectator ions (none in this case, as all ions are involved in the reaction): N鈧侶鈧 (aq) + CrO鈧劼测伝 (aq) + 4OH鈦 (aq) 鈫 N鈧 (g) + 2H鈧侽 (l) + Cr(OH)鈧勨伝 (aq) 4. Simplify the net ionic equation (no simplification necessary as all ions are involved in the reaction): N鈧侶鈧 (aq) + CrO鈧劼测伝 (aq) + 4OH鈦 (aq) 鈫 N鈧 (g) + 2H鈧侽 (l) + Cr(OH)鈧勨伝 (aq)

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