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How many hydrogen atoms are in each of the following: (a) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), (b) \(\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}\) (c) \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4} ?\)

Short Answer

Expert verified
In the given chemical formulas, we have: (a) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) has 6 hydrogen atoms, (b) \(\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}\) has 6 hydrogen atoms, and (c) \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\) has 12 hydrogen atoms.

Step by step solution

01

(a) Counting hydrogen atoms in \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\)

In this chemical formula, there are two types of hydrogen atoms. The first type is the \(\mathrm{H}_{5}\) atoms, which means there are 5 hydrogen atoms present. The second type is the \(\mathrm{OH}\) group, which contains a single hydrogen atom. In total, there are 5 + 1 = 6 hydrogen atoms in this molecule.
02

(b) Counting hydrogen atoms in \(\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}\)

In this chemical formula, we have the calcium ion (\(\mathrm{Ca}^{2+}\)) bonded with the acetate anion (\(\mathrm{CH}_{3} \mathrm{COO}^-\)) twice. Inside the \(\mathrm{CH}_{3} \mathrm{COO}\) group, we have the \(\mathrm{CH}_{3}\) part with 3 hydrogen atoms, and the \(\mathrm{COO}\) part does not have any hydrogen atoms. In total, we have 2 acetate anions, so we have 2 * 3 = 6 hydrogen atoms in this molecule.
03

(c) Counting hydrogen atoms in \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\)

In this chemical formula, we have the ammonium ion (\(\mathrm{NH}_{4}^+\)) bonded with the phosphate anion (\(\mathrm{PO}_{4}^{3-}\)). There are 3 ammonium ions present in this molecule. Each ammonium ion has 4 hydrogen atoms. In total, there are 3 * 4 = 12 hydrogen atoms in this molecule.

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