/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 (a) What is the common-ion effec... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) What is the common-ion effect? (b) Give an example of a salt that can decrease the ionization of \(\mathrm{HNO}_{2}\) in solution.

Short Answer

Expert verified
(a) The common-ion effect is the suppression of the ionization of a weak electrolyte by the presence of a common ion from a strong electrolyte in the solution. This effect occurs because adding a common ion shifts the equilibrium of the weak electrolyte's ionization reaction backward, decreasing its ionization. (b) An example of a salt that can decrease the ionization of \(\mathrm{HNO}_{2}\) is \(\mathrm{KNO}_{2}\) (potassium nitrite). This salt introduces the common ion \(\mathrm{NO}_{2}^{-}\) into the solution, suppressing the ionization of \(\mathrm{HNO}_{2}\).

Step by step solution

01

Define the common-ion effect

The common-ion effect is the suppression of the ionization of a weak electrolyte, such as a weak acid or a weak base, by the presence of a common ion from a strong electrolyte in the solution. This effect occurs because adding a common ion shifts the equilibrium of the weak electrolyte's ionization reaction backward, decreasing the ionization of the weak electrolyte.
02

Consider the ionization of \(\mathrm{HNO}_{2}\)

The ionization reaction for \(\mathrm{HNO}_{2}\) in water is given by: \[\mathrm{HNO}_{2} \rightleftharpoons \mathrm{H}^{+} + \mathrm{NO}_{2}^{-}\] Here, \(\mathrm{HNO}_{2}\) is a weak acid and does not ionize completely, meaning that the equilibrium lies to the left. We're looking for a salt that can decrease the ionization of \(\mathrm{HNO}_{2}\) by introducing a common ion into the solution.
03

Choose a salt that introduces the common ion

In order to suppress the ionization of \(\mathrm{HNO}_{2}\), we need to choose a salt that has a common ion with the ionization reaction of \(\mathrm{HNO}_{2}\). The ions present in the reaction are \(\mathrm{H}^{+}\) and \(\mathrm{NO}_{2}^{-}\). A salt that contains either of these ions will decrease the ionization of \(\mathrm{HNO}_{2}\). A good option for this purpose is \(\mathrm{KNO}_{2}\) (potassium nitrite), which dissociates in water as \(\mathrm{KNO}_{2} \rightarrow \mathrm{K}^{+} + \mathrm{NO}_{2}^{-}\). The common ion with \(\mathrm{HNO}_{2}\) ionization is \(\mathrm{NO}_{2}^{-}\). So, the example of a salt that can decrease the ionization of \(\mathrm{HNO}_{2}\) is \(\mathrm{KNO}_{2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Predict whether the equivalence point of each of the following titrations is below, above, or at \(\mathrm{pH} 7\) : (a) formic acid titrated with \(\mathrm{NaOH}\), (b) calcium hydroxide titrated with perchloric acid, (c) pyridine titrated with nitric acid.

Calculate the molar solubility of \(\mathrm{Fe}(\mathrm{OH})_{2}\) when buffered at \(\mathrm{pH}(\mathrm{a}) 8.0\), (b) \(10.0,(\mathrm{c}) 12.0 .\)

Consider the titration of \(30.0 \mathrm{~mL}\) of \(0.030 \mathrm{M} \mathrm{NH}_{3}\) with \(0.025 \mathrm{M} \mathrm{HCl}\). Calculate the \(\mathrm{pH}\) after the following volumes of titrant have been added: (a) \(0 \mathrm{~mL}\), (b) \(10.0 \mathrm{~mL}_{\text {, }}\) (c) \(20.0 \mathrm{~mL}\), (d) \(35.0 \mathrm{~mL}\), (e) \(36.0 \mathrm{~mL}\), (f) \(37.0 \mathrm{~mL}\).

A hypothetical weak acid, HA, was combined with \(\mathrm{NaOH}\) in the following proportions: \(0.20 \mathrm{~mol}\) of \(\mathrm{HA}\), \(0.080 \mathrm{~mol}\) of \(\mathrm{NaOH}\). The mixture was diluted to a total volume of \(1.0 \mathrm{~L}\), and the pH measured. (a) If \(\mathrm{pH}=4.80\), what is the \(\mathrm{p} K_{a}\) of the acid? (b) How many additional moles of \(\mathrm{NaOH}\) should be added to the solution to increase the \(\mathrm{pH}\) to \(5.00 ?\)

Fluoridation of drinking water is employed in many places to aid in the prevention of dental caries. Typically the \(\mathrm{F}^{-}\) ion concentration is adjusted to about \(1 \mathrm{ppb}\). Some water supplies are also "hard"; that is, they contain certain cations such as \(\mathrm{Ca}^{2+}\) that interfere with the action of soap. Consider a case where the concentration of \(\mathrm{Ca}^{2+}\) is 8 ppb. Could a precipitate of \(\mathrm{CaF}_{2}\) form under these conditions? (Make any necessary approximations.)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.