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What is the \(\mathrm{pH}\) at \(25^{\circ} \mathrm{C}\) of water saturated with \(\mathrm{CO}_{2}\) at a partial pressure of \(1.10 \mathrm{~atm}\) ? The Henry's law constant for \(\mathrm{CO}_{2}\) at \(25^{\circ} \mathrm{C}\) is \(3.1 \times 10^{-2} \mathrm{~mol} / \mathrm{L}-\mathrm{atm}\). The \(\mathrm{CO}_{2}\) is an acidic oxide, reacting with \(\mathrm{H}_{2} \mathrm{O}\) to form \(\mathrm{H}_{2} \mathrm{CO}_{3}\).

Short Answer

Expert verified
The pH of water saturated with CO鈧 at 25掳C and at a partial pressure of 1.10 atm is approximately 4.42.

Step by step solution

01

Calculate the concentration of CO鈧 dissolved in water using Henry's law

The concentration (C) of CO鈧 can be determined using Henry's law, which can be expressed as: C = k 脳 P where C is the concentration of the gas in mol/L, k is Henry's law constant, given as \(3.1 脳 10^{-2} \mathrm{~mol} / \mathrm{L}-\mathrm{atm}\), P is the partial pressure of CO鈧, given as 1.10 atm. C = \(3.1 脳 10^{-2} \mathrm{~mol} / \mathrm{L}-\mathrm{atm}\) 脳 1.10 atm C = \(3.41 脳 10^{-2} \mathrm{~mol}/\mathrm{L}\)
02

Write the balanced chemical equation for the reaction between CO鈧 and H鈧侽 to form H鈧侰O鈧

The balanced chemical equation is: CO鈧 (aq) + H鈧侽 (l) 鈬 H鈧侰O鈧 (aq)
03

Determine the concentration of H鈧侰O鈧

The reaction between CO鈧 and H鈧侽 to form H鈧侰O鈧 is in equilibrium, as shown by the double-headed arrow in the balanced chemical equation. This means that the concentration of H鈧侰O鈧 is equal to the concentration of dissolved CO鈧. [H鈧侰O鈧僝 = \(3.41 脳 10^{-2} \mathrm{~mol}/\mathrm{L}\)
04

Identify the ionization of H鈧侰O鈧 to form H鈧僌鈦 and equilibrium constants

H鈧侰O鈧 is a weak acid and will ionize in water to form H鈧僌鈦 and HCO鈧冣伝 ions. The ionization equation is: H鈧侰O鈧 (aq) + H鈧侽 (l) 鈬 HCO鈧冣伝 (aq) + H鈧僌鈦 (aq) The equilibrium constant for this ionization, Ka1, is: Ka1 = [HCO鈧冣伝][H鈧僌鈦篯/[H鈧侰O鈧僝
05

Set up an equation to determine the concentration of H鈧僌鈦 ions

Let x be the concentration of H鈧僌鈦 ions formed. We can write the equilibrium constant equation as: Ka1 = x虏/(\(3.41 脳 10^{-2}\) - x)
06

Calculate the pH using the concentration of H鈧僌鈦 ions

The value of Ka1 for H鈧侰O鈧 is known to be approximately \(4.3 脳 10^{-7}\). However, we can approximate x as being much smaller compared to the concentration of H鈧侰O鈧. Therefore, the equilibrium constant equation can be simplified as: \(4.3 脳 10^{-7}\) = x虏/(\(3.41 脳 10^{-2}\)) x虏 = (\(4.3 脳 10^{-7}\)) 脳 (\(3.41 脳 10^{-2}\)) x = 鈭(\(1.47 脳 10^{-8}\)) x = \(3.83 脳 10^{-5} \mathrm{~mol}/\mathrm{L}\) (approx) Now, we can find the pH using the concentration of H鈧僌鈦 ions: pH = -log([H鈧僌鈦篯) pH = -log(\(3.83 脳 10^{-5}\)) pH 鈮 4.42 The pH of water saturated with CO鈧 at 25掳C and at a partial pressure of 1.10 atm is approximately 4.42.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Henry's Law
Henry's Law plays a crucial role in calculating the concentration of gases in liquids. It establishes a direct linear relationship between the concentration of a dissolved gas and its partial pressure above the solution. In mathematical terms, Henry's Law is expressed as

\( C = k \times P \)

where \( C \) represents the solute concentration in the solvent (mol/L), \( k \) is the Henry's Law constant specific to each gas and solvent pair, and \( P \) is the partial pressure of the gas (atm). By using this law, we can determine how much carbon dioxide (CO2) is dissolved in water, which is the first step in calculating the pH of CO2-saturated water. Simply by knowing the partial pressure of the gas and the constant specific to CO2 and water at a given temperature, the concentration can be easily computed, setting the stage for further reactions and equilibrium considerations.
Acidic Oxide Reactions with Water
Acidic oxides, such as CO2, react with water to form acidic solutions. The reaction between carbon dioxide (a common acidic oxide) and water yields carbonic acid (H2CO3), an important intermediate in determining the acidity of aqueous solutions containing CO2. This reaction is represented by the equation:

\( \text{CO}_2 (\text{aq}) + \text{H}_2\text{O} (\text{l}) \rightleftharpoons \text{H}_2\text{CO}_3 (\text{aq}) \)

This equilibrated process is reversible and reaches a state of balance between the reactants and products. Understanding this reaction is key for predicting how a gas will affect the pH of the solution upon dissolution, a concept central to environmental science, physiology, and industrial processes involving carbonated beverages.
Chemical Equilibrium Essentials
Chemical equilibrium occurs when the rates of the forward and reverse reactions in a closed system become equal, resulting in no net change in the concentrations of reactants and products over time. In the case of CO2 reacting with water to form carbonic acid, the dynamic equilibrium can be represented as:

\( \text{CO}_2 (\text{aq}) + \text{H}_2\text{O} (\text{l}) \rightleftharpoons \text{H}_2\text{CO}_3 (\text{aq}) \)

At equilibrium, the concentration of H2CO3 will be equal to the concentration of dissolved CO2, provided no other reactions take place. Recognizing the establishment of equilibrium is fundamental to understanding how changes in conditions, such as pressure or temperature, may shift the balance and affect the resulting concentrations in the system.
Weak Acid Ionization and Its Effects
When a weak acid like carbonic acid (H2CO3) dissolves in water, it only ionizes partially. This process results in a dynamic equilibrium between the undissociated acid and its ions. The ionization equation for carbonic acid is:

\( \text{H}_2\text{CO}_3 (\text{aq}) + \text{H}_2\text{O} (\text{l}) \rightleftharpoons \text{HCO}_3^- (\text{aq}) + \text{H}_3\text{O}^+ (\text{aq}) \)

The equilibrium constant for this weak acid ionization, represented as Ka, gives an indication of the strength of the acid. The lower the value of Ka, the weaker the acid, and the fewer hydrogen ions (H3O+) are produced. Consequently, the lower concentration of hydrogen ions dictates a higher pH, meaning a less acidic solution. Understanding the ionization behavior of weak acids like carbonic acid is crucial for predicting the resulting pH of the solution.
The Significance of Equilibrium Constants
Equilibrium constants such as Ka for weak acids, provide information on the extent of ionization at equilibrium. For a general weak acid ionization represented by:

\( \text{HA} (\text{aq}) + \text{H}_2\text{O} (\text{l}) \rightleftharpoons \text{A}^- (\text{aq}) + \text{H}_3\text{O}^+ (\text{aq}) \)

the equilibrium constant Ka is expressed as:

\( \text{Ka} = \frac{[\text{A}^-][\text{H}_3\text{O}^+]}{[\text{HA}]} \)

For the specific case of carbonic acid (H2CO3), knowing Ka allows for the prediction of H3O+ ion concentration. As the H3O+ concentration can be approximated by the square root of the product of Ka and the concentration of H2CO3, it is possible to determine the pH by the negative logarithm of the H3O+ concentration. A thorough understanding of equilibrium constants is thus integral to pH calculation and interpretation of acid-base behavior in solution.

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Most popular questions from this chapter

How many grams of sodium lactate \(\left[\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COONa}\right.\) or \(\left.\mathrm{NaC}_{3} \mathrm{H}_{5} \mathrm{O}_{3}\right]\) should be added to \(1.00 \mathrm{~L}\) of \(0.150 \mathrm{M}\) lactic acid \(\left[\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\right.\) or \(\left.\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{3}\right]\) to form a buffer solution with \(\mathrm{pH} 4.00\) ? Assume that no volume change occurs when the sodium lactate is added.

How many milliliters of \(0.105 \mathrm{M} \mathrm{HCl}\) are needed to titrate each of the following solutions to the equivalence point: (a) \(45.0 \mathrm{~mL}\) of \(0.0950 \mathrm{M} \mathrm{NaOH}\), (b) \(22.5 \mathrm{~mL}\) of \(0.118 \mathrm{M} \mathrm{NH}_{3}\), (c) \(125.0 \mathrm{~mL}\) of a solution that contains \(1.35 \mathrm{~g}\) of \(\mathrm{NaOH}\) per liter?

How does titration of a strong, monoprotic acid with a strong base differ from titration of a weak, monoprotic acid with a strong base with respect to the following: (a) quantity of base required to reach the equivalence point, (b) \(\mathrm{pH}\) at the beginning of the titration, \((\mathrm{c}) \mathrm{pH}\) at the equivalence point, (d) \(\mathrm{pH}\) after addition of a slight excess of base, (e) choice of indicator for determining the equivalence point?

Describe the solubility of \(\mathrm{CaCO}_{3}\) in each of the following solutions compared to its solubility in water: (a) in \(0.10 \mathrm{M} \mathrm{NaCl}\) solution; \((\mathrm{b})\) in \(0.10 \mathrm{M} \mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) solution; (c) \(0.10 \mathrm{M} \mathrm{Na}_{2} \mathrm{CO}_{3}\); (d) \(0.10 \mathrm{M}\) HCl solution. (Answer same, less soluble, or more soluble.)

The osmotic pressure of a saturated solution of strontium sulfate at \(25^{\circ} \mathrm{C}\) is 21 torr. What is the solubility product of this salt at \(25^{\circ} \mathrm{C}\) ?

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