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(a) Write an equation for the reaction in which \(\mathrm{H}_{2} \mathrm{C}_{6} \mathrm{H}_{7} \mathrm{O}_{5}^{-}(a q)\) acts as a base in \(\mathrm{H}_{2} \mathrm{O}(l) .\) (b) Write an equation for the reaction in which \(\mathrm{H}_{2} \mathrm{C}_{6} \mathrm{H}_{7} \mathrm{O}_{5}^{-}(\mathrm{aq})\) acts as an acid in \(\mathrm{H}_{2} \mathrm{O}(l)\). (c) What is the conjugate acid of \(\mathrm{H}_{2} \mathrm{C}_{6} \mathrm{H}_{7} \mathrm{O}_{5}^{7} ?\) What is its conjugate base?

Short Answer

Expert verified
(a) As a base in H鈧侽, the reaction is: HC鈧咹鈧嘜鈧呪伝 (aq) + H鈧侽 (l) 鈬 H鈧侰鈧咹鈧嘜鈧 (aq) + OH鈦 (aq). (b) As an acid in H鈧侽, the reaction is: HC鈧咹鈧嘜鈧呪伝 (aq) + H鈧侽 (l) 鈬 C鈧咹鈧哋鈧吢测伝 (aq) + H鈧僌鈦 (aq). (c) The conjugate acid of HC鈧咹鈧嘜鈧呪伝 is H鈧侰鈧咹鈧嘜鈧, and its conjugate base is C鈧咹鈧哋鈧吢测伝.

Step by step solution

01

Write the equation for the reaction in which HC鈧咹鈧嘜鈧呪伝 acts as a base in H鈧侽

According to the Bronsted-Lowry definition, a base is a proton (H鈦) acceptor. HC鈧咹鈧嘜鈧呪伝 will accept a proton from water, H鈧侽, forming OH鈦 and the conjugate acid of HC鈧咹鈧嘜鈧呪伝. The equation for this reaction is: HC鈧咹鈧嘜鈧呪伝 (aq) + H鈧侽 (l) 鈬 H鈧侰鈧咹鈧嘜鈧 (aq) + OH鈦 (aq)
02

Write the equation for the reaction in which HC鈧咹鈧嘜鈧呪伝 acts as an acid in H鈧侽

According to the Bronsted-Lowry definition, an acid is a proton (H鈦) donor. HC鈧咹鈧嘜鈧呪伝 will donate a proton to water, H鈧侽, forming H鈧僌鈦 and the conjugate base of HC鈧咹鈧嘜鈧呪伝. The equation for this reaction is: HC鈧咹鈧嘜鈧呪伝 (aq) + H鈧侽 (l) 鈬 C鈧咹鈧哋鈧吢测伝 (aq) + H鈧僌鈦 (aq)
03

Identify the conjugate acid of HC鈧咹鈧嘜鈧呪伝 and its conjugate base

The conjugate acid of HC鈧咹鈧嘜鈧呪伝 is formed when HC鈧咹鈧嘜鈧呪伝 acts as a base and accepts a proton (H鈦). From the equation in step 1, we see that the conjugate acid of HC鈧咹鈧嘜鈧呪伝 is H鈧侰鈧咹鈧嘜鈧. The conjugate base of HC鈧咹鈧嘜鈧呪伝 is formed when HC鈧咹鈧嘜鈧呪伝 acts as an acid and donates a proton. From the equation in step 2, we see that the conjugate base of HC鈧咹鈧嘜鈧呪伝 is C鈧咹鈧哋鈧吢测伝. So, the conjugate acid of HC鈧咹鈧嘜鈧呪伝 is H鈧侰鈧咹鈧嘜鈧, and its conjugate base is C鈧咹鈧哋鈧吢测伝.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bronsted-Lowry acid
In the world of chemistry, understanding acids and bases is fundamental. The Bronsted-Lowry definition of an acid is a molecule or ion that can donate a proton, which is a hydrogen ion (\(\text{H}^+\)). This concept broadens our perspective beyond simple aqueous solutions like hydrochloric acid or sulfuric acid. An acid, under this definition, does not need to increase hydrogen concentration directly in water, but only needs to be able to donate hydrogen ions to other substances.

Let's consider the chemical species \(\text{HC}_6\text{H}_7\text{O}_5^-\) in water. When it acts as an acid, it donates a proton to water (\(\text{H}_2\text{O}\)), forming \(\text{H}_3\text{O}^+\) or hydronium ions, and \(\text{C}_6\text{H}_6\text{O}_5^{2-}\) which is the conjugate base. The process can be visualized in the equation:
  • \(\text{HC}_6\text{H}_7\text{O}_5^- + \text{H}_2\text{O} \rightleftharpoons \text{C}_6\text{H}_6\text{O}_5^{2-} + \text{H}_3\text{O}^+\)
Notice the bidirectional arrow, indicating that this is an equilibrium, reversible process.
Bronsted-Lowry base
A Bronsted-Lowry base is a molecule or ion that can accept a proton (\(\text{H}^+\)). This broader definition allows us to classify compounds as bases even if they don't display traditional characteristics like a slippery feel or high pH. Instead, bases are evaluated on their ability to accept protons in chemical reactions.

For example, consider the species \(\text{HC}_6\text{H}_7\text{O}_5^-\) acting as a base. In a chemical reaction with water, this compound accepts a proton from \(\text{H}_2\text{O}\) and forms \(\text{OH}^-\) ions along with \(\text{H}_2\text{C}_6\text{H}_7\text{O}_5\), which becomes the conjugate acid of the base. This reaction is represented by the equation:
  • \(\text{HC}_6\text{H}_7\text{O}_5^- + \text{H}_2\text{O} \rightleftharpoons \text{H}_2\text{C}_6\text{H}_7\text{O}_5 + \text{OH}^-\)
Here, the flexibility of \(\text{HC}_6\text{H}_7\text{O}_5^-\) showcases how substances can interchangeably act as acids or bases, depending on the reaction context.
Conjugate acid-base pairs
The concept of conjugate acid-base pairs is central to the Bronsted-Lowry theory and helps us understand the reversibility and dynamic nature of acid-base reactions. When a Bronsted-Lowry acid donates a proton, it becomes a conjugate base. Conversely, when a Bronsted-Lowry base accepts a proton, it becomes a conjugate acid. This transformation forms a conjugate acid-base pair.

For instance, in the reaction in which \(\text{HC}_6\text{H}_7\text{O}_5^-\) acts as an acid, after donating a proton, it becomes \(\text{C}_6\text{H}_6\text{O}_5^{2-}\). This shows that \(\text{HC}_6\text{H}_7\text{O}_5^-\) and \(\text{C}_6\text{H}_6\text{O}_5^{2-}\) form a conjugate acid-base pair.

Similarly, when \(\text{HC}_6\text{H}_7\text{O}_5^-\) acts as a base, it accepts a proton and becomes \(\text{H}_2\text{C}_6\text{H}_7\text{O}_5\), forming another conjugate pair. Identifying these pairs in reactions helps predict the direction and extent of chemical changes.
  • In reaction 1: \(\text{HC}_6\text{H}_7\text{O}_5^- + \text{H}_2\text{O} \rightleftharpoons \text{C}_6\text{H}_6\text{O}_5^{2-} + \text{H}_3\text{O}^+\)
  • In reaction 2: \(\text{HC}_6\text{H}_7\text{O}_5^- + \text{H}_2\text{O} \rightleftharpoons \text{H}_2\text{C}_6\text{H}_7\text{O}_5 + \text{OH}^-\)
Recognizing these relationships sharpens our understanding of chemical and biological systems.

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