/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 A dilute aqueous solution of an ... [FREE SOLUTION] | 91Ó°ÊÓ

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A dilute aqueous solution of an organic compound soluble in water is formed by dissolving \(2.35 \mathrm{~g}\) of the compound in water to form \(0.250 \mathrm{~L}\) solution. The resulting solution has an osmotic pressure of \(0.605 \mathrm{~atm}\) at \(25^{\circ} \mathrm{C}\). Assuming that the organic compound is a nonelectrolyte, what is its molar mass?

Short Answer

Expert verified
The molar mass of the organic compound is \(38.3\mathrm{~g/mol}\).

Step by step solution

01

Calculate Temperature in Kelvin

Convert the given temperature from Celsius to Kelvin by adding 273.15 to the Celsius value: \(T = 25 + 273.15 = 298.15\mathrm{~K}\)
02

Calculate Molarity of the Solution

Use the osmotic pressure formula (π = MRT) to calculate the molarity (M) by rearranging it: \(M = \frac{π}{RT}\) Substitute the given values of π, R, and T into the formula to calculate the molarity: \(M = \frac{0.605\mathrm{~atm}}{(0.0821\mathrm{~L~atm/mol~K}) (298.15\mathrm{~K})} = 0.0247 \mathrm{~mol/L}\)
03

Calculate Grams per Mole

Use the formula to calculate grams per mole: \[Mâ‚‚ = \frac{m}{MV}\] Substitute the mass (m), molarity (M), and volume (V) into the formula to calculate the molar mass: \(Mâ‚‚ = \frac{2.35\mathrm{~g}}{(0.0247\mathrm{~mol/L})(0.250\mathrm{~L})} = 38.3\mathrm{~g/mol}\) Therefore, the molar mass of the organic compound is 38.3 g/mol.

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Most popular questions from this chapter

Show that the vapor-pressure reduction, \(\Delta P_{\text {solvent }}\), associated with the addition of a nonvolatile solute to a volatile solvent is given by the equation \(\Delta P_{\text {solvent }}=\) \(X_{\text {solute }} \times P_{\text {solvent }}^{\circ}\)

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