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Suppose you are given two 1-L flasks and told that one contains a gas of molar mass 30 , the other a gas of molar mass 60 , both at the same temperature. The pressure in flask \(\mathrm{A}\) is \(\mathrm{X} \mathrm{atm}\), and the mass of gas in the flask is \(1.2 \mathrm{~g}\). The pressure in flask B is \(0.5 \mathrm{X} \mathrm{atm}\), and the mass of gas in that flask is \(1.2 \mathrm{~g}\). Which flask contains gas of molar mass 30 , and which contains the gas of molar mass 60 ?

Short Answer

Expert verified
Flask A contains the gas with a molar mass of 30 and flask B contains the gas with a molar mass of 60, as there are twice as many moles in flask A compared to flask B.

Step by step solution

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1. Calculate the moles of gases for flask A and flask B using the Ideal Gas Law

As we know the mass, molar mass, and pressure of both gases, we can calculate the moles of gas using the formula: n = mass / molar mass For flask A: Pressure P = X atm M = 1.2 g For flask B: Pressure P = 0.5*X atm M = 1.2 g As we don’t know the molar mass yet, we denote this as Molar_mass_A for flask A and Molar_mass_B for flask B. Now we can use the Ideal Gas Law to determine the moles. For flask A: \(n_A = 1.2 / \text{Molar_mass_A}\) For flask B: \(n_B = 1.2 / \text{Molar_mass_B}\)
02

2. Compare the moles of the two gases

We will now compare the moles of gases in both flasks, using the pressure ratio to find the relationship between the moles of gas: \(P_A / P_B = n_A / n_B\) Substitute the given values for P_A and P_B: \(X / (0.5X) = n_A / n_B\) or \(2 = n_A / n_B\) Now we know that there are twice as many moles in flask A compared to flask B.
03

3. Identify the molar mass of each gas

Since flask A has twice the moles of gas as flask B, we can conclude that the molar mass of the gas in flask A is smaller than that in flask B. Therefore, flask A contains the gas with a molar mass of 30, and flask B contains the gas with a molar mass of 60.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
Understanding how to calculate the molar mass of a gas is essential in chemistry, particularly when working with the Ideal Gas Law. Molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol). It is calculated by summing the atomic masses of all the atoms in one molecule of the substance.

To find the molar mass from a mass of gas and the number of moles, you use the simple formula:
\[ \text{Molar Mass} = \frac{\text{mass of the gas (in grams)}}{\text{number of moles of the gas}} \]
This formula was applied in our exercise, where the mass was given, and the moles were found using the Ideal Gas Law. Once the amount of substance in moles was determined, a comparison between the two different gases allowed for identification of which flask contains which molar mass of gas. Simplicity in this calculation is key, as it lays the foundation for understanding more complex chemical equations and applications.
Gas Law Applications
The Ideal Gas Law, represented by the equation \(PV = nRT\), where \(P\) stands for pressure, \(V\) for volume, \(n\) for moles, \(R\) for the ideal gas constant, and \(T\) for temperature, is a crucial tool in chemistry. In our example, we see the Ideal Gas Law in action, demonstrating how it can be used to solve real-world problems involving gases.

One key application of the Ideal Gas Law is determining the amount of gas (in moles) present in a container of known volume and pressure, as was needed in our exercise. This calculation is common in lab settings where the reaction yields need to be calculated or when dealing with pressurized systems. By manipulating the Ideal Gas Law, we can predict how a gas will behave under different conditions, such as changes in pressure or temperature, making it a versatile equation in chemistry and engineering.
Mole Concept
The mole concept is a fundamental pillar in the study of chemistry. One mole is defined as the amount of substance containing as many elementary entities (such as atoms or molecules) as there are atoms in exactly 12 grams of carbon-12. This number is Avogadro's number, which is approximately \(6.022 \times 10^{23}\) entities per mole.

The mole allows chemists to convert between the mass of a substance and the number of particles it contains. In the given exercise, the mole concept enables us to bridge the gap between the macroscopic world (grams of a substance) and the microscopic world (number of molecules of the gas). Precise understanding and application of the mole concept are necessary for all quantitative aspects of chemistry, as it is used to measure the amount of substance when it comes to reactions, concentrations, and even the Ideal Gas Law.

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Most popular questions from this chapter

A sample of \(1.42 \mathrm{~g}\) of helium and an unweighed quantity of \(\mathrm{O}_{2}\) are mixed in a flask at room temperature. The partial pressure of helium in the flask is \(42.5\) torr, and the partial pressure of oxygen is 158 torr. What is the mass of the oxygen in the container?

Carbon dioxide, which is recognized as the major contributor to global warming as a "greenhouse gas," is formed when fossil fuels are combusted, as in electrical power plants fueled by coal, oil, or natural gas. One potential way to reduce the amount of \(\mathrm{CO}_{2}\) added to the atmosphere is to store it as a compressed gas in underground formations. Consider a 1000 -megawatt coalfired power plant that produces about \(6 \times 10^{6}\) tons of \(\mathrm{CO}_{2}\) per year. (a) Assuming ideal gas behavior, \(1.00 \mathrm{~atm}\), and \(27{ }^{\circ} \mathrm{C}\), calculate the volume of \(\mathrm{CO}_{2}\) produced by this power plant. (b) If the \(\mathrm{CO}_{2}\) is stored underground as a liquid at \(10^{\circ} \mathrm{C}\) and \(120 \mathrm{~atm}\) and a density of \(1.2 \mathrm{~g} / \mathrm{cm}^{3}\), what volume does it possess? (c) If it is stored underground as a gas at \(36{ }^{\circ} \mathrm{C}\) and \(90 \mathrm{~atm}\), what volume does it occupy?

Assume that you have a cylinder with a movable piston. What would happen to the gas pressure inside the cylinder if you do the following? (a) Decrease the volume to one-fourth the original volume while holding the temperature constant. (b) Reduce the Kelvin temperature to half its original value while holding the volume constant. (c) Reduce the amount of gas to half while keeping the volume and temperature constant.

In the United States, barometric pressures are generally reported in inches of mercury (in. \(\mathrm{Hg}\) ). On a beautiful summer day in Chicago the barometric pressure is \(30.45\) in. Hg. (a) Convert this pressure to torr. (b) A meteorologist explains the nice weather by referring to a "high-pressure area." In light of your answer to part (a), explain why this term makes sense.

A large flask is evacuated and weighed, filled with argon gas, and then reweighed. When reweighed, the flask is found to have gained \(3.224 \mathrm{~g}\). It is again evacuated and then filled with a gas of unknown molar mass. When reweighed, the flask is found to have gained \(8.102\) g. (a) Based on the molar mass of argon, estimate the molar mass of the unknown gas. (b) What assumptions did you make in arriving at your answer?

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