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Assign an oxidation state to phosphorus in each of the following: (a) \(\mathrm{NaH}_{2} \mathrm{PO}_{3}\) (b) \(\mathrm{PF}_{5}\) (c) \(\mathrm{P}_{4} \mathrm{O}_{6}\) (d) \(\mathrm{K}_{3} \mathrm{PO}_{4}\) (e) \(\mathrm{Na}_{3} \mathrm{P}\) (f) \(\mathrm{Na}_{4} \mathrm{P}_{2} \mathrm{O}_{7}\)

Short Answer

Expert verified
Oxidation states of phosphorus: (a) +3, (b) +5, (c) +3, (d) +5, (e) -3, (f) +5

Step by step solution

01

- Assign oxidation states for simple ions

For compounds with simple ions, the oxidation state of the ion matches its charge. In ionic compounds with multiple elements, alkali metal ions (from group 1 of the periodic table) have an oxidation state of +1, and oxygen generally has an oxidation state of -2 (except in peroxides, superoxides, or when bonded to fluorine).
02

- Use known oxidation states to determine phosphorus oxidation state in NaH2PO3

Using the formula for sodium dihydrogen phosphite (NaH2PO3), and knowing that sodium (Na) has an oxidation state of +1, hydrogen (H) has an oxidation state of +1, and oxygen (O) generally has an oxidation state of -2, we can set up an equation: \( 1({\text{for Na}}) + 2({\text{for H}}) + x({\text{for P}}) + 3(-2) = 0 \) where x is the oxidation state of phosphorus. Solving for x gives us the oxidation state of phosphorus.
03

- Determine phosphorus oxidation state in PF5

In phosphorus pentafluoride (PF5), each fluorine (F) has an oxidation state of -1. Since there are five fluorine atoms, we set up the equation: \( x + 5(-1) = 0 \), where x is the oxidation state of phosphorus. Solving for x gives us the oxidation state of phosphorus.
04

- Calculate the average oxidation state of phosphorus in P4O6

Tetraphosphorus hexoxide (P4O6) is a molecular compound with 4 phosphorus atoms. Oxygen has an oxidation state of -2. The total oxidation state of the oxygen atoms in the molecule is \( 6(-2) = -12 \). We can set up the equation: \( 4x - 12 = 0 \), where x is the average oxidation state of phosphorus. Solving for x gives us the average oxidation state of phosphorus in the molecule.
05

- Determine phosphorus oxidation state in K3PO4

Potassium phosphate (K3PO4) contains potassium (K) with an oxidation state of +1 and oxygen with an oxidation state of -2. With 3 potassium atoms, and 4 oxygen atoms, the equation is: \( 3(+1) + x + 4(-2) = 0 \), where x is the oxidation state of phosphorus. Solving for x gives us the oxidation state of phosphorus.
06

- Calculate the oxidation state of phosphorus in Na3P

In sodium phosphide (Na3P), sodium has an oxidation state of +1. With 3 sodium atoms, the equation is: \( 3(+1) + x = 0 \), where x is the oxidation state of phosphorus. Solving for x yields the oxidation state of phosphorus.
07

- Determine phosphorus oxidation state in Na4P2O7

Sodium pyrophosphate (Na4P2O7) contains sodium with an oxidation state of +1 and oxygen with an oxidation state of -2. With 4 sodium atoms and 7 oxygen atoms, we set up the equation for 2 phosphorus atoms: \( 4(+1) + 2x + 7(-2) = 0 \), which simplifies to \( 4 - 14 + 2x = 0 \). Solving for x gives us the average oxidation state of phosphorus.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation State Determination
Understanding the oxidation states of elements within compounds is a fundamental aspect of analyzing chemical reactions, particularly redox reactions. An oxidation state, often referred to as oxidation number, is a theoretical charge that an atom would have if all bonds to atoms of different elements were completely ionic. Here's a simplified approach for determining oxidation states:

  • For monoatomic ions, the oxidation state is equal to the charge of the ion. For example, Na+ has an oxidation state of +1.
  • In a neutral compound, the sum of the oxidation states is zero; in a polyatomic ion, it equals the ion’s charge.
  • Some elements have consistent oxidation states, like alkali metals (always +1) and alkaline earth metals (always +2).
  • Oxygen typically has an oxidation state of -2, except in peroxides or when bonded to fluorine.
  • Hydrogen generally has an oxidation state of +1, except when it's bonded to metals in hydrides where its oxidation state is -1.
To determine the oxidation state of phosphorus in a compound, you would balance the known oxidation states of other elements with the unknown oxidation state of phosphorus so that the sum correlates with the compound's overall charge. Through setting up an algebraic equation, you are able to solve for the unknown oxidation state.
Chemical Nomenclature
Navigating through the diverse world of chemical compounds can be daunting without a proper naming system, known as chemical nomenclature. It provides a standardized way to refer to chemical substances based on their composition. A few highlights include:

  • Binary compounds consist of two different elements and are named by using the first element's full name and adding 'ide' to the root of the second element's name.
  • We use prefixes like mono-, di-, tri-, to indicate the number of atoms of each element in a molecular compound.
  • For ionic compounds with transition metals, roman numerals denote the metal’s oxidation state due to its ability to have multiple oxidation states.
  • Polyatomic ions are named based on their composition and the number of oxygen atoms, with suffixes '-ate' or '-ite' indicating more or fewer oxygen atoms respectively.
Chemical nomenclature sets the stage for understanding the composition and reactions of compounds. For example, in sodium dihydrogen phosphite (NaH2PO3), 'sodium' indicates the presence of Na, 'dihydrogen' tells us there are two hydrogen atoms, and 'phosphite' suggests a polyatomic ion with phosphorus and less oxygen than in 'phosphate' compounds.
Balancing Redox Equations
Redox equations require balance, not just in terms of mass, but also in charge, making them more complex than standard chemical equations. Redox (reduction-oxidation) reactions involve the transfer of electrons between species, leading to a change in their oxidation states. Here's how to approach balancing redox equations:

  • Identify the oxidation states of all atoms involved in the reaction.
  • Separate the reaction into two half-reactions: one for oxidation and one for reduction.
  • Balance the elements and charges in each half-reaction. You may have to add H2O, H+, or OH- ions to balance the equation depending on the reaction conditions (acidic or basic).
  • Balance the electrons transferred by multiplying the half-reactions by coefficients that will equalize the number of electrons lost in the oxidation half and gained in the reduction half.
  • Combine the half-reactions, canceling out species that appear on both sides, and ensure that the atoms and charges are balanced.
Mastering the balancing of redox equations is essential for understanding how electrons shuffle during chemical reactions, which is a cornerstone of topics like electrochemistry and metabolic processes in biology.

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Most popular questions from this chapter

The following reactions are all similar to those of the industrial chemicals. Complete and balance the equations for these reactions: (a) reaction of a weak base and a strong acid \(\mathrm{NH}_{3}+\mathrm{HClO}_{4} \rightarrow\) (b) preparation of a soluble silver salt for silver plating \(\mathrm{Ag}_{2} \mathrm{CO}_{3}+\mathrm{HNO}_{3} \longrightarrow\) (c) preparation of strontium hydroxide by electrolysis of a solution of strontium chloride \(\operatorname{SrCl}_{2}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \stackrel{\text { electrolysis }}{\longrightarrow}\)

Give balanced equations for the overall reaction in the electrolysis of molten lithium chloride and for the reactions occurring at the electrodes. You may wish to review the chapter on electrochemistry for relevant examples.

Write balanced chemical equations for the following reactions: (a) zinc metal heated in a stream of oxygen gas (b) zinc carbonate heated until loss of mass stops (c) zinc carbonate added to a solution of acetic acid, \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}\) (d) zinc added to a solution of hydrobromic acid

Why does phosphorous acid form only two series of salts, even though the molecule contains three hydrogen atoms?

Determine the oxidation state of nitrogen in each of the following. You may wish to review the chapter on chemical bonding for relevant examples. (a) \(\mathrm{NCl}_{3}\) (b) CINO (c) \(\mathrm{N}_{2} \mathrm{O}_{5}\) (d) \(\mathrm{N}_{2} \mathrm{O}_{3}\) (e) \(\mathrm{NO}_{2}^{-}\) (f) \(\mathrm{N}_{2} \mathrm{O}_{4}\) (g) \(\mathrm{N}_{2} \mathrm{O}\) (h) \(\mathrm{NO}_{3}^{-}\) (i) HNO \(_{2}\) (j) HNO \(_{3}\)

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