Chapter 14: Problem 94
Calculate the pH at the following points in a titration of 40 mL (0.040 L) of 0.100 M barbituric acid ( \(K_{\mathrm{a}}=9.8\) \(\left.\times 10^{-5}\right)\) with \(0.100 \mathrm{M} \mathrm{KOH}\). (a) no KOH added (b) \(20 \mathrm{mL}\) of KOH solution added (c) \(39 \mathrm{mL}\) of \(\mathrm{KOH}\) solution added (d) \(40 \mathrm{mL}\) of \(\mathrm{KOH}\) solution added (e) \(41 \mathrm{mL}\) of KOH solution added
Short Answer
Step by step solution
- Calculate the initial pH
- Calculate the pH with 20 mL KOH added
- Calculate the pH with 39 mL KOH added
- Calculate the pH at the equivalence point
- Calculate the pH after exceeding the equivalence point
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