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What is the electron-pair and molecular geometry around the central \(\mathrm{S}\) atom in sulfury \(\mathrm{chloride}, \mathrm{SO}_{2} \mathrm{Cl}_{2} ?\) What is the hybridization of sulfur in this compound?

Short Answer

Expert verified
The electron-pair and molecular geometry are tetrahedral; sulfur is \(sp^3\) hybridized.

Step by step solution

01

Determine Valence Electrons

Sulfur (S) has 6 valence electrons, each Oxygen (O) has 6, and each Chlorine (Cl) has 7. Calculating total: \(1 \times 6 + 2 \times 6 + 2 \times 7 = 32\) electrons.
02

Draw the Lewis Structure

The Lewis structure of \(\text{SO}_2\text{Cl}_2\) shows sulfur in the center with single bonds to two chlorine atoms and one double bond to each oxygen atom, fulfilling the octet rule for all atoms.
03

Identify Electron-Pair Geometry

Sulfur has four regions of electron density (two bonds with Cl, two double bonds with O), resulting in a tetrahedral electron-pair geometry.
04

Determine Molecular Geometry

All bonds are with different atoms, so there are no lone pairs on sulfur. The molecular geometry corresponds to the electron-pair geometry, which is also tetrahedral.
05

Find Hybridization

With four regions of electron density, sulfur is \(sp^3\) hybridized, as \(sp^3\) corresponds to a tetrahedral arrangement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Structure
To understand the shape and behavior of a molecule like sulfuryl chloride (\( \text{SO}_2\text{Cl}_2 \)), we first need to identify the Lewis structure. Lewis structures are diagrams that show the bonding between atoms of a molecule, as well as any lone pairs of electrons. For \( \text{SO}_2\text{Cl}_2 \), sulfur is the central atom. This is because it's usually the atom with the least electronegativity (other than hydrogen), making it a good central atom. Sulfur forms single bonds with two chlorine atoms and double bonds with two oxygen atoms. This arrangement satisfies the octet rule, ensuring each atom's outer shell is filled. By drawing out the Lewis structure, we can visualize the particular bonds and understand the arrangement of electrons around our central sulfur atom.
Electron-Pair Geometry
Electron-pair geometry considers all regions of electron density around the central atom, including bonds and lone pairs. For sulfuryl chloride, sulfur is surrounded by four regions of electron density: two single bonds to chlorine and two double bonds to oxygen. This gives every region equal importance, indicating a tetrahedral electron-pair geometry. Understanding the electron-pair geometry helps predict molecular shapes by showing how electron pairs or bonds are distributed in three-dimensional space. It’s like imagining a central core with electron clouds stretching out equally in all directions, ensuring minimal repulsion and maximum stability.
Hybridization
Hybridization explains how atomic orbitals mix to form new hybrid orbitals, leading to new bonding properties. In \( \text{SO}_2\text{Cl}_2 \), sulfur needs to form four bonds—one with each atom. Thus, it adopts a hybridization that allows for such an arrangement. Sulfur in this molecule undergoes \( sp^3 \) hybridization. This means one \( s \) orbital and three \( p \) orbitals combine, creating four equivalent \( sp^3 \) hybrid orbitals. These orbitals then form the shape that corresponds with a tetrahedral arrangement, providing insights into the bonding framework and molecular geometry.
Molecular Geometry
While electron-pair geometry considers both bonding and non-bonding pairs, molecular geometry focuses only on the bonding pairs. For \( \text{SO}_2\text{Cl}_2 \), since all electron density regions are involved in bonding and there are no lone pairs on sulfur, the molecular geometry mirrors the electron-pair geometry, which is tetrahedral. By examining the molecular geometry, we see how the atoms are precisely positioned in space. This understanding helps predict how the molecule interacts chemically and physically with other substances, highlighting important practical insights into its properties.

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Most popular questions from this chapter

The simple valence bond picture of \(\mathrm{O}_{2}\) does not agree with the molecular orbital view. Compare these two theories with regard to the peroxide ion, \(\mathbf{O}_{2}^{2-}\) (a) Draw an electron dot structure for \(\mathrm{O}_{2}^{2-}\). What is the bond order of the ion? (b) Write the molecular orbital electron configuration for O \(_{2}^{2-} .\) What is the bond order based on this approach? (c) Do the two theories of bonding lead to the same magnetic character and bond order for \(\mathbf{O}_{2}^{2-} ?\)

Carbon dioxide \(\left(\mathrm{CO}_{2}\right),\) dinitrogen monoxide \(\left(\mathrm{N}_{2} \mathrm{O}\right)\) the azide ion \(\left(\mathrm{N}_{3}^{-}\right),\) and the cyanate ion (OCN^-) have the same arrangement of atoms and the same number of valence shell electrons. However, there are significant differences in their electronic structures. (a) What hybridization is assigned to the central atom in each species? Which orbitals overlap to form the bonds between atoms in each structure. (b) Evaluate the resonance structures of these four species. Which most closely describe the bonding in these species? Comment on the differences in bond lengths and bond orders that you expect to see based on the resonance structures.

Platinum hexafluoride is an extremely strong oxidizing agent. It can even oxidize oxygen, its reaction with \(\mathrm{O}_{2}\) giving \(\mathrm{O}_{2}^{+} \mathrm{PtF}_{6}^{-}\). Sketch the molecular orbital energy Level diagram for the \(\mathrm{O}_{2}^{+}\) ion. How many net \(\sigma\) and \(\pi\) bonds does the ion have? What is the oxygen-oxygen bond order? How has the bond order changed on taking away electrons from \(\mathbf{O}_{2}\) to obtain \(\mathbf{O}_{2}^{+}\) ? Is the \(\mathbf{O}_{2}^{+}\) ion paramagnetic?

Specify the electron-pair and molecular geometry for each underlined atom in the following list. Describe the hybrid orbital set used by this atom in each molecule or ion. (a) \(\underline{\mathrm{BBr}}_{\mathrm{s}}\) (b) \(\underline{\mathrm{CO}}_{2}\) (c) \(\underline{\mathrm{CH}}_{2} \mathrm{Cl}_{2} \quad\) (d) \(\underline{\mathrm{CO}}_{3}^{2-}\)

What is the hybridization of the carbon atom in phosgene, \(\mathrm{Cl}_{2}\) CO? Give a complete description of the \(\sigma\) and \pi bonding in this molecule.

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