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Show all possible resonance structures for each of the following molecules or ions: (a) sulfur dioxide, \(\mathrm{SO}_{2}\) (b) nitrous acid, HNO \(_{2}\) (c) thiocyanate ion, \(\mathrm{SCN}^{-}\)

Short Answer

Expert verified
Each molecule or ion has multiple resonance structures, which involve shifting double or triple bonds and lone pairs to maintain electron count.

Step by step solution

01

Identify the Central Atom

For each molecule or ion, identify the central atom. This is usually the atom with the lowest electronegativity, except for hydrogen. For (a) SO鈧, the central atom is sulfur (S). For (b) HNO鈧, the central atom is nitrogen (N), and for (c) SCN鈦, the central atom is carbon (C).
02

Calculate Total Valence Electrons

Determine the total number of valence electrons for each species by adding the valence electrons of each atom. For SO鈧, sulfur contributes 6 electrons and each oxygen 6, totaling 18 electrons. HNO鈧 has H with 1, N with 5, and each O with 6, totaling 18. SCN鈦 has S with 6, C with 4, and N with 5 electrons, plus 1 extra electron for the charge, totaling 16 electrons.
03

Draw Initial Lewis Structure

Create the initial structure using single bonds connecting the central atom to other atoms, and distribute the remaining electrons to satisfy the octet rule where possible. For (a) SO鈧, place sulfur in the center with single bonds to two O's. For (b) HNO鈧, place N centrally, single-bond to H, and double-bond to O鹿, single-bond to O虏. For (c) SCN鈦, connect S, C, and N linearly.
04

Draw Resonance Structures for SO鈧

For SO鈧, you can have structures where sulfur forms one double bond with one oxygen while the other oxygen has a single bond. Alternate the double bond with each oxygen to show resonance structures.
05

Draw Resonance Structures for HNO鈧

Nitrous acid's resonance involves shifting the position of the double bond from one oxygen to the other, while maintaining the rest of the structure intact.
06

Draw Resonance Structures for SCN鈦

Shift the location of the double or triple bonds between the sulfur-carbon-nitrogen line. You can have a triple bond between C and N with a single bond from S to C, or a triple bond between C and S with a single bond from C to N, and a double bond from C to N and C to S.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Structures
Lewis structures are visual representations of the arrangement of atoms within a molecule. They help to show how the atoms are bonded together and the distribution of valence electrons. To draw a Lewis structure, start by identifying the central atom, which is usually the one with the lowest electronegativity. Surround it with other atoms. Use lines to represent bonds between atoms. Each line signifies two electrons. After establishing bonds, distribute remaining electrons to satisfy the octet rule, which ensures atoms have eight electrons around them, either shared or lone pairs. When drawing structures for molecules like sulfur dioxide (SO鈧) or ions like the thiocyanate ion (SCN鈦), consider how each atom can achieve a full valence shell. Lewis structures are the starting point for drawing resonance structures, as they show how electrons are initially distributed.
Valence Electrons
Valence electrons are the outermost electrons of an atom and are crucial in forming chemical bonds. Knowing the number of valence electrons helps in determining how atoms will bond in a molecule. To figure out the number of valence electrons:
  • Look at the group number in the periodic table for each atom鈥攖his usually corresponds to the number of valence electrons.
  • Add up the valence electrons from each atom in the molecule. For ions, adjust for the charge by adding an electron for a negative charge or subtracting for a positive charge.
Valence electrons are involved in forming bonds and are depicted in Lewis structures. For example, sulfur dioxide (SO鈧) has 18 valence electrons, accounting for sulfur and both oxygen atoms. Proper calculation of these electrons is essential to accurately portray the molecular structures.
Octet Rule
The octet rule is a fundamental principle in chemistry, stating that atoms tend to form bonds in such a way that each atom has eight electrons in its valence shell, resembling the electron configuration of noble gases. This rule helps in predicting the bonding behavior of atoms, especially in drawing Lewis structures. While applying the octet rule:
  • Make sure every atom in the molecule (except hydrogen, which follows a duet rule) follows this rule for stability.
  • Atoms will share pairs of electrons through covalent bonds to achieve a complete octet.
There are exceptions to this rule, especially in molecules containing elements from period three and beyond, such as sulfur in SO鈧, which can have more than eight electrons. Understanding the octet rule is crucial when drawing resonance structures, as it guides the rearrangement of electrons.
Resonance in Molecular Chemistry
Resonance occurs in molecules where the electrons can be distributed in different ways by rearranging the bonds, without shifting the position of the atoms. This concept is important as it represents the true nature of the molecule, which cannot be explained by a single Lewis structure alone. For molecules like
  • sulfur dioxide (SO鈧),
  • nitrous acid (HNO鈧),
  • and thiocyanate ion (SCN鈦),
multiple resonance structures can be drawn by shifting bonds and lone pairs. These structures signify the delocalization of electrons across the molecule, contributing to its stability. Resonance helps in understanding the blending of molecular orbitals that contribute to the actual structure, which is a hybrid of all possible resonance forms. The depiction of resonance structures ensures that all significant electron distributions are considered, making it a powerful tool for predicting molecular behavior and properties.

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Most popular questions from this chapter

Compare the electron dot structures of the carbonate \(\left(\mathrm{CO}_{3}^{2-}\right)\) and borate \(\left(\mathrm{BO}_{3}^{3-}\right)\) ions. (a) Are these ions isoelectronic? (b) How many resonance structures does each ion have? (c) What are the formal charges of each atom in these ions? (d) If an \(\mathrm{H}^{+}\) ion attaches to \(\mathrm{CO}_{3}^{2-}\) to form the bicarbonate ion, \(\mathrm{HCO}_{3}^{-},\) does it attach to an \(\mathrm{O}\) atom or to the C atom?

The chemistry of the nitrite ion and HNO \(_{2}:\) (a) Two resonance structures are possible for \(\mathrm{NO}_{2}^{-}\). Draw these structures, and then find the formal charge on each atom in each resonance structure. (b) If an \(\mathrm{H}^{+}\) ion is attached to \(\mathrm{NO}_{2}^{-}\) (to form the acid \(\left.\mathrm{HNO}_{2}\right),\) it attaches to the \(\mathrm{O}\) atom and not the \(\mathrm{N}\) atom. Explain why you would predict this structure. (c) Two resonance structures are possible for HNO,. Draw these structures, and then find the formal charge on each atom in each resonance structure. Is either of these structures strongly preferred over the other?

The following molecules or ions all have three oxygen atoms attached to a central atom. Draw a Lewis structure for each one, and then describe the electron-pair geometry and the molecular geometry around the central atom. Comment on similarities and differences in the series. (a) \(\mathrm{CO}_{3}^{2-}\) (b) \(\mathrm{NO}_{3}^{-}\) (c) \(\mathrm{SO}_{3}^{2-}\) (d) \(\mathrm{ClO}_{3}^{-}\)

For each of the bonds listed below, tell which atom is the more negatively charged. (a) \(\mathbf{C}-\mathbf{N}\) (b) \(\mathbf{C}-\mathbf{H}\) (c) \(\mathrm{C}-\mathrm{Br}\) (d) \(\mathrm{S}-\mathrm{O}\)

Draw resonance structures for the formate ion, \(\mathrm{HCO}_{2}^{-}\) and then determine the \(\mathrm{C}-\mathrm{O}\) bond order in the ion.

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