Chapter 8: Problem 42
Which of the following molecules is (are) not polar? For each polar molecule, indicate the direction of polarity-that is, which is the negative end and which is the positive end. (a) CO (b) \(\mathrm{BCl}_{3}\) (c) \(\mathrm{CF}_{4}\) (d) \(\mathrm{PCl}_{3}\) (e) \(\mathrm{GeH}_{4}\)
Short Answer
Expert verified
\( \mathrm{BCl}_3, \mathrm{CF}_4, \mathrm{GeH}_4 \) are non-polar; CO and \( \mathrm{PCl}_3 \) are polar.
Step by step solution
01
Determine Molecular Geometry
Examine the molecular geometry of each molecule to identify if the shape allows for symmetry, which could lead to non-polarity. - CO is a linear molecule.- \(\mathrm{BCl}_3\) is trigonal planar.- \(\mathrm{CF}_4\) is tetrahedral.- \(\mathrm{PCl}_3\) is trigonal pyramidal.- \(\mathrm{GeH}_4\) is tetrahedral.
02
Determine Electronegativity Difference
Calculate the difference in electronegativity between atoms in each molecule. Polar bonds result from differences in electronegativity:- CO: C (2.55) and O (3.44) have a significant difference, making it polar.- \(\mathrm{BCl}_3\): B (2.04) and Cl (3.16) have a significant difference, but the symmetrical planar shape leads to cancellation of dipoles.- \(\mathrm{CF}_4\): C (2.55) and F (3.98) have a significant difference, with symmetrical cancelation, making it non-polar.- \(\mathrm{PCl}_3\): P (2.19) and Cl (3.16) do not fully cancel due to asymmetrical trigonal pyramidal shape.- \(\mathrm{GeH}_4\) has Ge (2.01) and H (2.20) with low difference and symmetrical structure leading to complete cancellation.
03
Evaluate Polarity and Direction
Evaluate the polarity based on molecular geometry and electronegativity differences:- CO is polar, with C as the positive end and O as the negative end due to higher electronegativity.- \(\mathrm{BCl}_3\) is non-polar due to the symmetrical arrangement.- \(\mathrm{CF}_4\) is non-polar due to the symmetrical tetrahedral shape.- \(\mathrm{PCl}_3\) is polar; the Cl atoms are more electronegative, making them the negative end.- \(\mathrm{GeH}_4\) is non-polar due to the symmetrical tetrahedral shape.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Geometry
The geometry of a molecule plays a crucial role in determining whether it is polar or non-polar. Molecular geometry refers to the three-dimensional arrangement of atoms in a molecule. It's essential because it affects how the molecule's electrons are distributed, which in turn influences the overall polarity. For instance:
- Linear Geometry: Molecules like CO are linear. In linear molecules, polarity is determined by the difference in electronegativity between the bonded atoms, as there are only two atoms.
- Trigonal Planar Geometry: In molecules like \( \mathrm{BCl}_3 \), the trigonal planar shape allows for symmetrical distribution, often leading to non-polarity if all exterior atoms are identical.
- Tetrahedral Geometry: Both \( \mathrm{CF}_4 \) and \( \mathrm{GeH}_4 \) have a tetrahedral shape, which can cancel out polarities if the surrounding atoms are the same. This symmetry in the shape makes these molecules non-polar.
- Trigonal Pyramidal Geometry: The \( \mathrm{PCl}_3 \) molecule has a trigonal pyramidal shape, causing an asymmetry that can lead to polarity.
Electronegativity
Electronegativity is a measure of how strongly an atom attracts electrons in a covalent bond. The concept of electronegativity is vital for predicting the polarity of molecules. When there is a significant difference in electronegativity between two bonded atoms, the electrons are not shared equally, resulting in a polar bond. Consider the following examples:
- CO: Carbon (2.55) and Oxygen (3.44) have a significant electronegativity difference, making CO polar.
- \( \mathrm{BCl}_3 \): Though B (2.04) and Cl (3.16) have quite a difference, its symmetrical geometry results in a non-polar molecule overall.
- \( \mathrm{CF}_4 \): With carbon (2.55) and fluorine (3.98) having a large difference, each bond is polar; however, the symmetrical tetrahedral shape means that the molecule itself is non-polar.
- \( \mathrm{PCl}_3 \): The difference between phosphorus (2.19) and chlorine (3.16) results in polar bonds, and the molecular shape further supports an overall polar character.
- \( \mathrm{GeH}_4 \): Even with a small difference between germanium (2.01) and hydrogen (2.20), the symmetry of the molecule leads to non-polarity.
Polar and Non-polar Molecules
The polarity of a molecule is a crucial concept in chemistry that determines many of its physical properties and chemical reactivity. A molecule is considered polar if it has a net dipole moment, which arises from uneven electron sharing. On the other hand, non-polar molecules do not have a net dipole moment because the electrons are evenly distributed.
- Polar Example: CO is polar. The carbon is the positive end, while the oxygen is more electronegative, forming the negative end.
- Non-polar Example: \( \mathrm{BCl}_3 \) and \( \mathrm{CF}_4 \) are non-polar despite polar bonds because their shape leads to an even distribution of charge.
- Symmetry’s Role: Shape symmetry can nullify the effects of polar bonds, leading to non-polar molecules, as seen in \( \mathrm{CF}_4 \) and \( \mathrm{GeH}_4 \).
- Polar Example: Additionally, \( \mathrm{PCl}_3 \) remains polar due to an asymmetrical structure leading to a net dipole moment.
Symmetry in Molecules
Symmetry in molecules is a critical factor that can greatly affect their polarity. A symmetrical molecule, especially one with uniform geometry, may end up being non-polar even if it contains polar bonds. This occurs because the dipoles cancel each other out, resulting in no net dipole moment.
In the case of \( \mathrm{BCl}_3 \), symmetry leads to non-polarity despite polar B-Cl bonds, because the planar structure evenly distributes electron density. Similarly, \( \mathrm{CF}_4 \) is non-polar. Though C-F bonds are polar, the tetrahedral symmetry balances out the dipoles.
However, asymmetrical shapes, like those of \( \mathrm{PCl}_3 \), introduce net dipoles since this arrangement doesn't allow complete cancellation of polarity. Polarity often leads to interaction differences, such as \( \mathrm{PCl}_3 \)'s ability to mix with other polar substances, hence its important role in chemical reactions. Assessing symmetry is crucial for concluding a molecule's properties and interactions.
In the case of \( \mathrm{BCl}_3 \), symmetry leads to non-polarity despite polar B-Cl bonds, because the planar structure evenly distributes electron density. Similarly, \( \mathrm{CF}_4 \) is non-polar. Though C-F bonds are polar, the tetrahedral symmetry balances out the dipoles.
However, asymmetrical shapes, like those of \( \mathrm{PCl}_3 \), introduce net dipoles since this arrangement doesn't allow complete cancellation of polarity. Polarity often leads to interaction differences, such as \( \mathrm{PCl}_3 \)'s ability to mix with other polar substances, hence its important role in chemical reactions. Assessing symmetry is crucial for concluding a molecule's properties and interactions.