/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 How do we interpret the physical... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

How do we interpret the physical meaning of the square of the wave function? What are the units of \(4 \pi r^{2} \psi^{2} ?\)

Short Answer

Expert verified
The square of the wave function represents probability density, and \(4\pi r^{2} \psi^{2}\) has units of inverse length.

Step by step solution

01

Understanding the Wave Function

The wave function, commonly represented by \( \psi \), is a fundamental concept in quantum mechanics. It provides information about the probability amplitude of a quantum system's position, among other properties. While \( \psi \) itself may not have a direct physical meaning, its square, \( |\psi|^2 \), does.
02

Determining the Physical Meaning of \( |\psi|^2 \)

The square of the wave function, \( |\psi|^2 \), represents the probability density of finding a particle at a particular point in space. In other words, \( |\psi|^2 \) gives the likelihood per unit volume that a particle is located at a specific position. The concept of probability density is crucial in quantum mechanics as it links the mathematical description (wave function) with observable quantities.
03

Understanding the Expression

The expression \( 4 \pi r^{2} \psi^{2} \) relates the probability density \( |\psi|^2 \) to a spherical shell of radius \( r \). The term \( 4 \pi r^{2} \) is the surface area of a sphere with radius \( r \), and thus \( 4 \pi r^{2} \psi^2 \) corresponds to the probability of finding a particle on a spherical surface.
04

Analyzing Units

To determine the units of \( 4\pi r^{2} \psi^{2} \), consider each component: \( \psi^{2} \) has units of probability per unit volume, while \( r^{2} \) has units of area, usually \( m^2 \). Multiplying these gives the units as probability per unit length, specifically using the spherical shell area context. Thus, the units of \( 4\pi r^{2} \psi^{2} \) can be considered as inverse length.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Function
The wave function, symbolized as \( \psi \), is at the heart of quantum mechanics. It is a mathematical function that describes the quantum state of a particle or system. The wave function provides crucial information, most importantly, the probability amplitude of a particle's position or momentum. It is complex-valued, generally implying both a real and an imaginary component that together give a complete picture of the particle's state. This is important because it allows for the calculation of probabilities through its absolute square.
The absolute square of the wave function, \(|\psi|^2\), conveys physical meaning. It represents the probability density, indicating the likelihood of encountering a particle in a particular region of space. This is vital as it links the mathematical framework to observable phenomena, allowing us to predict the behavior of particles microscopically. In essence, while \(\psi\) itself lacks a direct physical interpretation, \(|\psi|^2\) bridges the gap between abstract theory and measurable reality.
Quantum Mechanics
Quantum mechanics is the branch of physics that deals with the behavior of very small particles, such as electrons, atoms, and photons. Unlike classical physics, which can predict the exact trajectory of a moving body, quantum mechanics is inherently probabilistic. It describes the probability of finding a particle in a certain position or with a certain energy.
In quantum mechanics, the Schrödinger equation governs the dynamics of wave functions. This equation allows us to calculate how \(|\psi|^2\) evolves over time, which provides insights into how a quantum system changes. The probabilistic nature of quantum mechanics means that it often deals in likelihoods or uncertainties, rather than certainties. Therefore, concepts like \(|\psi|^2\) are indispensable, providing a way to predict outcomes within these uncertainties.
  • Particles exhibit wave-particle duality: they can behave like both particles and waves.
  • There is a fundamental limit to the precision with which certain pairs of physical properties, like position and momentum, can be known simultaneously (Heisenberg's uncertainty principle).
  • Measurements affect the system being observed, making it impossible to observe a quantum system without altering it.
Spherical Coordinates
In various applications, particularly in physics, it becomes necessary to describe systems in three dimensions using a coordinate system. Spherical coordinates are useful for this, especially when dealing with problems involving spheres or necessitating symmetry about a point.
The spherical coordinate system represents points in three-dimensional space with three values: radius \(r\), polar angle \(\theta\), and azimuthal angle \(\phi\). Here, \(r\) is the distance from a point to the origin, \(\theta\) measures the angle down from the positive z-axis, and \(\phi\) is the angle in the xy-plane from the positive x-axis.
In quantum mechanics, spherical coordinates often simplify the task of integrating over a spherical volume, particularly when dealing with the hydrogen atom or phenomena involving spherical shells. The expression \(4\pi r^{2}\) is associated with these coordinates as the surface area of a sphere. When combined with \(|\psi|^2\), it gives insight into how probability density distributes over a spherical surface, enabling calculations of where a particle is likely to be found in regions like electron clouds in atomic orbitals.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The radioactive element technetium is not found naturally on earth; it must be synthesized in the laboratory. It is a valuable element, however, because it has medical uses. For example, the element in the form of sodium pertechnetate \(\left(\mathrm{NaTcO}_{4}\right)\) is used in imaging studies of the brain, thyroid, and salivary glands and in renal blood flow studies, among other things. (a) In what group and period of the periodic table is the element found? (b) The valence electrons of technetium are found in the \(5 s\) and \(4 d\) subshells. What is a set of quantum numbers \(\left(n, \ell, \text { and } m_{\ell}\right)\) for one of the electrons of the \(5 s\) subshell? (c) Technetium emits a \(\gamma\) -ray with an energy of \(0.141 \mathrm{MeV} (1 \mathrm{MeV}=10^{6}\) electron-volts, where $$\left.1 \mathrm{eV}=1.6022 \times 10^{-19} \mathrm{J} .\right) \text { What are the wavelength }$$and frequency of a \(\gamma\) -ray photon with an energy of \(0.141 \mathrm{MeV} ?\) (d) To make \(\mathrm{NaTcO}_{4},\) the metal is dissolved in nitric acid. $$\begin{aligned} 7 \mathrm{HNO}_{3}(\mathrm{aq})+& \mathrm{Tc}(\mathrm{s}) \rightarrow \\ & \mathrm{HTcO}_{4}(\mathrm{aq})+7 \mathrm{NO}_{2}(\mathrm{g})+3 \mathrm{H}_{2} \mathrm{O}(\ell) \end{aligned}$$ and the product, HTcO \(_{4}\), is treated with \(\mathrm{NaOH}\) to make \(\mathrm{NaTcO}_{4}\) (i) Write a balanced equation for the reaction of \(\mathrm{HTcO}_{4}\) with \(\mathrm{NaOH}\) (ii) If you begin with 4.5 mg of Tc metal, what mass of \(\mathrm{NaTcO}_{4}\) can be made? What mass of \(\mathrm{NaOH}\), in grams, is required to convert all of the \(\mathrm{HTcO}_{4}\) into \(\mathrm{NaTcO}_{4} ?\) (e) If you synthesize 1.5 micromoles of \(\mathrm{NaTcO}_{4},\) what mass of compound do you have? If the compound is dissolved in \(10.0 \mathrm{mL}\) of solution, what is the concentration?

Cobalt-60 is a radioactive isotope used in medicine for the treatment of certain cancers. It produces \(\beta\) particles and \(\gamma\) rays, the latter having energies of 1.173 and \(1.332 \mathrm{MeV} .\left(1 \mathrm{MeV}=10^{6}\) electron-volts and \right. \(\left.1 \mathrm{eV}=1.6022 \times 10^{-19} \mathrm{J} .\right)\) What are the wavelength and frequency of a \(\gamma\) -ray photon with an energy of 1.173 MeV?

An advertising sign gives off red light and green light. (a) Which light has higher-energy photons? (b) One of the colors has a wavelength of \(680 \mathrm{nm},\) and the other has a wavelength of 500 nm. Which color has which wavelength? (c) Which light has the higher frequency?

Explain briefly why each of the following is not a possible set of quantum numbers for an electron in an atom. (a) \(n=2, \ell=2, m_{\ell}=0\) (b) \(n=3, \ell=0, m_{\ell}=-2\) (c) \(n=6, \ell=0, m_{\ell}=1\)

Radiation in the ultraviolet region of the electromagnetic spectrum is quite energetic. It is this radiation that causes dyes to fade and your skin to develop a sunburn. If you are bombarded with 1.00 mol of photons with a wavelength of 375 nm, what amount of energy, in kilojoules per mole of photons, are you being subjected to?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.