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Define the terms system and surroundings. What does it mean to say that a system and its surroundings are in thermal equilibrium?

Short Answer

Expert verified
A system is the focus of study, while surroundings are everything else. Thermal equilibrium means no net heat flow between them.

Step by step solution

01

Define System

In thermodynamics, a 'system' refers to the part of the universe that is under investigation. It is a defined region of space, or quantity of matter, that is separated from the rest of the universe by a boundary. This boundary can be real or imaginary, and can be fixed or movable.
02

Define Surroundings

The 'surroundings' consist of everything external to the system that can interact with it. Together, the system and the surroundings encompass the entire universe. The surroundings can exchange energy, such as heat, work, or matter, with the system depending on the type of boundary defined.
03

Thermal Equilibrium Explained

When a system and its surroundings are in thermal equilibrium, it means there is no net flow of thermal energy between them. This occurs when both the system and the surroundings are at the same temperature, resulting in no heat transfer across the boundary of the system.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Equilibrium
Understanding thermal equilibrium is crucial in the study of thermodynamics. When we say a system and its surroundings are in thermal equilibrium, it means they are at the same temperature. There is no exchange or net flow of heat energy between them since both sides have reached a balanced state.
This concept is like reaching a peaceful state where no more energy battles occur, as energy is stationary across the boundary.
  • Occurs when temperatures are equal
  • No net heat flow
  • A balanced energy state between system and surroundings
Imagine putting a hot coffee cup in a room. Initially, the coffee is hotter than the room. Over time, it cools down. Eventually, if untouched, both the room and coffee reach the same temperature. That's thermal equilibrium! This concept is essential in processes like heat engines where maintaining or achieving equilibrium affects efficiency.
Thermodynamic Surroundings
The thermodynamic surroundings include everything outside the system under investigation. Essentially, it is all that surrounds the system, contributing to external interactions. Surroundings can influence the system by exchanging heat and matter based on boundaries' nature.
Suppose you heat water in a pot on the stove. Here, the stove, air, and everything not contained in the pot are part of the surroundings.
  • Includes external environment
  • Participates in energy exchanges
  • Affects the system based on contact and boundaries
The surroundings and system together comprise the entire universe from the perspective of thermodynamics. By investigating these surroundings, we learn how external conditions affect the system and how heat and work transfer occur.
Heat Transfer
Heat transfer is the movement of thermal energy from one place to another. It occurs due to temperature differences between systems and surroundings.
There are three main modes of heat transfer: conduction, convection, and radiation.
  • Conduction: Heat moves directly through a substance due to molecular motion and collisions.
  • Convection: Heat transfer via fluid movement driven by temperature differences.
  • Radiation: Transfer of energy through electromagnetic waves without needing a medium.
In any scenario where there’s a temperature difference, these processes will cause energy to move until equilibrium is reached. For instance, heat naturally transfers from the hot drink to your hand and then into the air. Heat transfer mechanisms are integral in weather systems, engines, cooking, and even how our homes are heated.

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Most popular questions from this chapter

In lab, you plan to carry out a calorimetry experiment to determine \(\Delta_{\mathrm{r}} H\) for the exothermic reaction of \(\mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{s})\) and \(\mathrm{HCl}(\mathrm{aq}) .\) Predict how each of the following will affect the calculated value of \(\Delta_{\mathrm{r}} H\). (The value calculated for \(\Delta_{\mathrm{r}} H\) for this reaction is a negative value so choose your answer from the following: \(\Delta_{r} H\) will be too low [that is, a larger negative value], \(\Delta_{\mathrm{r}} H\) will be unaffected, \(\Delta_{\mathrm{r}} H\) will be too high \([\) that is, a smaller negative value. \(]\) )(a) You spill a little bit of the \(\mathrm{Ca}(\mathrm{OH})_{2}\) on the benchtop before adding it to the calorimeter. (b) Because of a miscalculation, you add an excess of HCl to the measured amount of \(\mathrm{Ca}(\mathrm{OH})_{2}\) in the calorimeter. (c) \(\mathrm{Ca}(\mathrm{OH})_{2}\) readily absorbs water from the air. The \(\mathrm{Ca}(\mathrm{OH})_{2}\) sample you weighed had been exposed to the air prior to weighing and had absorbed some water. (d) After weighing out \(\mathrm{Ca}(\mathrm{OH})_{2},\) the sample sat in an open beaker and absorbed water. (e) You delay too long in recording the final temperature. (f) The insulation in your coffee-cup calorimeter was poor, so some energy as heat was lost to the surroundings during the experiment. (g) You have ignored the fact that energy as heat also raised the temperature of the stirrer and the thermometer in your system.

A 182 -g sample of gold at some temperature was added to 22.1 g of water. The initial water temperature was \(25.0^{\circ} \mathrm{C},\) and the final temperature was \(27.5^{\circ} \mathrm{C} .\) If the specific heat capacity of gold is \(0.128 \mathrm{J} / \mathrm{g} \cdot \mathrm{K},\) what was the initial temperature of the gold sample?

Calculate the quantity of energy required to convert \(60.1 \mathrm{g}\) of \(\mathrm{H}_{2} \mathrm{O}(\mathrm{s})\) at \(0.0^{\circ} \mathrm{C}\) to \(\mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) at \(100.0^{\circ} \mathrm{C} .\) The enthalpy of fusion of ice at \(0^{\circ} \mathrm{C}\) is \(333 \mathrm{J} / \mathrm{g}\); the enthalpy of vaporization of liquid water at \(100^{\circ} \mathrm{C}\) is \(2256 \mathrm{J} / \mathrm{g}.\)

After absorbing \(1.850 \mathrm{kJ}\) of energy as heat, the temperature of a \(0.500-\mathrm{kg}\) block of copper is \(37^{\circ} \mathrm{C} .\) What was its initial temperature?

A piece of titanium metal with a mass of \(20.8 \mathrm{g}\) is heated in boiling water to \(99.5^{\circ} \mathrm{C}\) and then dropped into a coffee-cup calorimeter containing \(75.0 \mathrm{g}\) of water at \(21.7^{\circ} \mathrm{C} .\) When thermal equilibrium is reached, the final temperature is \(24.3^{\circ} \mathrm{C} .\) Calculate the specific heat capacity of titanium.

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