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In the "contact process" for making sulfuric acid, sulfur is first burned to \(\mathrm{SO}_{2} .\) Environmental restrictions allow no more than \(0.30 \%\) of this \(\mathrm{SO}_{2}\) to be vented to the atmosphere. (a) If enough sulfur is burned in a plant to produce \(1.80 \times 10^{6} \mathrm{kg}\) of pure, anhydrous \(\mathrm{H}_{2} \mathrm{SO}_{4}\) per day, what is the maximum amount of \(\mathrm{SO}_{2}\) that is allowed to be exhausted to the atmosphere? (b) One way to prevent any \(\mathrm{SO}_{2}\) from reaching the atmosphere is to "scrub" the exhaust gases with slaked lime, \(\mathrm{Ca}(\mathrm{OH})_{2}:\) $$\begin{array}{l} \mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{s})+\mathrm{SO}_{2}(\mathrm{g}) \rightarrow \mathrm{CaSO}_{3}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(\ell) \\ 2 \mathrm{CaSO}_{3}(\mathrm{s})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{CaSO}_{4}(\mathrm{s}) \end{array}$$ What mass of \(\mathrm{Ca}(\mathrm{OH})_{2}\) (in kilograms) is needed to remove the SO \(_{2}\) calculated in part (a)?

Short Answer

Expert verified
(a) 3.54 x 10鲁 kg SO鈧; (b) 4.09 x 10鲁 kg Ca(OH)鈧 needed.

Step by step solution

01

Calculate the amount of sulfuric acid produced

First, calculate the amount of sulfur in sulfuric acid (H鈧係O鈧). The molar mass of H鈧係O鈧 is 98.08 g/mol. Thus, 1.80 x 10鈦 kg of H鈧係O鈧 equals \(1.80 \times 10^6 \text{ kg} \times \frac{1000 \text{ g}}{1 \text{ kg}} \times \frac{1 \text{ mol}}{98.08 \text{ g/mol}} \approx 1.84 \times 10^4 \text{ kmol H}_2\text{SO}_4\) produced per day.
02

Calculate the amount of SO鈧 initially required

Each mole of H鈧係O鈧 requires 1 mole of SO鈧. Therefore, the number of moles of SO鈧 initially required is \(1.84 \times 10^4 \text{ kmol}\). To find the mass, multiply by the molar mass of SO鈧, which is 64.07 g/mol: \(1.84 \times 10^4 \text{ kmol} \times 64.07 \text{ g/mol} = 1.18 \times 10^6 \text{ kg SO}_2\).
03

Calculate the maximum allowed SO鈧 vented

Only 0.30% of the SO鈧 can be vented, so calculate this as \(0.003 \times 1.18 \times 10^6 \text{ kg} = 3.54 \times 10^3 \text{ kg SO}_2\) that can be released to the atmosphere.
04

Determine the mass of Ca(OH)鈧 required

The balanced reaction shows that 1 mole of Ca(OH)鈧 reacts with 1 mole of SO鈧. Calculate the number of moles of SO鈧 to be removed: \(3.54 \times 10^3 \text{ kg} \times \frac{10^6 \text{ g}}{1 \text{ kg}} \times \frac{1 \text{ mol}}{64.07 \text{ g/mol}} \approx 5.52 \times 10^4 \text{ mol}\). Using the molar mass of Ca(OH)鈧 (74.09 g/mol), the mass needed is \(5.52 \times 10^4 \text{ mol} \times 74.09 \text{ g/mol} / 1000 = 4.09 \times 10^3 \text{ kg} \text{ of Ca(OH)}_2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Contact Process
Sulfuric acid is one of the most important industrial chemicals, and the Contact Process is a major way of producing it. This method involves burning sulfur to form sulfur dioxide \( \text{SO}_2 \), which is then converted into sulfur trioxide \( \text{SO}_3 \) through catalytic reactions. Mixing \( \text{SO}_3 \) with water ultimately produces sulfuric acid \( \text{H}_2\text{SO}_4 \).

The process begins by burning elemental sulfur to form \( \text{SO}_2 \). This reaction is highly exothermic and produces significant amounts of heat. The sulfur dioxide formed is then passed over a vanadium(V) oxide catalyst at high temperatures, typically between 400掳C and 600掳C, to facilitate the conversion to sulfur trioxide. The key reactions involved are:
  • \( \text{S} + \text{O}_2 \rightarrow \text{SO}_2 \)
  • \( 2\, \text{SO}_2 + \text{O}_2 \rightarrow 2\, \text{SO}_3 \)
Finally, \( \text{SO}_3 \) is absorbed in concentrated \( \text{H}_2\text{SO}_4 \) to create the oleum, which is then diluted with water to yield sulfuric acid.

Each step in the Contact Process is carefully controlled to maximize yield and minimize emissions, making it a more environmentally friendly method than some older processes.
Environmental Chemistry
In the realm of environmental chemistry, managing and minimizing industrial emissions is a critical concern. The sulfur dioxide produced in the Contact Process is a significant air pollutant, contributing to acid rain and respiratory problems in living organisms. Consequently, environmental regulations strictly limit the permissible amount of \( \text{SO}_2 \) that can be released into the atmosphere.

Industries are often required to implement scrubbing technologies to reduce \( \text{SO}_2 \) emissions. In our exercise, only 0.30% of \( \text{SO}_2 \) can be vented, meaning that a considerable amount must be managed effectively to prevent environmental damage. Regulations like this are crucial in maintaining air quality and protecting the environment. Understanding these regulations and the chemical processes involved can help industries comply and contribute to global environmental efforts.
SO2 Scrubbing
\( \text{SO}_2 \) scrubbing is an essential technique employed to control air pollution from sulfur sources. This process involves the removal of sulfur dioxide from exhaust gases before they are released into the atmosphere, typically using substances like slaked lime (calcium hydroxide).

The chemical reaction in scrubbers converts \( \text{SO}_2 \), a gaseous pollutant, into a calcium sulfite solid, which can then be managed and disposed of safely. The main reactions are as follows:
  • \( \text{Ca(OH)}_2(\text{s}) + \text{SO}_2(\text{g}) \rightarrow \text{CaSO}_3(\text{s}) + \text{H}_2\text{O}(\ell) \)
  • \( 2\, \text{CaSO}_3(\text{s}) + \text{O}_2(\text{g}) \rightarrow 2\, \text{CaSO}_4(\text{s}) \)
By converting \( \text{SO}_2 \) into a stable compound, the scrubbing process helps in reducing the environmental impact of sulfur emissions. The scrubbed substances can sometimes be repurposed; calcium sulfate, formed during the process, can be used in the production of plaster and other materials. This conversion not only helps in reducing pollution but also provides a sustainable way to manage emissions.

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Most popular questions from this chapter

Calcium reacts with hydrogen gas at \(300-400^{\circ} \mathrm{C}\) to form a hydride. This compound reacts readily with water, so it is an excellent drying agent for organic solvents. (a) Write a balanced equation showing the formation of calcium hydride from Ca and \(\mathrm{H}_{2}\) (b) Write a balanced equation for the reaction of calcium hydride with water (Figure 21.7 ).

To prepare chlorine from chloride ion a strong oxidizing agent is required. The dichromate ion, \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-},\) is one example (Figure 21.32 ). Consult the table of standard reduction potentials (Appendix \(\mathbf{M}\) ), and identify several other oxidizing agents that may be suitable. Write balanced equations for the reactions of these substances with chloride ion.

Give examples of two acidic oxides. Write equations illustrating the formation of each oxide from its component elements. Write another chemical equation that illustrates the acidic character of each oxide.

Select one of the alkali metals, and write a balanced chemical equation for its reaction with chlorine. Is the reaction likely to be exothermic or endothermic? Is the product ionic or molecular?

Phosphorus forms an extensive series of oxoanions. (a) Draw a structure, and give the charge for an oxophosphate anion with the formula \(\left[\mathrm{P}_{4} \mathrm{O}_{13}\right]^{\mathrm{n}-} .\) How many ionizable H atoms should the completely protonated acid have? (b) Draw a structure, and give the charge for an oxophosphate anion with the formula \(\left[\mathrm{P}_{4} \mathrm{O}_{12}\right]^{\mathrm{n}-} .\) How many ionizable \(\mathrm{H}\) atoms should the completely protonated acid have?

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