Chapter 20: Problem 25
Calculate the potential delivered by a voltaic cell using the following reaction if all dissolved species are \(2.5 \times 10^{-2} \mathrm{M}\) and the pressure of \(\mathrm{H}_{2}\) is 1.0 bar. $$\begin{aligned} \mathrm{Zn}(\mathrm{s})+2 \mathrm{H}_{2} \mathrm{O}(\ell)+2 \mathrm{OH}^{-}(\mathrm{aq}) & \rightarrow \\ &\left[\mathrm{Zn}(\mathrm{OH})_{4}\right]^{2-}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{g}) \end{aligned}$$
Short Answer
Step by step solution
Identify the Half-Reactions
Find Standard Electrode Potentials
Calculate Standard Cell Potential
Apply Nernst Equation
Calculate Reaction Quotient \(Q\)
Solve for \(E_{cell}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Voltaic cell calculation
Starting with our reaction, we separate it into two half-reactions:
- Oxidation at the anode: \( \mathrm{Zn}(\mathrm{s}) + 4\mathrm{OH}^- \rightarrow \left[\mathrm{Zn}(\mathrm{OH})_4\right]^{2-} + 2e^- \)
- Reduction at the cathode: \( 2\mathrm{H}_2O + 2e^- \rightarrow \mathrm{H}_2(g) + 2\mathrm{OH}^- \)
The potential difference (voltage) calculation is a multi-step process, starting with finding the standard cell potential \(E^0_{cell}\) using the equation:\[E^0_{cell} = E^0_{cathode} - E^0_{anode}\]where the standard potentials are taken from known data.
Nernst equation applications
For the given exercise, once you've determined the standard cell potential, \(E^0_{cell}\), it is time to use the Nernst equation:\[E_{cell} = E^0_{cell} - \frac{RT}{nF} \ln{Q}\]where:
- \(E_{cell}\) is the actual cell potential
- \(R\) is the universal gas constant \(8.314 \, \mathrm{J/mol}\, K\)
- \(T\) is the temperature in Kelvin
- \(n\) is the number of moles of electrons transferred
- \(F\) is the Faraday constant \(96485 \, \mathrm{C/mol}\)
- \(Q\) is the reaction quotient
Standard electrode potentials
In the provided exercise, the standard reduction potential values, \(E^0\), were used to identify the tendency of half-reactions to gain or lose electrons. The more positive the electrode potential, the greater the substance's affinity to gain electrons and act as a good oxidizing agent. Conversely, a more negative potential suggests a stronger reducing capability.
With zinc's standard reduction potential near \(-0.76 \, \mathrm{V}\) and water's reduction to \(\mathrm{H}_2\) being around \(-0.83 \, \mathrm{V}\), these two metals' standard electrode potentials helped us arrive at a standard cell potential of \(-0.07 \, \mathrm{V}\) for the complete cell in this electrochemical setup. This foundational understanding is crucial for applying the Nernst equation and making further predictions about cell behavior under varied conditions.