/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 What mass is represented by 0.02... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What mass is represented by 0.0255 mol of each of the following compounds? (a) \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH},\) 2-propanol, rubbing alcohol (b) \(\mathrm{C}_{11} \mathrm{H}_{16} \mathrm{O}_{2},\) an antioxidant in foods, also known as BHA (butylated hydroxyanisole) (c) \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4},\) aspirin (d) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO},\) acetone, an important industrial solvent

Short Answer

Expert verified
0.0255 moles represent masses of 1.53355 g (2-propanol), 4.5951 g (BHA), 4.59108 g (aspirin), and 1.48204 g (acetone).

Step by step solution

01

Calculate Molar Mass for C3H7OH (2-Propanol)

Firstly, we need to determine the molar mass of 2-propanol, \(\mathrm{C}_{3}\mathrm{H}_{7}\mathrm{OH}\). The atomic weights are: C = 12.01, H = 1.008, O = 16.00. The molar mass will be calculated as follows: \(3 \times 12.01 + 8 \times 1.008 + 16.00 = 60.10\ \mathrm{g/mol}\) (note: \(8 \times 1.008\) accounts for the OH group in addition to the 7 hydrogens).
02

Calculate Mass for 0.0255 mol of C3H7OH

To find the mass of 0.0255 moles of 2-propanol, use the formula: \(\text{mass} = \text{moles} \times \text{molar mass}\). So, we calculate: \(0.0255 \times 60.10 = 1.53355\ \mathrm{g}\).
03

Calculate Molar Mass for C11H16O2 (BHA)

Next, calculate the molar mass for BHA, \(\mathrm{C}_{11}\mathrm{H}_{16}\mathrm{O}_{2}\). The atomic weights are: C = 12.01, H = 1.008, O = 16.00. Hence, \(11 \times 12.01 + 16 \times 1.008 + 2 \times 16.00 = 180.24\ \mathrm{g/mol}\).
04

Calculate Mass for 0.0255 mol of C11H16O2

Use the formula \(\text{mass} = \text{moles} \times \text{molar mass}\) to find the mass: \(0.0255 \times 180.24 = 4.5951\ \mathrm{g}\).
05

Calculate Molar Mass for C9H8O4 (Aspirin)

Determine the molar mass of aspirin, \(\mathrm{C}_{9}\mathrm{H}_{8}\mathrm{O}_{4}\). The atomic weights are: C = 12.01, H = 1.008, O = 16.00. Calculate: \(9 \times 12.01 + 8 \times 1.008 + 4 \times 16.00 = 180.16\ \mathrm{g/mol}\).
06

Calculate Mass for 0.0255 mol of C9H8O4

Using the formula \(\text{mass} = \text{moles} \times \text{molar mass}\), we find the mass as: \(0.0255 \times 180.16 = 4.59108\ \mathrm{g}\).
07

Calculate Molar Mass for (CH3)2CO (Acetone)

Determine the molar mass for acetone, \((\mathrm{CH}_{3})_{2}\mathrm{CO}\). Atomic weights are: C = 12.01, H = 1.008, O = 16.00. The calculation is \(3 \times 12.01 + 6 \times 1.008 + 16.00 = 58.08\ \mathrm{g/mol}\).
08

Calculate Mass for 0.0255 mol of (CH3)2CO

Finally, use the formula \(\text{mass} = \text{moles} \times \text{molar mass}\) to calculate: \(0.0255 \times 58.08 = 1.48204\ \mathrm{g}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

2-propanol
2-Propanol, commonly known as isopropanol or rubbing alcohol, is a colorless compound with the formula \(\mathrm{C}_3\mathrm{H}_7\mathrm{OH}\). It is widely used as a disinfectant and a solvent. To calculate the molar mass of 2-propanol, we start by considering the atomic weights:
  • Carbon (C): 12.01 g/mol
  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 16.00 g/mol
The compound contains 3 carbon atoms, 8 hydrogen atoms (including the OH group), and 1 oxygen atom. The molar mass is thus calculated as \[ 3 \times 12.01 + 8 \times 1.008 + 16.00 = 60.10 \ g/mol \] To find out the mass of 0.0255 moles of 2-propanol, use the formula: \[ \text{mass} = \text{moles} \times \text{molar mass} \] Substituting the values, we get \[ 0.0255 \times 60.10 = 1.53355 \ g \]. This shows that 0.0255 moles of 2-propanol has a mass of approximately 1.5336 grams.
butylated hydroxyanisole (BHA)
Butylated hydroxyanisole, or BHA, is a synthetic antioxidant with the chemical formula \(\mathrm{C}_{11}\mathrm{H}_{16}\mathrm{O}_2\). It is often used to prevent spoilage in food products due to its properties that inhibit oxidation. To determine its molar mass, we use:
  • Carbon (C): 12.01 g/mol
  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 16.00 g/mol
The calculation involves 11 carbon atoms, 16 hydrogen atoms, and 2 oxygen atoms, which results in\[ 11 \times 12.01 + 16 \times 1.008 + 2 \times 16.00 = 180.24 \ g/mol \] The mass of 0.0255 moles of BHA can be calculated using: \[ \text{mass} = \text{moles} \times \text{molar mass} \]Thus, \[ 0.0255 \times 180.24 = 4.5951 \ g \]This means 0.0255 moles of BHA weighs approximately 4.595 grams.
aspirin
Aspirin, chemically known as acetylsalicylic acid, has the formula \(\mathrm{C}_{9}\mathrm{H}_{8}\mathrm{O}_4\). It is one of the most common medications used worldwide for pain relief, reducing fever, and as an anti-inflammatory. The molecular composition comprises the following atomic components:
  • Carbon (C): 12.01 g/mol
  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 16.00 g/mol
For the molar mass calculation, aspirin contains 9 carbons, 8 hydrogens, and 4 oxygens, giving\[ 9 \times 12.01 + 8 \times 1.008 + 4 \times 16.00 = 180.16 \ g/mol \] The mass for 0.0255 moles of aspirin can be calculated as:\[ \text{mass} = \text{moles} \times \text{molar mass} \]So,\[ 0.0255 \times 180.16 = 4.59108 \ g \]Hence, 0.0255 moles of aspirin has a mass close to 4.591 grams.
acetone
Acetone is a simple organic compound with the formula \((\mathrm{CH}_3)_2\mathrm{CO}\). It is widely known as a solvent and is used in many industrial applications and also as the main ingredient in nail polish remover. The calculation of its molar mass involves:
  • Carbon (C): 12.01 g/mol
  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 16.00 g/mol
Acetone consists of 3 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom, leading to\[ 3 \times 12.01 + 6 \times 1.008 + 16.00 = 58.08 \ g/mol \] To find the mass of 0.0255 moles of acetone:\[ \text{mass} = \text{moles} \times \text{molar mass} \] This gives\[ 0.0255 \times 58.08 = 1.48204 \ g \]Thus, 0.0255 moles of acetone weigh about 1.482 grams.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The highest mass peaks in the mass spectrum of \(\mathrm{Br}_{2}\) occur at \(m / Z 158,160,\) and \(162 .\) The ratio of intensities of these peaks is approximately \(1: 2: 1 .\) Bromine has two stable isotopes, \(^{79} \mathrm{Br}(50.7 \% \text { abundance })\) and \(^{81} \mathrm{Br}\) \((49.3 \% \text { abundance })\) (a) What molecular species gives rise to each of these peaks? (b) Explain the relative intensities of these peaks. (Hint: Consider the probabilities of each atom combination.)

Ionic and molecular compounds of the halogens. (a) What are the names of \(\mathrm{BaF}_{2}, \mathrm{SiCl}_{4},\) and \(\mathrm{NiBr}_{2} ?\) (b) Which of the compounds in part (a) are ionic, and which are molecular? (c) Which has the larger mass, 0.50 mol of \(\mathrm{BaF}_{2}\) 0.50 mol of \(\mathrm{SiCl}_{4},\) or 1.0 mol of \(\mathrm{NiBr}_{2} ?\)

Iron pyrite, often called "fool's gold," has the formula FeS\(_{2} .\) If you could convert \(15.8 \mathrm{kg}\) of iron pyrite to iron metal, what mass of the metal would your obtain?

You combine 1.25 g of germanium, Ge, with excess chlorine, \(\mathrm{Cl}_{2} .\) The mass of product, \(\mathrm{Ge}_{x} \mathrm{Cl}_{y},\) is \(3.69 \mathrm{g}\) What is the formula of the product, Ge, \(\mathrm{Cl}_{y}\) ?

Mandelic acid is an organic acid composed of carbon \((63.15 \%),\) hydrogen \((5.30 \%),\) and oxygen \((31.55 \%) .\) Its molar mass is \(152.14 \mathrm{g} / \mathrm{mol} .\) Determine the empirical and molecular formulas of the acid.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.