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In each of the following cases, decide whether a precipitate will form when mixing the indicated reagents, and write a balanced equation for the reaction. (a) \(\mathrm{NaBr}(\mathrm{aq})+\mathrm{AgNO}_{3}(\mathrm{aq})\) (b) \(\mathrm{KCl}(\mathrm{aq})+\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})\)

Short Answer

Expert verified
Precipitates form in both cases: AgBr and PbCl鈧 are the precipitates.

Step by step solution

01

Determine ion combinations

When mixing solutions, the ions from each compound dissolve in water and float around. For each pair of reactants, identify the possible cation-anion combinations that may form precipitates. These combinations are: (a) NaBr (aq) + AgNO鈧 (aq): Na鈦, Br鈦, Ag鈦, NO鈧冣伝 which combine to form NaNO鈧 and AgBr. (b) KCl (aq) + Pb(NO鈧)鈧 (aq): K鈦, Cl鈦, Pb虏鈦, NO鈧冣伝 which combine to form KNO鈧 and PbCl鈧.
02

Apply solubility rules

Use solubility rules to check if any of the combinations result in a precipitate: (a) According to solubility rules, AgBr is insoluble in water while NaNO鈧 is soluble. Thus, AgBr will form as a precipitate. (b) PbCl鈧 is insoluble in water, as per solubility rules, while KNO鈧 is soluble. Hence, PbCl鈧 will form as a precipitate.
03

Write balanced chemical equations

For the reactions that form a precipitate, write down the balanced chemical equation: (a) NaBr (aq) + AgNO鈧 (aq) 鈫 AgBr (s) + NaNO鈧 (aq) (b) 2KCl (aq) + Pb(NO鈧)鈧 (aq) 鈫 PbCl鈧 (s) + 2KNO鈧 (aq)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility Rules
Understanding solubility rules is essential when predicting the formation of precipitates in chemical reactions. These rules are guidelines that help us know whether an ionic compound will dissolve in water.
Key Points about Solubility Rules:
  • Compounds containing sodium (Na鈦), potassium (K鈦), and nitrate (NO鈧冣伝) ions are generally soluble in water.
  • Most chlorides (Cl鈦), bromides (Br鈦), and iodides (I鈦) are soluble, except when paired with silver (Ag鈦), lead (Pb虏鈦), or mercury (Hg鈧偮测伜).
  • Sulfates (SO鈧劼测伝) are usually soluble, with exceptions like calcium sulfate (CaSO鈧), barium sulfate (BaSO鈧), and lead sulfate (PbSO鈧).
  • Carbonates (CO鈧兟测伝), phosphates (PO鈧劼斥伝), and sulfides (S虏鈦) are typically insoluble, except when with alkali metals (like Na鈦, K鈦) or ammonium (NH鈧勨伜).
These rules provide a quick reference to determine if a compound forms a soluble solution or a solid, known as a precipitate, during reactions. Knowing solubility rules helps predict the outcome of mixing various ionic solutions.
Chemical Equations
Chemical equations are expressions that describe the transformation of reactants into products in a chemical reaction. They provide a concise way to communicate chemical changes.
Start recognizing reactants and products on either side of the equation:
  • Reactants are substances you begin with, on the left side of the equation.
  • Products are the substances formed, listed on the right side.
A balanced chemical equation adheres to the law of conservation of mass, meaning the number of atoms for each element must be the same on both sides.
Example:
  • For AgBr formation: \(\text{NaBr (aq) + AgNO}_3 \text{(aq) 鈫 AgBr (s) + NaNO}_3 \text{(aq)}\)
  • For PbCl鈧 formation: \(2\text{KCl (aq) + Pb(NO}_3\text{)}_2\text{(aq) 鈫 PbCl}_2\text{(s) + 2KNO}_3\text{(aq)}\)
Each equation shows reactants converted to products, with states (solid \((s)\), liquid \((l)\), aqueous \((aq)\), gas \((g)\)) in parentheses to indicate the physical state of each compound.
Cation-Anion Combinations
Cation-anion combinations occur when positively charged ions (cations) and negatively charged ions (anions) associate to form compounds. In aqueous solutions, ions dissociate and can recombine when different solutions are mixed.
  • Cations within the exercise include Na鈦, K鈦, Ag鈦, and Pb虏鈦.
  • Anions include Br鈦, Cl鈦, and NO鈧冣伝.
These ions in separate solutions can mix and form new combinations. Such mixing can lead to products like insoluble compounds, precipitating out of the solution.
In the examples given, the cation of one reactant meets the anion of the other, resulting in either soluble or insoluble compounds. For instance:
  • Na鈦 + NO鈧冣伝 form soluble NaNO鈧.
  • Ag鈦 + Br鈦 form the insoluble compound AgBr (precipitate).
  • K鈦 + NO鈧冣伝 form soluble KNO鈧.
  • Pb虏鈦 + Cl鈦 form the insoluble compound PbCl鈧 (precipitate).
This process shows why knowing ion combinations is critical for predicting the formation of a precipitation.
Insoluble Compounds
Insoluble compounds are those that do not dissolve significantly in water, resulting in the formation of a solid precipitate when solutions combine during a reaction. Understanding why certain compounds are insoluble helps in predicting the outcome of an ionic reaction.
Substances with certain ion pairs, like silver bromide (AgBr) or lead chloride (PbCl鈧), are known to be insoluble. Upon interaction:
  • AgBr is formed when Ag鈦 and Br鈦 combine, precipitating as a solid because it does not dissolve in water.
  • PbCl鈧 forms under similar circumstances from Pb虏鈦 and Cl鈦, appearing as a solid precipitate.
Not all ionic compounds will dissolve when introduced to water, leading to substances that appear as precipitates, which can be visible as cloudy forms in the mixture. Recognizing which compounds are likely to be insoluble allows for the prediction of a reaction鈥檚 visual outcome and the identification of resultant products.

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Most popular questions from this chapter

A sample of hard water contains about \(2.0 \times 10^{-3} \mathrm{M}\) \(\mathrm{Ca}^{2+} .\) A soluble fluoride-containing salt such as NaF is added to "fluoridate" the water (to aid in the prevention of dental cavities). What is the maximum concentration of \(\mathrm{F}^{-}\) that can be present without precipitating \(\mathrm{CaF}_{2} ?\) (IMAGE CAN'T COPY)

A buffer solution is prepared by adding 0.125 mol of ammonium chloride to \(5.00 \times 10^{2} \mathrm{mL}\) of \(0.500 \mathrm{M}\) solution of ammonia. (a) What is the pH of the buffer? (b) If 0.0100 mol of \(\mathrm{HCl}\) gas is bubbled into \(5.00 \times 10^{2}\) mL of the buffer, what is the new \(\mathrm{pH}\) of the solution?

Construct a rough plot of \(\mathrm{pH}\) versus volume of base for the titration of \(25.0 \mathrm{mL}\) of \(0.050 \mathrm{M} \mathrm{HCN}\) with \(0.075 \mathrm{M}\) \(\mathrm{NaOH}.\) (a) What is the pH before any \(\mathrm{NaOH}\) is added? (b) What is the pH at the halfway point of the titration? (c) What is the pH when \(95 \%\) of the required \(\mathrm{NaOH}\) has been added? (d) What volume of base, in milliliters, is required to reach the equivalence point? (e) What is the \(\mathrm{pH}\) at the equivalence point? (f) What indicator would be most suitable for this titration? (See Figure 18.10 .) (g) What is the pH when \(105 \%\) of the required base has been added?

Predict whether each of the following is insoluble or soluble in water. (a) \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\) (b) \(\mathrm{Fe}(\mathrm{OH})_{3}\) (c) \(\mathrm{ZnCl}_{2}\) (d) CuS

Without doing detailed calculations, sketch the curve for the titration of \(30.0 \mathrm{mL}\) of \(0.10 \mathrm{M} \mathrm{NaOH}\) with 0.10 M HCl. Indicate the approximate \(\mathrm{pH}\) at the beginning of the titration and at the equivalence point. What is the total solution volume at the equivalence point?

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