Chapter 27: Problem 2
Which of the following molecules are polar? (a) \(\mathrm{CH}_{3} \mathrm{Cl}\) (b) \(\mathrm{CH}_{2} \mathrm{Cl}_{2} ;(\mathrm{c}) \mathrm{SO}_{3}:(\mathrm{d}) \mathrm{HCHO}\) (e) \(\mathrm{HBr}\) (f) \(\mathrm{H}_{2} \mathrm{O} ;(\mathrm{g}) \mathrm{CH}_{3} \mathrm{OH}\) (h) \(\mathrm{CBr}_{4}\)
Short Answer
Step by step solution
Understand Polarity
Analyze Molecule (a)
Analyze Molecule (b)
Analyze Molecule (c)
Analyze Molecule (d)
Analyze Molecule (e)
Analyze Molecule (f)
Analyze Molecule (g)
Analyze Molecule (h)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electronegativity
This creates a region of partial negative charge around the more electronegative atom, while the less electronegative atom exhibits a partial positive charge. This separation of charge within a molecule is what we call a dipole.
- In molecules like \[\mathrm{H_2O} \] and \[\mathrm{HBr}, \] differences in electronegativity between hydrogen and oxygen or bromine result in polar bonds.
- Chlorine in \[\mathrm{CH_3Cl} \] and \[\mathrm{CH_2Cl_2} \] is highly electronegative, leading to polar bonds with carbon.
Dipole Moment
The larger the electronegativity differences between the bonded atoms and the more asymmetrical its shape, the more likely the molecule will have a significant dipole moment. This results in the phenomenon of molecular polarity.
- \[\mathrm{H_2O} \] has a significant dipole moment due to its bent shape and the difference in electronegativity between hydrogen and oxygen, making it a classic example of a polar molecule.
- \[\mathrm{SO_3} \], despite possessing polar bonds, is nonpolar because its symmetrical trigonal planar geometry cancels out any net dipole moment.
Molecular Geometry
For instance, in a molecule like \[\mathrm{CBr_4}, \] the geometry is tetrahedral. Despite having polar \[\mathrm{C-Br} \] bonds, the symmetry of this shape means that the dipoles point equally in opposite directions and cancel out, leading to a nonpolar molecule.
- In contrast, \[\mathrm{CH_3OH} \] has a less symmetrical form. The polar \[\mathrm{O-H} \] bond adds to the asymmetry, resulting in a net dipole moment and a polar molecule.
- \[\mathrm{HCHO} \] is polar due to its trigonal planar shape, which doesn't allow for the cancellation of its dipole moments.
Symmetry
- For instance, \[\mathrm{SO_3} \] has three \[\mathrm{S=O} \] bonds arranged in a trigonal planar shape, and although each bond is polar, they cancel out due to symmetry, resulting in no net dipole moment.
- \[\mathrm{CBr_4}\] is another example where the symmetry of the tetrahedral geometry causes the dipoles from each \[\mathrm{C-Br} \] bond to cancel out completely.