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In chemistry, solution concentration indicates the amount of solute present in a given quantity of solvent. It is usually represented in different forms such as molarity, molality, or mass/volume percentage (m/v). In this exercise, we are dealing with mass/volume percentage. This means the concentration is the mass of the solute (glucose, in this case) per 100 mL of solution. For instance, a 25% (m/v) glucose solution contains 25 grams of glucose in every 100 mL of solution. To summarize:

• A higher concentration means more solute in the given volume of solution.
• It's crucial to know the concentration to accurately prepare new solutions by dilution.

Understanding solution concentration is vital for performing accurate calculations in various chemical applications including this problem.

The dilution formula is a handy equation used to calculate dilutions in chemistry. It allows us to determine how much of a concentrated solution is needed to achieve a desired concentration. The formula is expressed as: \[C_1 \times V_1 = C_2 \times V_2\]where:

• \(C_1\) is the initial concentration of the stock solution.
• \(V_1\) is the volume of the stock solution you need to use.
• \(C_2\) is the final concentration you want to achieve.
• \(V_2\) is the final volume of the diluted solution.

This equation implies that the product of the initial concentration and volume equals the product of the final concentration and volume. It ensures that the amount of solute remains constant before and after dilution. Using the given problem: A 25% glucose solution (\(C_1\)) diluted to achieve 500 mL of a 5% glucose solution (\(C_2\), final volume \(V_2\)) helped us solve for the unknown volume (\(V_1\)) of the concentrated stock solution needed. The equation becomes: \[25 \times V_1 = 5 \times 500 \]When solved yields \(V_1 = 100\) mL.

A glucose solution involves dissolving glucose (a simple sugar) in water. It's commonly used in various fields such as biology, chemistry, and medicine. The concentration of a glucose solution can be crucial for experiments and treatments. Here’s an overview of key points to remember:

• Glucose (\(C_6H_{12}O_6\)) is an essential nutrient for cell metabolism.
• In medical settings, glucose solutions are used for intravenous drips to provide energy to patients.
• In laboratories, glucose solutions are utilized in biochemical assays and culture media.

In the given problem, a 5% (m/v) glucose solution is prepared from a more concentrated 25% (m/v) solution by dilution. We calculated that 100 mL of the 25% glucose solution is mixed with water to achieve a final volume of 500 mL at a 5% concentration. This process involves understanding how to use the dilution formula effectively to achieve the desired concentration.