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a. An athlete with a body mass of \(65 \mathrm{~kg}\) has \(3.0 \%\) body fat. How many pounds of body fat does that person have? (2.6) b. In liposuction, a doctor removes fat deposits from a person's body. If body fat has a density of \(0.909 \mathrm{~g} / \mathrm{mL}\) and \(3.0 \mathrm{~L}\) of fat is removed, how many pounds of fat were removed from the patient?

Short Answer

Expert verified
a. 4.299 lb of body fatb. 6.006 lb of fat removed

Step by step solution

01

Convert body mass to pounds

First, convert the athlete's body mass from kilograms to pounds. Since there are approximately 2.20462 pounds in 1 kilogram, we use the conversion factor: \[ 65 \text{ kg} \times 2.20462 \text{ lb/kg} = 143.3 \text{ lb} \]
02

Calculate the mass of body fat

Next, calculate the mass of the body fat by taking \(3.0\%\) of the total body mass. This can be done as follows: \[ 143.3 \text{ lb} \times 0.03 = 4.299 \text{ lb} \]
03

Convert density to consistent units

For part b, start by ensuring all units are consistent. The density of body fat is given as \(0.909 \text{ g/mL}\). Convert this to pounds per liter. Knowing \(1 \text{ g} = 0.00220462 \text{ lb}\) and \(1 \text{ mL} = 0.001 \text{ L}\), we have: \[ 0.909 \text{ g/mL} \times 0.00220462 \text{ lb/g} \times 1000 \text{ mL/L} = 2.002 \text{ lb/L} \]
04

Calculate the pounds of fat removed

Now, use the converted density to find out how many pounds of fat were removed: \[ 2.002 \text{ lb/L} \times 3.0 \text{ L} = 6.006 \text{ lb} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Unit conversion is essential when working with different measurement systems, such as the metric system (kilograms, liters, etc.) and the imperial system (pounds, ounces, etc.). In the example exercise, we converted body mass from kilograms to pounds. We use a conversion factor to do this. Specifically, 1 kilogram is approximately equal to 2.20462 pounds.

To convert 65 kilograms to pounds, we multiply the mass of 65 kg by the conversion factor: \( 65 \text{ kg} \times 2.20462 \text{ lb/kg} = 143.3 \text{ lb} \).

Conversion factors serve as a bridge between two different units. Always make sure that the units cancel out correctly, leaving the desired unit. Besides weights, conversions can involve volume and other physical quantities. This is crucial for precise calculations.
Density
Density is a measure of mass per unit volume, often expressed in units like grams per milliliter (g/mL) or kilograms per liter (kg/L). It helps describe how much mass is contained in a given volume.

For example, in the exercise, the density of body fat was given as 0.909 g/mL. To work with different units or contexts, we sometimes need to convert this density to a different unit, like pounds per liter (lb/L).

The conversion involves:
  • Multiplying by the conversion factor from grams to pounds \( (1 \text{ g} = 0.00220462 \text{ lb}) \)
  • Adjusting for the conversion between milliliters and liters \( (1 \text{ L} = 1000 \text{ mL}) \)
So, the conversion for the density is: \( 0.909 \text{ g/mL} \times 0.00220462 \text{ lb/g} \times 1000 \text{ mL/L} = 2.002 \text{ lb/L} \).

Accurate unit conversion ensures the outcome is in the suitable format for further calculations or practical use.
Percentage
Percentages are used to express parts of a whole as a fraction of 100. In the exercise, the athlete has 3.0% body fat, meaning that 3.0% of the whole body mass is fat.

To calculate this, we take the total body mass (in this case, 143.3 pounds) and multiply it by the percentage in decimal form. The decimal form of 3.0% is 0.03: \( 143.3 \text{ lb} \times 0.03 = 4.299 \text{ lb} \).

This calculation provides the mass of body fat, which is a small portion of the total body mass. Percentages are crucial in various calculations, such as determining concentrations, rates of change, and proportions in everyday contexts.
Mass Calculations
Mass calculations involve determining the amount of matter in an object or substance, often expressed in units like grams (g), kilograms (kg), or pounds (lb).

For example, to find the mass of fat removed in a liposuction procedure, we use the density of body fat (in lb/L) and the volume removed (in L).

If 3.0 liters of fat is removed, with a given density of 2.002 lb/L, the calculation is straightforward: \( 2.002 \text{ lb/L} \times 3.0 \text{ L} = 6.006 \text{ lb} \).

This determines the total mass of fat in pounds removed from the body. Such straightforward calculations are commonly used in medical, scientific, and various practical applications to quantify substance amounts precisely.

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Most popular questions from this chapter

What is the density \((\mathrm{g} / \mathrm{mL})\) of each of the following samples? a. A lightweight head on a golf club is made of titanium. The volume of a sample of titanium is \(114 \mathrm{~cm}^{3}\) and the mass is \(514.1 \mathrm{~g}\) b. A syrup is added to an empty container with a mass of \(115.25 \mathrm{~g}\). When \(0.100 \mathrm{pt}\) of syrup is added, the total mass of the container and syrup is \(182.48 \mathrm{~g}\). c. A block of aluminum metal has a volume of \(3.15 \mathrm{~L}\) and a mass of \(8.51 \mathrm{~kg}\).

A balance measures mass to \(0.001 \mathrm{~g}\). If you determine the mass of an object that weighs about \(31 \mathrm{~g}\), would you record the mass as \(31 \mathrm{~g}, 31.1 \mathrm{~g}, 31.08 \mathrm{~g}, 31.075 \mathrm{~g},\) or \(31.0750 ?\) Explain your choice by writing two to three complete sentences that describe your thinking. (2.3)

During a workout at the gym, you set the treadmill at a pace of \(55.0 \mathrm{~m} / \mathrm{min} .\) How many minutes will you walk if you cover a distance of \(7500 \mathrm{ft} ?\) (2.6)

How many significant figures are there in each of the following? a. \(28.003 \mathrm{~g}\) b. \(0.000057 \mathrm{~m}\) c. \(890000000 \mathrm{~km}\) d. \(4.50 \times 10^{6} \mathrm{~kg}\) e. \(0.7005 \mathrm{~L}\) f. \(19.0^{\circ} \mathrm{C}\)

Solve each of the following problems using one or more conversion factors: a. Wine is \(12 \%\) alcohol by volume. How many milliliters of alcohol are in a 0.750-L bottle of wine? b. Blueberry high-fiber muffins contain \(51 \%\) dietary fiber by mass. If a package with a net weight of 12 oz contains six muffins, how many grams of fiber are in each muffin? c. A jar of crunchy peanut butter contains \(1.43 \mathrm{~kg}\) of peanut butter. If you use \(8.0 \%\) of the peanut butter for a sandwich, how many ounces of peanut butter did you take out of the container? d. In a candy factory, the nutty chocolate bars contain \(22.0 \%\) pecans by mass. If \(5.0 \mathrm{~kg}\) of pecans were used for candy last Tuesday, how many pounds of nutty chocolate bars were made?

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