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Identify the acid (proton donor) and the base (proton acceptor) for the reactants in each of the following: a. \(\mathrm{CO}_{3}^{2-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftarrows \mathrm{HCO}_{3}^{-}(a q)+\mathrm{OH}^{-}(a q)\) b. \(\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{H}_{3} \mathrm{O}^{+}(a q)+\mathrm{HSO}_{4}^{-}(a q)\)

Short Answer

Expert verified
a) Acid: \(\mathrm{H}_{2} \mathrm{O}\), Base: \(\mathrm{CO}_{3}^{2-}\) \ b) Acid: \(\mathrm{H}_{2} \mathrm{SO}_{4}\), Base: \(\mathrm{H}_{2}\mathrm{O}\)

Step by step solution

01

- Identify the Acid and Base for Reaction (a)

Analyze the reactants in the equation: \ \(\mathrm{CO}_{3}^{2-}(aq)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftarrows \mathrm{HCO}_{3}^{-}(aq)+\mathrm{OH}^{-}(aq)\)\ - Carbonate ion (\(\mathrm{CO}_{3}^{2-}\)) accepts a proton from water, hence it acts as a base. \ - Water (\(\mathrm{H}_{2}\mathrm{O}\)) donates a proton, hence it acts as an acid.
02

- Identify the Acid and Base for Reaction (b)

Analyze the reactants in the equation: \ \(\mathrm{H}_{2} \mathrm{SO}_{4}(aq)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{3} \mathrm{O}^{+}(aq)+\mathrm{HSO}_{4}^{-}(aq)\)\ - Sulfuric acid (\(\mathrm{H}_{2} \mathrm{SO}_{4}\)) donates a proton, hence it acts as an acid. \ - Water (\(\mathrm{H}_{2} \mathrm{O}\)) accepts a proton, hence it acts as a base.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

proton donor
In an acid-base reaction, the proton donor is the substance that gives away a proton (H+) to another substance. This is usually the definition of an acid in the Brønsted-Lowry theory. For example, in reaction (b), sulfuric acid (H2SO4) is the proton donor because it donates a proton to water. Similarly, in reaction (a), water (H2O) donates a proton to the carbonate ion (CO32-) and acts as the proton donor.
proton acceptor
The proton acceptor in an acid-base reaction is the substance that receives the proton (H+) from the proton donor. This is typically referred to as the base. For example, in reaction (a), the carbonate ion (CO32-) acts as the base because it accepts a proton from water. In reaction (b), water (H2O) acts as the proton acceptor when it receives a proton from sulfuric acid (H2SO4).
carbonate ion
The carbonate ion (CO32-) is a polyatomic ion and a common base in acid-base reactions. It is often found in various chemical and biological processes. In reaction (a), the carbonate ion accepts a proton from water and forms bicarbonate (HCO3-). This demonstrates that the carbonate ion acts as a base by accepting a proton and increasing the concentration of hydroxide ions (OH-) in solution.
sulfuric acid
Sulfuric acid (H2SO4) is a strong acid commonly used in various industrial and chemical processes. In reaction (b), sulfuric acid donates a proton to water, producing hydronium (H3O+) and bisulfate (HSO4-). Sulfuric acid is known for its ability to donate protons readily, making it a strong acid. Because it participates in many chemical reactions, understanding sulfuric acid's role as a proton donor is crucial in chemistry.
water as acid
Water (H2O) can act as an acid in certain reactions by donating a proton. An example is reaction (a), where water donates a proton to the carbonate ion (CO32-), resulting in the formation of bicarbonate (HCO3-) and hydroxide ions (OH-). In this context, water behaves as an acid, highlighting its amphoteric nature, which means it can act both as an acid and a base depending on the reaction.
water as base
Water is also capable of acting as a base by accepting a proton. In reaction (b), water accepts a proton from sulfuric acid (H2SO4), forming hydronium (H3O+). This shows water's role as a proton acceptor in this context, behaving as a base. Water's ability to act both as a proton donor and acceptor makes it crucial in many chemical reactions, especially those involving acids and bases.

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