/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Write the correct formula for th... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Problem 36

Write the correct formula for the following compounds: a. aluminum chlorate b. ammonium oxide c. magnesium bicarbonate d. sodium nitrite e. copper(I) sulfate

Short Answer

Expert verified
a. Al(ClO鈧�)鈧�, b. (NH鈧�)鈧侽, c. Mg(HCO鈧�)鈧�, d. NaNO鈧�, e. Cu鈧係O鈧�

Step by step solution

01

Understand the cations and anions

Identify the cation (positive ion) and anion (negative ion) for each compound. For example, aluminum chlorate: the cation is aluminum (Al鲁鈦�) and the anion is chlorate (ClO鈧冣伝).
02

Use the Criss-Cross Method

For each compound, use the criss-cross method to balance the charges. For instance, with aluminum chlorate, cross the charges to get Al(ClO鈧�)鈧�.
03

Compose the formula for each compound

a. Aluminum chlorate: Combine Al鲁鈦� and ClO鈧冣伝 using criss-cross, resulting in Al(ClO鈧�)鈧�. b. Ammonium oxide: Combine NH鈧勨伜 and O虏鈦� using criss-cross, resulting in (NH鈧�)鈧侽. c. Magnesium bicarbonate: Combine Mg虏鈦� and HCO鈧冣伝 using criss-cross, resulting in Mg(HCO鈧�)鈧�. d. Sodium nitrite: Combine Na鈦� and NO鈧傗伝 without the need for criss-cross, resulting in NaNO鈧�. e. Copper(I) sulfate: Combine Cu鈦� and SO鈧劼测伝 using criss-cross, resulting in Cu鈧係O鈧�.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

cation and anion identification
Understanding the basics of ionic compounds starts with identifying cations and anions.

Cations are positively charged ions, while anions are negatively charged ions.

In a chemical formula, the cation is always listed first, followed by the anion. For example, in the compound aluminum chlorate (Al(ClO鈧�)鈧�), aluminum is the cation and chlorate is the anion.

Here are some steps to make this identification easier:
  • Identify the metal or ammonium group, which is usually the cation.
  • Identify the non-metal or polyatomic ion, which tends to be the anion.
With these identifications, you lay a strong foundation for writing correct formulas.
criss-cross method
The criss-cross method is a handy tool to balance the charges of ions in an ionic compound.

It involves taking the numerical value of the charge on the cation and using it as the subscript for the anion, and vice versa.

Let's take aluminum chlorate as an example. Aluminum (Al鲁鈦�) and chlorate (ClO鈧冣伝) have charges of +3 and -1, respectively. Using the criss-cross method:
  • Cross the charges to form subscripts: Al becomes Al(ClO鈧�)鈧�.
  • Simplify if needed, but in this case, the formula is already simplified: Al(ClO鈧�)鈧�.
This method ensures the charges balance out to create a neutral compound.
compound balancing
Balancing compounds is crucial to maintaining charge neutrality. This means the total positive charge should equal the total negative charge.

If using the criss-cross method, make sure to check the following:
  • The sum of the charges from the cation(s) and anion(s) should be zero.
  • If needed, adjust the subscripts to balance the charges properly. For example, ammonium oxide combines NH鈧勨伜 with O虏鈦�. Using the criss-cross method and balancing the charges results in (NH鈧�)鈧侽.
Always verify the final formula to ensure accuracy by counting the charges of both ions.
ionic compounds
Ionic compounds are formed by the electrostatic attraction between cations and anions.

These compounds are usually formed when a metal reacts with a non-metal.

Here鈥檚 what you need to know:
  • Ionic compounds are generally solid at room temperature.
  • They have high melting and boiling points due to strong ionic bonds.
  • They often dissolve in water and conduct electricity in aqueous solution.
Examples from the exercise include:
  • Magnesium bicarbonate (Mg(HCO鈧�)鈧�) which is formed from Mg虏鈦� and HCO鈧冣伝.
  • Sodium nitrite (NaNO鈧�) which is formed from Na鈦� and NO鈧傗伝.
Understanding their properties helps in better understanding their behavior in different conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One of the ions of gold is gold(III). a. What is the symbol for this ion? b. How many protons and electrons are in the ion? c. What is the formula of gold(III) sulfate? d. What is the formula of gold(III) nitrate?

Which of the following pairs of elements are likely to form an ionic compound? a. helium and oxygen b. magnesium and chlorine c. chlorine and bromine d. potassium and sulfur e. sodium and potassium f. nitrogen and iodine

Identify the strongest attractive force between particles of each of the following: a. \(\mathrm{O}_{2}\) b. HI c. \(\mathrm{NaF}\) d. \(\mathrm{CH}_{3}-\mathrm{OH}\) e. Ne

Write the formula for the polyatomic ion in each of the following and name each compound: a. \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) b. \(\mathrm{NH}_{4} \mathrm{Cl}\) c. \(\mathrm{K}_{3} \mathrm{PO}_{4}\) d. \(\mathrm{Cr}\left(\mathrm{NO}_{2}\right)_{2}\) e. \(\mathrm{FeSO}_{3}\)

Identify the group number in the periodic table of \(\mathrm{X}\), a representative element, in each of the following ionic compounds: a. \(\mathrm{XCl}_{3}\) b. \(\mathrm{Al}_{2} \mathrm{X}_{3}\) c. \(\mathrm{XCO}_{3}\)
See all solutions

Recommended explanations on Chemistry Textbooks

Nuclear Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Inorganic Chemistry

Read Explanation

Kinetics

Read Explanation

Organic Chemistry

Read Explanation

Chemistry Branches

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.