Chapter 9: Problem 99
What quantity of energy does it take to convert 0.500 kg ice at \(-20 .^{\circ} \mathrm{C}\) to steam at \(250 .^{\circ} \mathrm{C} ?\) Specific heat capacities: ice, \(2.03 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C} ;\) liquid, \(4.2 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C} ;\) steam, \(2.0 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C} ; \Delta H_{\mathrm{vap}}=\) \(40.7 \mathrm{kJ} / \mathrm{mol} ; \Delta H_{\mathrm{fus}}=6.02 \mathrm{kJ} / \mathrm{mol}.\)
Short Answer
Step by step solution
Convert mass to grams and calculate the number of moles of water in the sample
Calculate the energy required to heat the ice from -20°C to 0°C
Calculate the energy required to convert the ice at 0°C to water
Calculate the energy required to heat the water from 0°C to 100°C
Calculate the energy required to convert the water at 100°C to steam
Calculate the energy required to heat the steam from 100°C to 250°C
Calculate the total energy required
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Specific Heat Capacity
For the problem at hand, the specific heat capacities are:
- Ice: 2.03 J/g°C
- Liquid water: 4.2 J/g°C
- Steam: 2.0 J/g°C
Enthalpy of Fusion
- \(\Delta H_{fus} = 6.02 \mathrm{kJ/mol}\)
Enthalpy of Vaporization
- \(\Delta H_{vap} = 40.7 \mathrm{kJ/mol}\)
Phase Transitions
Key transitions are:
- Melting (solid to liquid)
- Freezing (liquid to solid)
- Vaporization (liquid to gas)
- Condensation (gas to liquid)
- Ice melting to water involves the enthalpy of fusion.
- Water boiling into steam involves the enthalpy of vaporization.
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For example, in the discussed problem, several phase transitions are considered: