Chapter 9: Problem 44
Explain why water forms into beads on a waxed car finish.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 9: Problem 44
Explain why water forms into beads on a waxed car finish.
All the tools & learning materials you need for study success - in one app.
Get started for free
What is the vapor pressure of water at \(100^{\circ} \mathrm{C} ?\) How do you know?
Spinel is a mineral that contains \(37.9 \%\) aluminum, \(17.1 \%\) magnesium, and \(45.0 \%\) oxygen, by mass, and has a density of \(3.57 \mathrm{g} / \mathrm{cm}^{3} .\) The edge of the cubic unit cell measures \(809 \mathrm{pm} .\) How many of each type of ion are present in the unit cell?
A \(0.250-g\) chunk of sodium metal is cautiously dropped into a mixture of \(50.0 \mathrm{g}\) water and \(50.0 \mathrm{g}\) ice, both at \(0^{\circ} \mathrm{C}\). The reaction is $$2 \mathrm{Na}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{NaOH}(a q)+\mathrm{H}_{2}(g) \quad \Delta H=-368 \mathrm{kJ}$$ Assuming no heat loss to the surroundings, will the ice melt? Assuming the final mixture has a specific heat capacity of \(4.18 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C},\) calculate the final temperature. The enthalpy of fusion for ice is \(6.02 \mathrm{kJ} / \mathrm{mol}\).
What type of solid will each of the following substances form? a. \(\mathrm{diamond}\) b. \(\mathrm{PH}_{3}\) c. \(\mathrm{H}_{2}\) d. \(\mathrm{Mg}\) e. \(\mathrm{KCl}\) f. quartz g. \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) h. \(\mathrm{SF}_{2}\) i. \(\mathrm{Ar}\) j. \(\mathrm{Cu}\) k. \(\mathrm{C}_{6} \mathbf{H}_{12} \mathbf{O}_{6}\)
Iron has a density of \(7.86 \mathrm{g} / \mathrm{cm}^{3}\) and crystallizes in a bodycentered cubic lattice. Show that only \(68 \%\) of a body-centered lattice is actually occupied by atoms, and determine the atomic radius of iron.
What do you think about this solution?
We value your feedback to improve our textbook solutions.