Chapter 8: Problem 133
A \(2.00-\mathrm{L}\) sample of \(\mathrm{O}_{2}(g)\) was collected over water at a total pressure of \(785\) torr and \(25^{\circ} \mathrm{C}\). When the \(\mathrm{O}_{2}(g)\) was dried (water vapor removed), the gas had a volume of \(1.94 \mathrm{L}\) at \(25^{\circ} \mathrm{C}\) and \(785\) torr. Calculate the vapor pressure of water at \(25^{\circ} \mathrm{C}\)
Short Answer
Step by step solution
Write down the given values.
Determine the moles of dry Oâ‚‚ gas using the Ideal Gas Law.
Calculate the number of moles of dry Oâ‚‚ gas.
Calculate the partial pressure of Oâ‚‚ in the total pressure.
Calculate the partial pressure of Oâ‚‚ gas.
Calculate the vapor pressure of water using Dalton's Law of Partial Pressures.
Calculate the vapor pressure of water at 25°C.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dalton's Law of Partial Pressures
- Total Pressure (\(P_{\text{total}}\)) = Pressure of Oxygen (\(P_{\text{O}_2}\)) + Pressure of Water Vapor (\(P_{\text{H}_2\text{O}}\))
Vapor Pressure
When a gas is collected over water, the vapor pressure needs to be accounted for to isolate the pressure exerted by the gas you're interested in. Therefore, understanding the concept of vapor pressure is essential in exact calculations when gases are involved.
Moles Calculation
- \( PV = nRT \)
- \(P\) is the pressure
- \(V\) is the volume
- \(n\) is the number of moles
- \(R\) is the gas constant
- \(T\) is the temperature in Kelvin
Gas Mixtures
In our exercise, the gas mixture consisted of oxygen and water vapor. When the oxygen gas was initially gathered, the water vapor contributed to the total pressure inside the container. Adjusting calculations for this enables a more precise understanding of the behavior of the target gas (oxygen in this instance). Studying gas mixtures helps in various fields, including environmental science, chemistry, and engineering, where gas interactions often take place.