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Calculate the concentration of all ions present when \(0.160 \mathrm{g}\) of \(\mathrm{MgCl}_{2}\) is dissolved in \(100.0 \mathrm{mL}\) of solution.

Short Answer

Expert verified
When 0.160 g of MgCl鈧 is dissolved in 100.0 mL of solution, the concentration of Mg虏鈦 ions is approximately \(0.0168 \mathrm{mol/L}\) and the concentration of Cl鈦 ions is approximately \(0.0336 \mathrm{mol/L}\).

Step by step solution

01

Determine the moles of MgCl鈧

To determine the moles of MgCl鈧, we first need to find the molar mass of MgCl鈧. The molar masses of Mg, Cl are approximately 24.3 g/mol and 35.5 g/mol, respectively. Therefore, the molar mass of MgCl鈧 is: Molar mass of MgCl鈧 = 24.3 + 2(35.5) = 95.3 g/mol Now we can calculate the moles of MgCl鈧: Moles of MgCl鈧 = mass / molar mass = 0.160 g / 95.3 g/mol 鈮 0.00168 mol
02

Determine the moles of each ion

When MgCl鈧 dissolves in water, it dissociates into its constituent ions according to the following equation: MgCl鈧 (s) 鈫 Mg虏鈦 (aq) + 2 Cl鈦 (aq) From the stoichiometry of the reaction, we can see that 1 mole of MgCl鈧 produces 1 mole of Mg虏鈦 ions and 2 moles of Cl鈦 ions. Hence, we can calculate the moles of each ion: Moles of Mg虏鈦 = 1 * (moles of MgCl鈧) = 0.00168 mol Moles of Cl鈦 = 2 * (moles of MgCl鈧) = 2 * 0.00168 mol 鈮 0.00336 mol
03

Calculate concentration of each ion

Now that we know the moles of each ion, we can determine their concentration by dividing the moles by the volume of the solution (in liters): Volume of solution = 100.0 mL = 0.1 L Concentration of Mg虏鈦 = moles of Mg虏鈦 / volume of solution = 0.00168 mol / 0.1 L 鈮 0.0168 mol/L Concentration of Cl鈦 = moles of Cl鈦 / volume of solution = 0.00336 mol / 0.1 L 鈮 0.0336 mol/L So, when 0.160 g of MgCl鈧 is dissolved in 100.0 mL of solution, the concentration of Mg虏鈦 ions is approximately 0.0168 mol/L and the concentration of Cl鈦 ions is approximately 0.0336 mol/L.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
Molar mass, which is expressed in grams per mole (g/mol), is a fundamental property of a substance that tells us the mass of one mole of that substance. The molar mass of a molecule is calculated by summing the molar masses of all the atoms present in the molecule. For example, to calculate the molar mass of magnesium chloride (\r \( \text{MgCl}_{2} \)), we consider the molar masses of magnesium (approximately 24.3 g/mol) and chlorine (approximately 35.5 g/mol).

\rSince magnesium chloride consists of one magnesium atom and two chlorine atoms, its molar mass is computed as:\[ \text{Molar mass of MgCl}_{2} = \text{Molar mass of Mg} + 2 \times \text{Molar mass of Cl} = 24.3 \text{ g/mol} + 2(35.5 \text{ g/mol}) = 95.3 \text{ g/mol} \].

\rUnderstanding molar mass is crucial because it enables us to convert between the mass of a substance and the amount in moles, an essential step in many stoichiometric calculations.
Stoichiometry
Stoichiometry is a section of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. It is based on the conservation of mass and the concept of the mole. Using stoichiometry, we can predict the proportions of substances consumed and produced in a given reaction.

\rConsider the dissociation of magnesium chloride in water: \( \text{MgCl}_{2} (s) \rightarrow \text{Mg}^{2+} (aq) + 2 \text{Cl}^{-} (aq) \). The coefficients in the balanced chemical equation show the ratio of moles of reactants to products. For each mole of \( \text{MgCl}_{2} \), one mole of \( \text{Mg}^{2+} \) and two moles of \( \text{Cl}^{-} \) are produced. Thus, if we start with 0.00168 moles of \( \text{MgCl}_{2} \), stoichiometry tells us we will have 0.00168 moles of \( \text{Mg}^{2+} \) and twice that amount, 0.00336 moles, of \( \text{Cl}^{-} \).
Solution Concentration
The concentration of a solution is a measure of the amount of solute present in a given volume of solvent. There are various ways to express concentration, such as molarity, which is the number of moles of solute per liter of solution (mol/L).

\rTo find the concentration of ions in a solution, we divide the moles of the ion by the volume of the solution in liters. For instance, if we have 0.00168 moles of \( \text{Mg}^{2+} \) ions in a 100.0 mL solution, we first convert the volume to liters (0.1 L) and then use this to calculate the concentration:\[ \text{Concentration of } \text{Mg}^{2+} = \frac{\text{moles of } \text{Mg}^{2+}}{\text{volume of solution}} = \frac{0.00168 \text{ mol}}{0.1 \text{ L}} = 0.0168 \text{ mol/L} \].

\rTo ensure your calculations are accurate, always pay attention to units and convert measurements to the appropriate units before performing concentration calculations.
Dissociation of Ionic Compounds
Ionic compounds such as magnesium chloride \( \text{MgCl}_{2} \) tend to dissociate into their respective ions when dissolved in water. Dissociation is a reversible process where the solid ionic compound separates into its ions as it interacts with the solvent. The extent to which an ionic compound dissociates depends on the compound and the conditions, such as temperature and concentration.

\rIn our case, when \( \text{MgCl}_{2} \) is dissolved in water, it dissociates completely into \( \text{Mg}^{2+} \) and \( \text{Cl}^{-} \) ions following this equation: \( \text{MgCl}_{2} (s) \rightarrow \text{Mg}^{2+} (aq) + 2 \text{Cl}^{-} (aq) \). For every mole of \( \text{MgCl}_{2} \) that dissolves, we get one mole of magnesium ions and two moles of chloride ions. Understanding this process is important not only for computing ion concentrations but also for predicting the behavior of ionic substances in solution.

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Most popular questions from this chapter

A sample may contain any or all of the following ions: \(\mathrm{Hg}_{2}^{2+}\) \(\mathrm{Ba}^{2+},\) and \(\mathrm{Mn}^{2+}\) a. No precipitate formed when an aqueous solution of \(\mathrm{NaCl}\) was added to the sample solution. b. No precipitate formed when an aqueous solution of \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) was added to the sample solution. c. A precipitate formed when the sample solution was made basic with NaOH. Which ion or ions are present in the sample solution?

Suppose \(50.0 \mathrm{mL}\) of \(0.250 \mathrm{M} \mathrm{CoCl}_{2}\) solution is added to 25.0 mL of 0.350 \(M \mathrm{NiCl}_{2}\) solution. Calculate the concentration, in moles per liter, of each of the ions present after mixing. Assume that the volumes are additive.

Calculate the sodium ion concentration when \(70.0 \mathrm{mL}\) of 3.0 \(M\) sodium carbonate is added to \(30.0 \mathrm{mL}\) of \(1.0 \mathrm{M}\) sodium bicarbonate.

What volume of \(0.0521 M B a(O H)_{2}\) is required to neutralize exactly \(14.20 \mathrm{mL}\) of \(0.141 M \mathrm{H}_{3} \mathrm{PO}_{4} ?\) Phosphoric acid contains three acidic hydrogens.

Tris(pentafluorophenyl)borane, commonly known by its acronym BARF, is frequently used to initiate polymerization of ethylene or propylene in the presence of a catalytic transition metal compound. It is composed solely of \(\mathrm{C}, \mathrm{F},\) and \(\mathrm{B} ;\) it is \(42.23 \%\) C and \(55.66 \%\) F by mass. a. What is the empirical formula of BARF? b. A \(2.251-\mathrm{g}\) sample of BARF dissolved in \(347.0 \mathrm{mL}\) of solution produces a 0.01267-M solution. What is the molecular formula of BARF?

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