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First, calculate the mass composition of potassium in each compound: For potassium chloride (KCl): - Potassium (K) has a molar mass of 39.10 g/mol - Chlorine (Cl) has a molar mass of 35.45 g/mol - The molar mass of KCl = 39.10 g/mol (K) + 35.45 g/mol (Cl) = 74.55 g/mol The mass composition of potassium in KCl is \(\frac{39.10}{74.55}\) or 0.5244 (52.44%) For potassium nitrate (KNO3): - Potassium (K) has a molar mass of 39.10 g/mol - Nitrogen (N) has a molar mass of 14.01 g/mol - Oxygen (O) has a molar mass of 16.00 g/mol (and there are 3 O atoms in KNO3) - The molar mass of KNO3 = 39.10 g/mol (K) + 14.01 g/mol (N) + 3(16.00 g/mol) (O) = 101.11 g/mol The mass composition of potassium in KNO3 is \(\frac{39.10}{101.11}\) or 0.3866 (38.66%)

Let x be the mass fraction of KCl in the mixture. Then the mass fraction of KNO3 in the mixture is (1-x). We can set up the following equation using the given mass composition of potassium in the mixture (43.2%) and the mass composition of potassium in both compounds: \(0.432 = (0.5244)(x) + (0.3866)(1-x)\) Now we can solve for x: \(0.432 = 0.5244x + 0.3866 - 0.3866x\) \(0.0454x = 0.0454\) \(x = 1\) So, the mass fraction of KCl in the mixture is 1 (100%).

The mass fraction of KCl in the mixture is 1, which means the entire mixture is composed of KCl. So, the percent of KCl by mass in the original mixture is: Percent KCl by mass = (mass fraction of KCl) × 100 = 1 × 100 = 100% Therefore, the original mixture is 100% potassium chloride (KCl) by mass.