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Describe the bonding in the \(\mathrm{CO}_{3}^{2-}\) ion using the localized electron model. How would the molecular orbital model describe the \(\pi\) bonding in this species?

Short Answer

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In the Localized Electron Model, the bonding in CO鈧兟测伝 ion is described using resonance structures, involving one double bond (蟺 bond) and two single bonds (蟽 bonds) shared among three oxygen atoms, which results in a resonance hybrid. The 蟺 bonding originates from the overlap of the remaining p orbitals of the carbon and oxygen atoms, with electrons spread evenly across the oxygens. On the other hand, the Molecular Orbital Model describes the bonding through 蟺 bonding molecular orbitals formed by the combination of 2p orbitals from carbon and oxygen atoms, delocalizing the electrons over the entire ion, resulting in a bond order of 2/3 for the pi bonding, demonstrating partial double bond character.

Step by step solution

01

Describe the Localized Electron Model for CO鈧兟测伝

In the Localized Electron Model, we consider bonds as localized between two adjacent atoms as a result of the sharing of electrons. There are three resonance structures for the CO鈧兟测伝 ion, each structure having one double bond (鈭 bond) and two single bonds (蟽 bonds). It is important to understand that these resonance structures do not imply that the molecule switches between the different forms but rather that the resulting structure is a resonance hybrid of the three possibilities where the double bond is evenly distributed over all three oxygen atoms.
02

Describe the 蟽 bonding using the LE Model for CO鈧兟测伝

The electron configuration of carbon is \([He]2s^2 2p^2\). In order to form three sigma bonds with the oxygen atoms, carbon must hybridize its valence orbitals into three equivalent orbitals, involving 2s and two 2p orbitals. This is called sp虏 hybridization. Each of the three sp虏 orbitals on the carbon atom will form a sigma bond with one of the p orbitals on the oxygen atom. In terms of the LE Model, all six electrons are located within these sigma bonds.
03

Describe the 蟺 bonding using the LE Model for CO鈧兟测伝

In the LE Model, we use the concept of resonance structures to describe the distribution of the pi bonding electrons over the CO鈧兟测伝 ion. The 蟺 bonding originates from the overlap of the remaining p orbitals of the carbon atom and one of the oxygen atoms. There are three possible distributions for the location of the double bond among the three oxygens. These three resonance structures equally contribute to the actual molecule, spreading the 蟺 bonding electrons evenly across the oxygen atoms.
04

Describe the 蟺 bonding using the Molecular Orbital Model for CO鈧兟测伝

In the Molecular Orbital Model, we consider that electrons are delocalized over the entire molecule in molecular orbitals. In the case of the CO鈧兟测伝 ion, the molecular orbitals are formed by the combination of the 2p orbitals of the carbon atom and the 2p orbitals from the oxygen atoms. Since the 2p orbitals are perpendicular to the plane formed by the sp虏 hybrid orbitals, they create new molecular orbitals that are delocalized over all three oxygen atoms. There are three new molecular orbitals formed: one bonding (鈭 bonding), one non-bonding, and one antibonding (鈭* antibonding) molecular orbital. The 鈭 bonding molecular orbitals have lower energy and can hold two electrons each. For CO鈧兟测伝, there are two electrons delocalized over the entire ion in the 鈭 bonding molecular orbitals. That means the bond order of the pi bonding equals to 2/3, showing the partial double bond character in the CO鈧兟测伝 ion. In conclusion, the Localized Electron Model describes the bonding in CO鈧兟测伝 ion using resonance structures, where the double bond appears in a single location among the three oxygen atoms. In contrast, the Molecular Orbital Model gives a more accurate depiction of the delocalized nature of 蟺 bonding, where the electrons are shared evenly over all three oxygen atoms.

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Most popular questions from this chapter

Which of the following statements is/are true? Correct the false statements. a. The molecules \(\operatorname{SeS}_{3}, \operatorname{SeS}_{2}, \operatorname{PCl}_{5}, \operatorname{TeCl}_{4},\) ICl \(_{3}\), and \(\mathrm{XeCl}_{2}\) all exhibit at least one bond angle which is approximately \(120^{\circ} .\) b. The bond angle in \(\mathrm{SO}_{2}\) should be similar to the bond angle in \(\mathrm{CS}_{2}\) or \(\mathrm{SCl}_{2}\) c. Of the compounds \(\mathrm{CF}_{4}, \mathrm{KrF}_{4},\) and \(\mathrm{SeF}_{4},\) only \(\mathrm{SeF}_{4}\) exhibits an overall dipole moment (is polar). d. Central atoms in a molecule adopt a geometry of the bonded atoms and lone pairs about the central atom in order to maximize electron repulsions.

Use the localized electron model to describe the bonding in \(\mathrm{H}_{2} \mathrm{O}\).

Consider the following electron configuration: $$\left(\sigma_{3 s}\right)^{2}\left(\sigma_{3 s}^{* *}\right)^{2}\left(\sigma_{3 p}\right)^{2}\left(\pi_{3 p}\right)^{4}\left(\pi_{3 p}^{*}\right)^{4}$$ Give four species that, in theory, would have this electron configuration.

Using an MO energy-level diagram, would you expect \(\mathrm{F}_{2}\) to have a lower or higher first ionization energy than atomic fluorine? Why?

Predict the molecular structure for each of the following. (See Exercises 25 and \(26 .\) ) a. \(\mathrm{BrFI}_{2}\) b. \(\mathrm{XeO}_{2} \mathrm{F}_{2}\) c. \(\operatorname{TeF}_{2} \mathrm{Cl}_{3}^{-}\) For each formula there are at least two different structures that can be drawn using the same central atom. Draw all possible structures for each formula.

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